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\(1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}\)
\(=\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\)
\(=\frac{9}{3}\)
\(=3\)
= 4/3 x 5/4 x 6/5 x 7/6 x 8/7 x 9/8
= 4x5x6x7x8x9/3x4x5x6x7x8 = 9/3 = 3
k mk nha
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
\(1\frac{1}{2}.1\frac{1}{3}.1\frac{1}{4}...1\frac{1}{9}\)
\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{10}{9}\)
\(=\frac{10}{2}=5\)
DẤU . LÀ DẤU NHÂN NHA BẠN
\(1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}\times1\frac{1}{9}\)
\(=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\times\frac{10}{9}\)
\(=\frac{3\times4\times5\times6\times7\times8\times9\times10}{2\times3\times4\times5\times6\times7\times8\times9}=\frac{10}{2}=5\)
~ Hok tốt ~
\(1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}\)
\(=\)\(\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\)
\(=\)\(\frac{9}{3}\)
\(=\)\(3\)
\(1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times1\frac{1}{6}\times1\frac{1}{7}\times1\frac{1}{8}\)
\(=\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times\frac{9}{8}\)
Rút gọn phép tính trên ta được :
\(=\frac{9}{3}=3\)
A=1x(x+1)+1(x+1)(x+2)+1(x+2)(x+3)+....+1(x+99)(x+100)A=1x(x+1)+1(x+1)(x+2)+1(x+2)(x+3)+....+1(x+99)(x+100)
=1x−1x+1+1x+1−1x+2+1x+2−1x+3+....+1x+99−1x+ 100=1x-1x+1+1x+1-1x+2+1x+2-1x+3+....+1x+99-1x+ 100
=1x−1x+100=1x-1x+100
=x+100−xx(x+ 100)=x+100-xx(x+ 100)
=100x(x+100)
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