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Câu a:
7/10.4/9 + 3/10.4/9 - 1 7/9
= 4/9.(7/10 + 3/10) - 16/9
= 4/9 - 16/9
= - 12/9
= - 4/3
Câu b:
- 5/6 + 4/9.(5/4 - 2/3).(-3)^2 + 5/9.30%
= - 5/6 + [5/9 - 8/27].9 + 5/9.3/10
= - 5/6 + 5 - 8/3 + 1/6
= (-5/6 + 1/6) - 8/3 + 5
= - 4/6 - 8/3 + 15/3
= - 2/3 - 8/3 + 15/3
= - 10/3 + 15/3
= 5/3
a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)
Câu c:
1/2017.(1/3 - 7/12 + 1/4) - (6 2/3 - 1,5.2^2) :5/6
= 1/2017.(4/12 - 7/12 + 3/12) - (20/3 - 1,5x 4) : 5/6
= 1/2017.0 - (20/3 - 6) x 6/5
= 0 - (20/3 - 18/3) x 6/5
= - 2/3 x 6/5
= - 4/5
-3/11.(-22)/66.121/15
=(-3).(-22).121
11.66.15
=11
15
3/7.2/5.7/3.20.19/72
=3.2.7.20.19
7.5.3.72
=76
16
6/7.8/13+6/13.9/7-3/13.6/7
=6/7.8/13+6/7.9/13-3/13.6/7
=6/7.(8/13+9/13-3/13)
=6/7.14/13
=12/13
-1/4.152/11+68/4.(-1)/11
=152/4.(-1)/11+68/4.(-1)/11
=(-1)/11.(152/4+68/4)
=(-1)/11.220/4
=-110/22
-5/7.2/11+(-5)/7.9/11+12/7
=-5/7.2/11+-5/7.9/11+12/7
=-5/7.(2/11+9/11)+12/7
=-5/7.1+12/7
=(-5)/7+12/7
=7/7
=1
146/13-(18/7+68/13)
=146/13-18/7-68/13
=(146/13-68/13)-18/7
=78/13-18/7
=6-18/7
=42/7-18/7
=24/7
\(\frac{\frac{1}{9}-\frac{5}{6}-4}{\frac{7}{12}-\frac{1}{36}-10}\)
\(=\frac{\frac{2}{18}-\frac{15}{18}-\frac{72}{18}}{\frac{21}{36}-\frac{1}{36}-\frac{360}{36}}\)
\(=\frac{\frac{-85}{18}}{\frac{-340}{36}}\)
\(=\frac{-85\cdot\frac{1}{18}}{-340\cdot\frac{1}{36}}\)
\(=\frac{-85\cdot\frac{2}{36}}{-340\cdot\frac{1}{36}}\)
\(=\frac{-85\cdot\left(\frac{2}{36}\div\frac{1}{36}\right)}{-340\cdot\left(\frac{1}{36}\div\frac{1}{36}\right)}\)
\(=\frac{-85\cdot2}{-340}\)
\(=\frac{-170}{-340}\)
\(=\frac{-1}{-2}\)
\(=\frac{1}{2}\)