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a: \(y\times4\frac{7}{12}=6\frac14\)
=>\(y\times\frac{55}{12}=\frac{25}{4}\)
=>\(y=\frac{25}{4}:\frac{55}{12}=\frac{25}{4}\times\frac{12}{55}=\frac{3\times5}{11}=\frac{15}{11}\)
b: \(y:3\frac78=5\frac12\)
=>\(y:\frac{31}{8}=\frac{11}{2}\)
=>\(y=\frac{11}{2}\times\frac{31}{8}=\frac{341}{16}\)
c: \(6\frac17:y=5\frac25\)
=>\(\frac{43}{7}:y=\frac{27}{5}\)
=>\(y=\frac{43}{7}:\frac{27}{5}=\frac{43}{7}\times\frac{5}{27}=\frac{215}{189}\)
a, \(\frac{2}{5}\)+ y = 1
y = 1 - \(\frac{2}{5}\)
y = \(\frac{3}{5}\)
b, \(\frac{6}{8}\)- y = \(\frac{3}{5}\)
y = \(\frac{6}{8}\)- \(\frac{3}{5}\)
y = \(\frac{3}{20}\)
c, y : 6 = \(\frac{7}{4}\)
y = \(\frac{7}{4}\)x 6
y = \(\frac{21}{2}\)
d, y - \(\frac{1}{3}\)= 5 x \(\frac{2}{3}\)
y - \(\frac{1}{3}\)= \(\frac{10}{3}\)
y = \(\frac{10}{3}\)+ \(\frac{1}{3}\)
y = \(\frac{11}{3}\)
a,2/5 + y = 1
y = 1 - 2/5
y = 3/5
b, 6/8 - y = 3/5
y = 6/8 - 3/5
y = 3/10
c, y / 6 = 7/4
y = 7/4 * 6
y = 15/2
d, y - 1/3 = 5 * 2/3
y - 1/3 = 10/3
y = 10/3 + 1/3
y = 11/3
\(a,y+\dfrac{2}{3}=\dfrac{5}{2}\)
\(y=\dfrac{5}{2}-\dfrac{2}{3}\)
\(y=\dfrac{15}{6}-\dfrac{4}{6}\)
\(y=\dfrac{11}{6}\)
\(b,3\dfrac{4}{5}-y=\dfrac{18}{5}\)
\(y=3\dfrac{4}{5}-\dfrac{18}{5}\)
\(y=\dfrac{19}{5}-\dfrac{18}{5}\)
\(y=\dfrac{1}{5}\)
\(c,y-4\dfrac{5}{6}=2\dfrac{1}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{13}{6}+\dfrac{5}{6}\)
\(y-\dfrac{29}{6}=\dfrac{18}{6}\)
\(y=\dfrac{18}{6}+\dfrac{29}{6}\)
\(y=\dfrac{47}{6}\)
7/4-y x 5/6 = 1/2+1/3
7/4-y x 5/6=5/6
y x 5/6=7/4-5/6
y x 5/6=11/12
y=11/12 : 5/6
y=11/10
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{5}{6}\)
\(\frac{7}{4}-y=\frac{5}{6}\div\frac{5}{6}\)
\(\frac{7}{4}-y=1\)
\(y=1+\frac{7}{4}\)
\(y=\frac{11}{4}\)
\(\frac{7}{4}-y\cdot\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-y\cdot\frac{5}{6}=\frac{5}{6}\)
\(y\cdot\frac{5}{6}=\frac{7}{4}-\frac{5}{6}\)
\(y\cdot\frac{5}{6}=\frac{11}{12}\)
\(y=\frac{11}{12}:\frac{5}{6}\)
\(y=\frac{11}{10}\)