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a) \(\frac{7}{11}\)
b)\(\frac{218}{165}\)
c)\(\frac{1}{4}\)
d)\(\frac{-21}{20}\)
e)\(\frac{2}{9}\)
g) 1
h)\(\frac{-561}{26}\)
i)\(\frac{4}{3}\)
Bài nhìn vô muốn xỉu rồi ='((
1. a) \(\frac{2}{1.4}+\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{91.94}+\frac{2}{94.97}\)
\(=\frac{2}{3}\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{91.94}+\frac{3}{94.97}\right)\)
\(=\frac{2}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{94}-\frac{1}{97}\right)\)
\(=\frac{2}{3}\left(1-\frac{1}{97}\right)=\frac{2}{3}.\frac{96}{97}=\frac{64}{97}\)
b) Bạn tự làm, làm nữa chắc xỉu =((( Khi nào rảnh mình sẽ làm, nếu bạn cần
2 )
a) \(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x\left(x+2\right)}=\frac{1005}{2011}\)
\(\Leftrightarrow\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{1005}{2011}\)
\(\Leftrightarrow\frac{1}{2}\left(1-\frac{1}{x+2}\right)=\frac{1005}{2011}\)
\(\Leftrightarrow1-\frac{1}{x+2}=\frac{1005}{2011}:2=\frac{1005}{4022}\)
\(\Leftrightarrow\frac{1}{x+2}=1-\frac{1005}{4022}=\frac{3017}{4020+2}\)
\(\Rightarrow x=4020\)
a) \(\frac{30}{51}\)\(-\)\(\frac{20}{52}\)\(+\)\(\frac{14}{34}-\frac{56}{91}-2\)
\(=\frac{10}{17}-\frac{5}{13}+\frac{7}{17}-\frac{8}{13}-2\)
= (\(\frac{10}{17}\)\(+\frac{7}{17}\)) \(-\)(\(\frac{5}{13}+\frac{8}{13}\)) \(-2\)
= \(1-1-2\)
=\(0-2\)
= -2
k cho mik nha
\(E=\left(\frac{-2}{3}.\frac{-9}{10}\right).\left(\frac{-5}{6}.\frac{-14}{15}\right).\left(\frac{-20}{21}.\frac{-27}{28}\right).\frac{-35}{36}\)
\(E=\frac{3}{5}.\frac{7}{9}.\frac{45}{49}.\frac{-35}{36}\)
\(E=\left(\frac{3}{5}.\frac{-35}{36}\right).\left(\frac{7}{9}.\frac{45}{49}\right)\)
\(E=\frac{-7}{12}.\frac{5}{7}\)
\(E=\frac{-5}{12}\)
vậy \(E=\frac{-5}{12}\)
E=-2/3.-5/6.-9/10.-14/15.-20/21.-27/28.-35/36
=-2/3.-5/2.3.-3.3/2.5.-2.7/3.5.-4.5/3.7.3.3.3/4.7.-5.7/4.3.3
=-5/12
b) \(\frac{4}{10}+\frac{-2}{9}+\frac{-3}{-5}+\frac{21}{-27}+\frac{-10}{20}\)
\(=\frac{2}{5}-\frac{2}{9}+\frac{3}{5}-\frac{7}{9}-\frac{1}{2}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)-\left(\frac{2}{9}+\frac{7}{9}\right)-\frac{1}{2}\)
\(=1-1-\frac{1}{2}=-\frac{1}{2}\)
a) \(-\frac{5}{2}+\frac{1}{7}+\frac{6}{7}+\frac{1}{2}+\frac{3}{4}\)
\(=\left(\frac{-5}{2}+\frac{1}{2}\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+\frac{3}{4}\)
\(=-2+1+\frac{3}{4}\)
\(=-1+\frac{3}{4}\)
\(=-\frac{1}{4}\)


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