\(\frac{2016x125+1000}{126x2015-880}\)

\(=\frac{2015x125+125+1000}{125x2015+2015-880}\)

\(=\frac{2015x125+1125}{125x2015+1135}=\frac{2015x125+1135-10}{125x2015+1135}\)

\(=1-\frac{10}{125x2015+1135}\)

bn cs chép nhầm đề ko z?

ai giải hộ mik vs :))

\(\frac{2015}{2016}×\frac{20162016}{19451945}×\frac{194519451945}{201520152015}\)

\(=\frac{2015}{2016}×\frac{2016}{1945}×\frac{1945}{2015}\)

\(=\frac{2015×2016×1945}{2016×1945×2015}\)

\(=\frac{2015×2016×1945}{2015×2016×1945}\)

\(=1\)

\(\frac{2014.2015+2016}{2015.2016-2014}=\frac{2014.2015+2016}{2015.2014+4030-2014}=\frac{2014.2015+2016}{2014.2015+2016}=1\)

Đặt 2015.2016+2016=n

suy ra A=(n+1)/n   và B=(n+2)/(n+1)

Ta có A - B=(n+1)/n -(n+2)/(n+1)=((n+1)²-n(n+2))/n(n+1)=(n²+2n+1-n²-2n)/n(n+1)=1/n(n+1)

Vì A-B lớn hơn 0 nên A>B

thanks

2015/2016<2016/2017

\(\frac{2015}{2016}\)và \(\frac{2016}{2017}\)

Ta có : \(\frac{2015}{2016}-1=\frac{1}{2016};\frac{2016}{2017}-1=\frac{1}{2017}\)

Vì \(\frac{1}{2016}>\frac{1}{2017}\)nên \(\frac{2015}{2016}< \frac{2016}{2017}\).

~ Chúc bạn hok tốt ~

\(\frac{2015+2014\cdot2016}{2015\cdot2016-1}\)

\(=\frac{2015+\left(2015-1\right)2016}{2015\cdot2016-1}\)

\(=\frac{2015-2016+2015\cdot2016}{2015\cdot2016-1}\)

\(=\frac{2015\cdot2016-1}{2015\cdot2016-1}\)

\(=1\)

100

100

\(A=\frac{1+2+3+...+2015}{2016}\)

\(A=\frac{\left(2015+1\right)\times2015:2}{2016}\)

\(A=\frac{\text{2031120}}{2016}\)

\(A=\text{1007,5}\)