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Hoàng Thị Thanh Trúc
a,
\(\frac{x}{7}=\frac{6}{21}\Rightarrow x=\frac{6.7}{21}=2\)
b,
\(\frac{-5}{y}=\frac{20}{28}\Rightarrow y=\frac{\left(-5\right).28}{20}=-7\)
\(\frac{x}{7}=\frac{6}{21}\Rightarrow x=\frac{6.7}{21}=\frac{42}{21}=2\)
\(-\frac{5}{y}=\frac{20}{28}\Rightarrow y=-\frac{5.28}{20}=-\frac{140}{20}=-7\)
\(\frac{2}{7}=\frac{6}{21}\)
\(\frac{-5}{-7}=\frac{5}{7}=\frac{20}{28}\)
\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\Rightarrow\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\)
\(\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\)
\(\Rightarrow x=165;y=20;z=25\)
Ta có ; \(\frac{2}{x}=\frac{x}{8}\)
\(\Leftrightarrow x^2=2.8\)
\(\Leftrightarrow x^2=16\)
\(\Rightarrow x=\left\{-4;4\right\}\)
\(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3\times21}{7}=9\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Leftrightarrow3.\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow3x+4x=20-6\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)
a; \(\dfrac{-x}{4}\) = \(\dfrac{-2}{x}\)
-\(x.x\) = -2.4
-\(x^2\) = -8
\(x^2\) = 8
\(\left[{}\begin{matrix}x=-\sqrt{8}\\x=\sqrt{8}\end{matrix}\right.\)
Vậy \(x\in\) {-\(\sqrt{8}\); \(\sqrt{8}\)}

\(\frac{x}{7}=\frac{6}{21}\)
\(\Rightarrow x=\frac{7.6}{21}\)
\(\Rightarrow x=2\)
\(-\frac{5}{y}=\frac{20}{28}\)
\(\Rightarrow y=\frac{-5.28}{20}\)
\(\Rightarrow y=-7\)