a) \(10,\left(3\right)+0,\left(4\right)-8,\left(6\right)\)

\(=\frac{31}{3}+\frac{4}{9}-\frac{26}{3}\)

\(=\left(\frac{31}{3}-\frac{26}{3}\right)+\frac{4}{9}=\frac{5}{3}+\frac{4}{9}=\frac{15}{9}+\frac{4}{9}=\frac{19}{9}\)

b) \(\left[12,\left(1\right)-2,3\left(6\right)\right]:4,\left(21\right)\)

\(=\left[\frac{109}{9}-\frac{71}{30}\right]:\frac{139}{33}\)

\(=-\frac{52}{45}:\frac{139}{33}=-\frac{52}{45}\cdot\frac{33}{139}=-\frac{572}{2085}\)(số xấu quá)

c) \(3\frac{1}{2}\cdot\frac{4}{49}-\left[2,\left(4\right)\cdot2\frac{5}{11}\right]:\frac{-42}{53}\)

\(=\frac{7}{2}\cdot\frac{4}{49}-\left[\frac{22}{9}\cdot\frac{27}{11}\right]\cdot\frac{-53}{42}\)

\(=\frac{2}{7}-6\cdot\left(-\frac{53}{42}\right)=\frac{2}{7}-\left(-\frac{53}{7}\right)=\frac{2}{7}+\frac{53}{7}=\frac{55}{7}\)

$\textbf{a)}$

$A=\dfrac{\left(\dfrac49\right)^2\cdot\left(-\dfrac9{16}\right)\cdot(-1)^{19}}{\left(\dfrac4{25}\right)^2\cdot\left(-\dfrac{25}{144}\right)^2\cdot\left(-\dfrac{49}{144}\right)^2}$

$=\dfrac{\dfrac{16}{81}\cdot\left(-\dfrac9{16}\right)\cdot(-1)}{\dfrac{16}{625}\cdot\dfrac{625}{144^2}\cdot\dfrac{49^2}{144^2}}$

$=\dfrac{\dfrac19}{\dfrac{49^2}{144^4}}$

$=\dfrac19\cdot\dfrac{144^4}{49^2}$

$=\dfrac19\cdot\dfrac{(2^4\cdot3^2)^4}{7^4}$

$=\dfrac{2^{16}\cdot3^6}{7^4}$

$=\dfrac{47775744}{2401}.$

$\textbf{b)}$

$B=\dfrac{\left(\dfrac23\right)^3\cdot\left(-\dfrac34\right)^2\cdot(-1)^{2003}}{\left(\dfrac25\right)^2\cdot\left(-\dfrac5{12}\right)^3}$

$=\dfrac{\dfrac8{27}\cdot\dfrac9{16}\cdot(-1)}{\dfrac4{25}\cdot\left(-\dfrac{125}{1728}\right)}$

$=\dfrac{-\dfrac16}{-\dfrac5{432}}$

$=\dfrac16\cdot\dfrac{432}{5}$

$=\dfrac{72}{5}.$

Tính bằng máy tính cầm tay

mình cần tính nhanh cơ hoặc tính ra đày đủ đó

Biểu thức 1

$3\dfrac12\cdot\dfrac4{49}-\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{8}\right)$

$=\dfrac72\cdot\dfrac4{49}-\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\left(-\dfrac4{21}\right)$

$=\dfrac27-6\cdot\left(-\dfrac4{21}\right)$

$=\dfrac27+\dfrac87$

$=\dfrac{10}{7}.$

Biểu thức 2

$\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot3\dfrac13\right):\dfrac43$

$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac{10}{3}\right):\dfrac43$

$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac43\cdot\dfrac34$

$=\dfrac{10}{81}\cdot\dfrac{99}{250}-1$

$=\dfrac{11}{225}-1$

$=-\dfrac{214}{225}.$

b, \(2^n\left(2^{-1}+4\right)=9\cdot2^5\)

=> \(2^n\cdot\frac{9}{2}=9\cdot2^5\)

=> \(2^n=2^6\)

Vậy \(n=6\left(tm\right)\)

a, \(A=4\cdot16\cdot\frac{9}{16}\cdot\frac{4}{5}\cdot\frac{27}{8}=\frac{486}{5}=97,2\)

Biểu thức 1

$A=3\dfrac12\cdot\dfrac4{49}\cdot\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{5}\right)$

$=\dfrac72\cdot\dfrac4{49}\cdot\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\dfrac5{-42}$

$=\dfrac72\cdot\dfrac4{49}\cdot6\cdot\dfrac5{-42}$

$=\dfrac{12}{7}\cdot\dfrac5{-42}$

$=\dfrac{60}{-294}$

$=-\dfrac{10}{49}.$

Biểu thức 2

$B=\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot1\dfrac13\right):\dfrac43$

$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac43\right):\dfrac43$

$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac{8}{15}\cdot\dfrac34$

$=\dfrac{10}{81}\cdot\dfrac{99}{250}-\dfrac25$

$=\dfrac{11}{225}-\dfrac{90}{225}$

$=-\dfrac{79}{225}.$

$A=\dfrac{\left(\dfrac49\right)^2\cdot\left(-\dfrac9{16}\right)\cdot(-1)^{19}}{\left(\dfrac4{25}\right)^2\cdot\left(-\dfrac{25}{144}\right)^2\cdot\left(-\dfrac{49}{144}\right)^2}$

$=\dfrac{\dfrac{16}{81}\cdot\left(-\dfrac9{16}\right)\cdot(-1)}{\dfrac{16}{625}\cdot\dfrac{625}{144^2}\cdot\dfrac{49^2}{144^2}}$

$=\dfrac{\dfrac19}{\dfrac{49^2}{144^4}}$

$=\dfrac19\cdot\dfrac{144^4}{49^2}$

$=\dfrac19\cdot\dfrac{(2^4\cdot3^2)^4}{7^4}$

$=\dfrac19\cdot\dfrac{2^{16}\cdot3^8}{7^4}$

$=\dfrac{2^{16}\cdot3^6}{7^4}$

$=\dfrac{65536\cdot729}{2401}$

$=\dfrac{47775744}{2401}.$

làm ơn giúp mình bài toán hình phần d với cảm ơn nhiều

Bài toán hình phần d nào hả bạn?

1)

b) \(\left(-0,25\right):\left(\frac{1}{2}\right)^2\)

\(=\left(-\frac{1}{4}\right):\frac{1}{4}\)

\(=-1.\)

h) \(\left(-15\right).0,23+\left(-15\right).0,77\)

\(=\left(-15\right).\left(0,23+0,77\right)\)

\(=\left(-15\right).1\)

\(=-15.\)

Chúc bạn học tốt!