a) \(2^3=2.2.2=8\)

\(2^4=2.8=16\)

\(2^5=2.16=32\)

\(2^6=2.32=64\)

\(2^7=2.64=128\)

\(2^8=2.128=256\)

\(2^9=2.256=512\)

\(2^{10}=2.512=1024\)

b) \(4^2=4.4=16\)

\(4^3=16.4=64\)

\(4^4=64.4=256\)

Còn lại tương tự 

a) \(2^{3+4+5+6+7+8+9+10}=2^{52}\)

b) \(3^{14}\)\(=4782969\)

c) \(4^9\)\(=262144\)

d) \(5^9\)\(=1953125\)

e) \(6^9\)\(=10077696\)

K mk nha, mk nhanh nha

a: \(=36:4+2\cdot25=9+50=59\)

b: \(=79\left(82+18\right)=79\cdot100=7900\)

c: \(=49-9-\left(4^2+2^2\right)\)

\(=40-16-4=40-20=20\)

d: \(=16+\left[400:\left(200-42-138\right)\right]\)

\(=16+400:20=16+20=36\)

$A=1-$$3+5-7+...+2001-2003+2005$

$=\left(1-3\right)+\left(5-7\right)+...+\left(2001-2003\right)+2005$(Có 1002 cặp)

$=\left(-2\right).1002+2005$

$=-2004+2005$

$=1$

- A = 2097152.

\(8-12x+6x^2-x^3\)

\(=\left(2-x\right)^3\)

\(125x^3-75x^2+15x-1\)

\(=\left(5x-1\right)^3\)

\(x^2-xz-9y^2+3yz\)

\(=\left(x-3y\right)\left(x+3y\right)-z\left(x-3y\right)\)

\(=\left(x-3y\right)\left(x+3y-z\right)\)

\(x^3-x^2-5x+125\)

\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-5x+25-x\right)\)

\(=\left(x+5\right)\left(x^2-6x+25\right)\)

\(x^3+2x^2-6x-27\)

\(=x^3+5x^2+9x-3x^2-15x-27\)

\(=x\left(x^2+5x+9\right)-3\left(x^2+5x+9\right)\)

\(=\left(x-3\right)\left(x^2+5x+9\right)\)

\(12x^3+4x^2-27x-9\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x^2-9\right)\)

\(=\left(3x+1\right)\left(2x-3\right)\left(2x+3\right)\)

\(4x^4+4x^3-x^2-x\)

\(=4x^3\left(x+1\right)-x\left(x+1\right)\)

\(=x\left(x+1\right)\left(4x^2-1\right)\)

\(=x\left(x+1\right)\left(2x-1\right)\left(2x+1\right)\)

Là 00000000000000

a)56+48=104

b)343-216-125=2

c)1296-32*27=1296-864=432

d)=0(vì các số *với 0 đều =0(\(2^4\)-4\(^2\)=0)

a) \(2^3.7+3^2.6=8.7+9.6\)

                          \(=56+54\) 

                          \(=110\)

b) \(7^3-6^3-5^3=343-216-125\)

                            \(=2\)   

c) \(6^4-2^5.3^3=1296-32.27\)

                        \(=1296-864\)

                        \(=432\)

d) \(\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right)\left(2^4-4^2\right)\)

\(=\left(7^9-9^7\right)\left(6^8-8^6\right)\left(3^5-5^3\right).0\)

\(=0\)

NHỚ K CHO MÌNH NHÉ !

a) \(3^{7} \cdot 27^{5} \cdot 81^{3}\)

• Đổi về cơ số 3: \(27 = 3^{3} , \textrm{ }\textrm{ } 81 = 3^{4}\).

\(3^{7} \cdot \left(\right. 3^{3} \left.\right)^{5} \cdot \left(\right. 3^{4} \left.\right)^{3} = 3^{7} \cdot 3^{15} \cdot 3^{12} = 3^{7 + 15 + 12} = 3^{34} .\)

b) \(100^{6} \cdot 1000^{5} \cdot 10 \textrm{ } 000^{3}\)

• Đổi về cơ số 10: \(100 = 10^{2} , \textrm{ }\textrm{ } 1000 = 10^{3} , \textrm{ }\textrm{ } 10 \textrm{ } 000 = 10^{4}\).

\(\left(\right. 10^{2} \left.\right)^{6} \cdot \left(\right. 10^{3} \left.\right)^{5} \cdot \left(\right. 10^{4} \left.\right)^{3} = 10^{12} \cdot 10^{15} \cdot 10^{12} = 10^{39} .\)

c) \(\frac{36^{5}}{18^{5}}\)

• Do cùng số mũ:

\(\left(\left(\right. \frac{36}{18} \left.\right)\right)^{5} = 2^{5} = 32.\)

d) \(24 \cdot 5^{2} + 5^{2} \cdot 5^{3}\)

\(= 24 \cdot 25 + 25 \cdot 125 = 600 + 3125 = 3725.\)

e) \(\frac{125^{4}}{5^{8}}\)

• Đổi về cơ số 5: \(125 = 5^{3}\).

\(\left(\right. 5^{3} \left.\right)^{4} : 5^{8} = 5^{12} : 5^{8} = 5^{12 - 8} = 5^{4} = 625.\)

TÓM lại là a) \(3^{34}\)
b) \(10^{39}\)
c) \(32\)
d) \(3725\)
e) \(625\)

bạn muốn chép đáp án hay sem cách làm///??

a: \(3^7\cdot27^5\cdot81^3\)

\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)

\(=3^7\cdot3^{15}\cdot3^{12}=3^{7+15+12}=3^{34}\)

b: \(100^6\cdot1000^5\cdot10000^3\)

\(=\left(10^2\right)^6\cdot\left(10^3\right)^5\cdot\left(10^4\right)^3\)

\(=10^{12}\cdot10^{15}\cdot10^{12}=10^{15+12+12}=10^{39}\)

c: \(36^5:18^5=\left(\frac{36}{18}\right)^5=2^5=32\)

d: \(24\cdot5^2+5^2\cdot5^3\)

\(=5^2\left(24+5^3\right)\)

\(=25\cdot\left(24+125\right)=25\cdot149=3725\)

e: \(125^4:5^8=\left(5^3\right)^4:5^8=5^{12}:5^8=5^{12-8}=5^4\)

1. \(14-\left(\frac{17}{2}+\frac{7}{2}\right)=14-12=2\)

2. \(12+64:\left(3-\frac{5}{3}\right)=12+64:\frac{4}{3}=12+\frac{16}{3}=\frac{52}{3}\)

3. \(\left(\frac{2}{3}+\frac{3}{4}-\frac{4}{5}\right).\frac{5}{6}:\frac{7}{8}=\frac{47}{60}.\frac{5}{6}.\frac{8}{7}=\frac{47}{63}\)

Nguyễn Minh Thụ là có sai vài bước đó nhưng k sao , mk vẫn cảm ơn bạn