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\(\left(3\frac{1}{2}-2x\right).75\%=7\frac{1}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{75}{100}=\frac{22}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{3}{4}=\frac{22}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{3}{4}\)
\(\frac{7}{2}-2x=\frac{22}{3}.\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{88}{9}\)
\(2x=\frac{7}{2}-\frac{88}{9}\)
\(2x=\frac{63}{18}-\frac{176}{18}\)
\(2x=\frac{-113}{18}\)
\(x=\frac{-113}{18}:2\)
\(x=\frac{-113}{36}\)
Bài 2:
b: x+25%x=-1,25
=>1,25x=-1,25
hay x=-1
c: x-75%x=1/4
=>1/4x=1/4
hay x=1
Bài 2:
a: =3/2-11/4=6/4-11/4=-5/4
b: =-49/6-17/2=-49/6-51/6=-100/6=-50/3
Bài 2:
- \(\frac75\) + \(x\) = - \(\frac34\)
\(x\) = - \(\frac34+\frac75\)
\(x=-\frac{15}{20}\) + \(\frac{28}{20}\)
\(x\) = \(\frac{13}{20}\)
Vậy \(x=\frac{13}{20}\)
Bài 3:
- \(\frac74\) + \(\frac14:x\) = \(\frac32\)
\(\frac14:x\) = \(\frac32+\frac74\)
\(\frac14:x\) = \(\frac64+\frac74\)
\(\frac14:x=\frac{13}{4}\)
\(x=\frac14:\frac{13}{4}\)
\(x=\frac14\times\frac{4}{13}\)
\(x=\frac{1}{13}\)
Vậy \(x=\frac{1}{13}\)
kazuto kirigaya thật là bt làm ko đó ko bt thì nói đi còn bt thì làm đi
a)\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
\(=\frac{-7}{25}.1-\frac{18}{25}\)
\(=-\frac{7}{25}-\frac{18}{25}\)
\(=-1\)
b)\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}\)
\(=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)
\(=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=\frac{5}{7}.0\)
\(=0\)




\(75\%+1,1:\left(\frac{2}{5}-1\frac{1}{2}\right)-\left(\frac{1}{3}\right)^2=\frac{3}{4}+1,1:\left(\frac{2}{5}-\frac{3}{2}\right)-\frac{1}{9}=\frac{3}{4}+1,1:\left(-\frac{11}{10}\right)-\frac{1}{9}=\)
\(=\frac{3}{4}-1,1:1,1-\frac{1}{9}=\frac{3}{4}-1-\frac{1}{9}=-\frac{13}{36}\)