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Ta có: \(1996\cdot1995-996-100-1996\cdot1994\)
\(=1996\left(1995-1994\right)-1996\)
\(=1996-1996=0\)
\(\frac{1996\cdot1995-996}{1000+1996\cdot1994}\)
\(=\frac{1996\cdot\left(1994+1\right)-996}{1000+1996\cdot1994}\)
\(=\frac{1996\cdot1994+1996-996}{1000+1996\cdot1994}\)
\(=\frac{1996\cdot1994+1000}{1000+1996\cdot1994}=1\)
Dạng toán: Tính nhanh ( vận dụng tính chất kết hợp phân phối giữa phép nhân và phép cộng)
Chúc em học tốt!
\(\frac{1996.1995-996}{1000+1996.1994}=\frac{1996.\left(1994+1\right)-996}{1000+1996.1994}=\frac{1996.1994+1996-996}{1000+1996.1994}\)
\(=\frac{1996.1994+1000}{1000+1996.1994}=1\)
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\(\frac{1996\times1995-996}{1000+1996\times1994}\)
\(=\frac{1996\times\left(1994+1\right)-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1996\times1-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1996-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1000}{1996\times1994+1000}=1\)
\(\frac{1,65\times25+117\times1,65+1,65\times108}{150\times0,25+1,4\times150}\)
\(=\frac{\left(25+117+108\right)\times1,65}{150\times\left(0,25+1,4\right)}\)
\(=\frac{250\times1,65}{150\times1,65}\)
\(=\frac{\left(150+100\right)\times1,65}{150\times1,65}\)
\(=\frac{150\times1,65+100\times1,65}{150\times1,65}\)
\(=\frac{150\times1,65+165}{150\times1,65}=\frac{165}{1}=165\)
e: \(\left(1+2+4+\cdots+512\right)\times\left(101\times102-101\times101-50-51\right)\)
\(=\left(1+2+4+\cdots+512\right)\times\left(101\times102-101\times101-101\right)\)
\(=\left(1+2+4+\cdots+512\right)\times101\times\left(102-101-1\right)\)
=0
d: 1996x1995-996-1000-1996x1994
=1996x(1995-1994)-1996
=1996x1-1996
=1996-1996
=0
c: 399x46+65x399-10x399-10x399
=399x(46+65-10-10)
=399x91
=36309
b: 1234x5678x(630-315x2):1996
=1234x5678x(630-630):1996
=0
1234 . 5678 . ( 630 - 315 . 2 ) : 1996
= 1234 . 5678 . ( 630 - 630 ) : 1996
= 1234 . 5678 . 0 : 1996
= 0
Ta có: \(1234\cdot5678\cdot\left(630-315\cdot2\right):1996\)
\(=1234\cdot5678\cdot0:1996\)
=0
1234 . 5678 . ( 630 - 315 . 2 ) : 1996
= 1234 . 5678 . ( 630 - 630 ) : 1996
= 1234 . 5678 . 0 : 1996
= 0
Ta có: \(1996\cdot1995-996-100-1996\cdot1994\)
\(=1996\left(1995-1994\right)-1996\)
\(=1996-1996=0\)
Ta có: 1996⋅1995−996−1000−1996⋅1994
=(1996⋅1995−1996⋅1994)−(996+1000)
=1996(1995−1994)−1996
=1996−1996
=0