11611/4950!

2,34(56)=\(\frac{23222}{9900}\)

2,34(56) = 2 + 0,34(56)  = 2,34 + 0,00(01) * 56 = 2,34 + 56 * 0,01 * 0,(01) = 2,34 + 56 * \(\frac{1}{100}\) * \(\frac{1}{99}\) = 2,34 + \(\frac{56}{9900}\)= \(\frac{23222}{9900}\)= \(\frac{11611}{4950}\)

minh moi hoc lop 6 thoi

56,2(5)=5063/90

1,5(6)=47/30

2,34(36)=1289/550

`a)( -5/7)+7,45+12/7-2,45`

`=(-5/7 +12/7)+(7,45-2,45)`

`=1+5=6`

`b)7/12* (-2,34)- 7/12 * (-0,34)`

`=7/12 *[(-2,34)+0,34]`

`=7/12 *(-2)`

`=-7/6`

`c)0,75 *6/13+3/4 *7/13-2,75`

`=3/4*6/13+3/4 *7/13-2,75`

`=3/4*(6/13+7/13)-2,75`

`=3/4*1-11/4`

`=3/4-11/4`

`=(3-11)/4`

`=(-8)/4=-2`

2,34(56)=2+1711/4950=11611/4950

13,25(3)=13+19/75=994/75

56,2(5)=56+23/90=5063/90

43,2(34)=43+116/495=21401/495

\(2,34\left(56\right)=2,34+\frac{1}{100}.56.\frac{1}{99}=\frac{11611}{4950}\)

\(13,25\left(3\right)=13,25+\frac{1}{100}.3.\frac{1}{9}=\frac{994}{75}\)

\(56,2\left(5\right)=56,2+\frac{1}{10}.5.\frac{1}{9}=\frac{5063}{90}\)

\(43,2\left(34\right)=43,2+\frac{1}{10}.34.\frac{1}{99}=\frac{21401}{495}\)

P(x) = x^2 + x^4.4 + 213

Thay x = 2 vào P(x) ta có:

P(2) = 2^2 + 2^4.4 + 213

P(2) = 4 + 16.4 + 213

P(2) = 4 + 64 + 213

P(2) = 68 + 213

P(2) = 281