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Ta gọi biểu thức đó là A
Ta có công thức \(\frac{a}{b.c}=\frac{a}{c-b}.\left(\frac{1}{b}-\frac{1}{c}\right)\)
Dựa vào công thức ta có
\(\frac{4}{2.4}=2.\left(\frac{1}{2}-\frac{1}{4}\right)\)
\(\frac{4}{4.6}=2.\left(\frac{1}{4}-\frac{1}{6}\right)\)
\(....................\)
\(\frac{4}{18.20}=2.\left(\frac{1}{18}-\frac{1}{20}\right)\)
\(\Rightarrow\)\(A=2.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+....+\frac{1}{18}-\frac{1}{20}\right)\)
\(\Rightarrow\)\(A=2.\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(\Rightarrow\)\(A=2.\left(\frac{9}{20}\right)=\frac{18}{20}\)
Ai thấy đúng thì ủng hộ nha !!!
ax4=1/2-1/4+1/4-1/6+1/6+1/8+.......+1/16-1/18+1/18+1/20
ax4 =1/2-1/20
ax4 =9/20
a=9/20:4
a=9/80
2/2×4 + 2/4×6 + ... + 2/16×18 + 2/18×20
= 1/2 - 1/4 + 1/4 - 1/6 + ... + 1/16 - 1/18 + 1/18 - 1/20
= 1/2 - 1/20
= 10/20 - 9/20
= 9/20
2/2x4+2/4x6+...+2/16x18+2/18x20
=1/2=1/4+1/4-1/6+...+1/16-1/18+1/18-1/20
=1/2-1/20
=10/20-9/20
=1/20
\(\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{18.20}\right).10-x=0\)
\(2\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{18.20}\right).10-x=0\)
\(2\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{18}-\frac{1}{20}\right).10-x=0\)
\(2\left(\frac{1}{2}-\frac{1}{20}\right).10-x=0\)
\(2.\frac{9}{20}.10-x=0\)
\(9-x=0\)
\(x=9-0\)
\(x=9\)
Gọi tổng là A ta có :
A x 2 = 2/2.4 + 2/4.6 + 2/6.8 + ... + 2/18.20
A x 2 = 1/2 - 1/4 - 1/4 - 1/6 + 1/6 - 1/8 + ... + 1/18 - 1/20
A x 2 = 1/2 - 1/20
A x 2 = 9/20
A = 9/20 : 2
A = 9/40
1/2.4 + 1/4.6 + 1/6.8 + ... + 1/96.98 + 1/98.100
= 1/2.(2/2.4 + 2/4.6 + 2/6.8 + ... + 2/96.98 + 2/98.100)
= 1/2.(1/2 - 1/4 + 1/4 - 1/6 + ... + 1/96 - 1/98 + 1/98 - 1/100)
= 1/2.(1/2 - 1/100)
= 1/2.49/100
= 49/200
\(a,\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+....+\frac{4}{16.18}+\frac{4}{18.20}\)
\(=\frac{4}{2}\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{18}-\frac{1}{20}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(=2.\frac{9}{20}\)
\(=\frac{9}{10}\)
\(b,\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
thank you
a, \(\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+..+\frac{4}{16.18}+\frac{4}{18.20}\)
\(=\frac{4}{2}\cdot\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+....+\frac{1}{16}-\frac{1}{18}+\frac{1}{18}-\frac{1}{20}\right)\)
\(=2\cdot\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(=2\cdot\frac{9}{20}=\frac{9}{10}\)
b, \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}=\frac{9}{10}\)
A, \(\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+.......+\frac{4}{16\times18}+\frac{4}{18\times20}\)
= \(2\times\) \(\left(\frac{4-2}{2\times4}+\frac{6-4}{4\times6}+\frac{8-6}{6\times8}+.......+\frac{18-16}{16\times18}+\frac{20-18}{18\times20}\right)\)
= \(2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+.......+\frac{1}{16}-\frac{1}{18}+\frac{1}{18}-\frac{1}{20}\right)\)
= \(2\times\left(\frac{1}{2}-\frac{1}{20}\right)\)
= \(2\times\left(\frac{10}{20}-\frac{1}{20}\right)\)
= \(2\times\frac{9}{20}\)
= \(\frac{9}{10}\)
B, \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+.......+\frac{1}{90}\)
=\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+.......+\frac{1}{9\times10}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.......+\frac{1}{9}-\frac{1}{10}\)
= \(1-\frac{1}{10}\)
= \(\frac{9}{10}\)
CHÚC BẠN HỌC GIỎI VÀ ĐẠT ĐƯỢC NHIỀU THÀNH CÔNG TRONG CUỘC SỐNG.
Ta có:
a) \(\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{16.18}+\frac{4}{18.20}\)
\(=\frac{4}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{16}-\frac{1}{18}+\frac{1}{18}-\frac{1}{20}\right)\)
\(=2.\left(\frac{1}{2}-\frac{1}{20}\right)=2.\frac{9}{20}=\frac{9}{10}\)
b) \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{1}-\frac{1}{10}=\frac{9}{10}\)
a, 4/2x4+4/4x6+4/6x8+......+4/16x18+4/18x20=\(\frac{9}{10}\)
b, 1/2+1/6+1/12+1/20+......+1/90 =\(\frac{9}{10}\)