\(\frac{6^3+3.6^2+3^3}{13}=\frac{6^3+108+3^3}{13}.\)

\(=\frac{216+108+27}{13}=\frac{324+27}{13}\)

\(=\frac{351}{13}=27\)

\(\frac{6^3+3\cdot6^2+3^3}{13}=\frac{2^3\cdot3^3+3\cdot3^2\cdot2^2+3^3}{13}=\frac{3^3\left(2^3+2^2+1\right)}{13}=\frac{27\cdot13}{13}=27\)

6^2.(6+3)+3^3/-13=36.3^2+3^3/-13=3^2(36+3)/-13=9.39/-13=-27

2^10.3^8-2.3^9.2^9 / 2^10.3^8+3^8.2^8.2^2.5

=2^10.3^8(1-3) / 2^10.3^8(1+5)

=-2/6=-1/3

Chi bằng bạn cầm máy tính hay bạn tính thì nhanh hơn chứ bạn chờ người khác trả lời giúp thì hơi lâu đó.

\(\frac{6^3+3.6^2+3^3}{-13}\)\(=\frac{6^2.\left(6+3\right)+3^3}{-13}\)\(=\frac{6^2.9+3^3}{-13}\)\(=\frac{6^2.3^2+3^3}{-13}\)\(=\frac{3^2.\left(6^2+3\right)}{-13}\)\(=\frac{3^2.39}{-13}\)\(=3^2.\left(-3\right)\)\(=-3^3=-27\)

_Học_tốt_

a) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{3}{16}\)

b) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{2^3.3^3+3.2^2.3^2+3^3}{-13}=\frac{3^3.\left(2^3+2^2+1\right)}{-13}=-3^3\)

c)  \(\frac{5^4.20^4}{25^5.4^5}=\frac{100^4}{100^5}=\frac{1}{100}\)

d)  \(\frac{\left(5^4-5^3\right)^3}{125^4}=\frac{\left[5^3\left(5-1\right)\right]^3}{\left(5^3\right)^4}=\frac{5^9.4^3}{5^{12}}=\frac{4^3}{5^3}\)