trả lời bn lớp 6 ạ

x(y+1)+y=2

=>x(y+1)+y+1=3

=>(x+1)(y+1)=3

=>(x+1;y+1)∈{(1;3);(3;1);(-1;-3);(-3;-1)}

=>(x;y)∈{(0;2);(2;0);(-2;-4);(-4;-2)}

help mì 

a: \(\left(x+1\right)\left(y+2\right)=4\)

=>\(\left(x+1;y+2\right)\in\left\{\left(1;4\right);\left(4;1\right);\left(-2;-2\right);\left(2;2\right);\left(-1;-4\right);\left(-4;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(0;2\right);\left(3;-1\right);\left(-3;-4\right);\left(1;0\right);\left(-2;-6\right);\left(-5;-3\right)\right\}\)

b: \(\left(2x-1\right)\left(y-1\right)=7\)

=>\(\left(2x-1;y-1\right)\in\left\{\left(1;7\right);\left(7;1\right);\left(-1;-7\right);\left(-7;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(1;8\right);\left(4;2\right);\left(0;-6\right);\left(-3;0\right)\right\}\)

c: \(x+6=y\left(x-1\right)\)

=>\(x-1+7=y\left(x-1\right)\)

=>\(\left(x-1\right)\left(1-y\right)=-7\)

=>\(\left(x-1\right)\left(y-1\right)=7\)

=>\(\left(x-1;y-1\right)\in\left\{\left(1;7\right);\left(7;1\right);\left(-1;-7\right);\left(-7;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(2;8\right);\left(8;2\right);\left(0;-6\right);\left(-6;0\right)\right\}\)

d: \(2xy+6x+y=1\)

=>\(2x\left(y+3\right)+y+3=4\)

=>\(\left(2x+1\right)\left(y+3\right)=4\)

=>\(\left(2x+1;y+3\right)\in\left\{\left(1;4\right);\left(-1;-4\right);\left(4;1\right);\left(-4;-1\right);\left(2;2\right);\left(-2;-2\right)\right\}\)

=>\(\left(x;y\right)\in\left\{\left(0;1\right);\left(-1;-7\right);\left(\dfrac{3}{2};-2\right);\left(-\dfrac{5}{2};-4\right);\left(\dfrac{1}{2};-1\right);\left(-\dfrac{3}{2};-5\right)\right\}\)