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$B=\left(\dfrac1{2^2}-1\right)\left(\dfrac1{3^2}-1\right)\cdots\left(\dfrac1{99^2}-1\right)$
$=\left(-\dfrac{2^2-1}{2^2}\right)\left(-\dfrac{3^2-1}{3^2}\right)\cdots\left(-\dfrac{99^2-1}{99^2}\right)$
$=(-1)^{98}\prod_{k=2}^{99}\dfrac{(k-1)(k+1)}{k^2}$
$=\left(\prod_{k=2}^{99}\dfrac{k-1}{k}\right)\left(\prod_{k=2}^{99}\dfrac{k+1}{k}\right)$
$=\left(\dfrac12\cdot\dfrac23\cdot\dfrac34\cdots\dfrac{98}{99}\right)\left(\dfrac32\cdot\dfrac43\cdot\dfrac54\cdots\dfrac{100}{99}\right)$
$=\dfrac1{99}\cdot\dfrac{100}{2}$
$=\dfrac{50}{99}.$
$\textbf{a)}$
$\left(-\dfrac34+\dfrac27\right):\dfrac27+\left(-\dfrac14+\dfrac57\right):\dfrac23$
$=\left(-\dfrac{13}{28}\right)\cdot\dfrac72+\dfrac{13}{28}\cdot\dfrac32$
$=-\dfrac{13}{8}+\dfrac{39}{56}$
$=-\dfrac{13}{14}.$
$\textbf{b)}$
$\left(-\dfrac13\right)^2\cdot\dfrac4{11}+\dfrac7{11}\cdot\left(-\dfrac13\right)^2$
$=\dfrac19\left(\dfrac4{11}+\dfrac7{11}\right)$
$=\dfrac19.$
\(a,9.3^3.\frac{1}{81}.3^2=3^2.3^3.3^{\left(-4\right)}.3^2=3^{2+3-4+2}=3^3.\)
\(b,4.2^5:\left(2^3.\frac{1}{16}\right)=2^2.2^5:\left(2^3.2^{-4}\right)=2^{2+5}:2^{3-4}=2^7:2^{-1}=2^{7-\left(-1\right)}=2^8.\)
\(c,3^2.2^5.\left(\frac{2}{3}\right)^2=3^2.2^5.\frac{2^2}{3^2}=\left(\frac{3^2}{3^2}\right).\left(2^5.2^2\right)=1.2^{5+2}=2^7\)
\(d,\left(\frac{1}{3}\right)^2.\frac{1}{3}.9^2=\left(\frac{1}{3}\right)^2.\frac{1}{3}.\left(3^2\right)^2=\left(\frac{1}{3}\right)^{2+1}.3^4=\left(\frac{1}{3}\right)^3.\left(\frac{1}{3}\right)^{-4}=\left(\frac{1}{3}\right)^{3-4}=\left(\frac{1}{3}\right)^{-1}=3^1\)
$\textbf{a)}$
$A=\dfrac{\left(\dfrac23\right)^3\cdot\left(-\dfrac34\right)^2\cdot(-1)^{2019}}{36\cdot\dfrac15\cdot\left(\dfrac25\right)^2\cdot\left(-\dfrac5{12}\right)^3}$
$=\dfrac{\dfrac8{27}\cdot\dfrac9{16}\cdot(-1)}{36\cdot\dfrac15\cdot\dfrac4{25}\cdot\left(-\dfrac{125}{1728}\right)}$
$=\dfrac{-\dfrac16}{-\dfrac5{12}}$
$=\dfrac16\cdot\dfrac{12}5$
$=\dfrac25.$
$\textbf{b)}$
$B=\dfrac1{19}+\dfrac9{19\cdot29}+\dfrac9{29\cdot39}+\cdots+\dfrac9{2009\cdot2019}$
$=\dfrac1{19}+\left(\dfrac1{19}-\dfrac1{29}\right)+\left(\dfrac1{29}-\dfrac1{39}\right)+\cdots+\left(\dfrac1{2009}-\dfrac1{2019}\right)$
$=\dfrac1{19}+\dfrac1{19}-\dfrac1{2019}$
$=\dfrac2{19}-\dfrac1{2019}$
$=\dfrac{2\cdot2019-19}{19\cdot2019}$
$=\dfrac{4019}{38361}.$
\(B=\left(-13\cdot\frac{2}{5}+\frac{-2}{9}\div2\frac{1}{2}+\frac{2}{5}\cdot\frac{11}{9}\right)\cdot2\frac{1}{2}\)
\(B=\left(13\cdot\frac{2}{5}+\frac{-2}{9}\cdot\frac{2}{5}+\frac{2}{5}\cdot\frac{11}{9}\right)\cdot\frac{5}{2}\)
\(B=\left[\frac{2}{5}\cdot\left(-13+\frac{-2}{9}+\frac{11}{9}\right)\right]\cdot\frac{5}{2}\)
\(B=\left[\frac{2}{5}\cdot\left(-12\right)\right]\cdot\frac{5}{2}\)
\(B=\frac{-24}{5}\cdot\frac{5}{2}=-12\)