Bằng 96 nha

tại sao lại ra như thế

789 x 62 - 789 x 8 + 37 x 789 + 789

= 789 x ( 62 - 8 + 37 + 1 )

= 789 x 92

= 72588

~~Cô gái xử nữ~~

=2021.(1999-999)

=2021.1000

=2021000

2021x1999-2021x999

=2021x(1999-999)

=2021x1000

=2021000

Ta có :

\(A=\frac{1}{3}-\frac{3}{4}-\left(-\frac{3}{5}\right)+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)

\(\Rightarrow A=\frac{5}{15}-\frac{54}{72}+\frac{9}{15}+\frac{1}{72}-\frac{16}{72}-\frac{1}{72}+\frac{1}{15}\)

\(\Rightarrow A=\left(\frac{5}{15}+\frac{9}{15}+\frac{1}{15}\right)+\left(-\frac{54}{72}+\frac{1}{72}-\frac{16}{72}-\frac{2}{72}\right)\)

\(\Rightarrow A=1-\frac{71}{72}=\frac{1}{72}\)

\(\frac{72^3}{54^6}\)=\(\frac{\left(9.8\right)^3}{\left(9.6\right)^3}\)=\(\frac{9^3.8^3}{9^3.6^3}\)=\(\frac{8^3}{6^3}\)= \(\frac{2^3.2^3.2^3}{2^3.3^3}\)= \(\frac{2^3.2^3}{3^3}\)= \(\frac{8.8}{27}\)=\(\frac{64}{27}\)

S = ( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + ... + ( 2001 + 2001 - 2003 - 2004 ) + ( 2005 + 2006 )

S = ( - 4 ) + ( - 4 ) + .... + ( - 4 ) + ( 2005 + 2006 )

Dãy S có : 2004 - 1 : 1 + 1 = 2004 số hạng

Dãy số S : 2004 : 4  = 501 số ( - 4 )

Dãy đó S = -4 x 501 = -2004 

S = -2004 + ( 2005 + 2006 ) 

S = -2004 + 4011

S = 2007

Ta có :

\(\frac{3}{8}.\frac{58}{3}-\frac{3}{8}.\frac{100}{3}\)

\(=\frac{3}{8}.\left(\frac{58}{3}-\frac{100}{3}\right)\)

\(=\frac{3}{8}.\frac{-42}{3}\)

\(=\frac{-42}{8}=\frac{-21}{4}\)

8/15 + 7/4 + 7/15 + 5/4

= 8/15 + 7/15 + 7/4 +5/4

= ( 8/15 + 7/15) + ( 7/4 + 5/4)

= 15/15 + 12/4

= 1 + 3

=4

=8/15+7/15+7/4+5/4

=1+3

=4