sau bạn đăng tách ra cho mn cùng giúp nhé 

a, \(\left(-2x^5+3x^2-4x^3\right):2x^2=-x^3+\frac{3}{2}-2x\)

b, \(\left(x^3-2x^2y+3xy^2\right):\left(-\frac{1}{2}x\right)=-\frac{x^2}{2}+xy-\frac{3y^2}{2}\)

c, \(\left(3x^2y^2+6x^3y^3-12xy^2\right):3xy=xy+2x^2y^2-4y\)

d, \(\left(4x^3-3x^2y+5xy^2\right):\frac{1}{2}x=2x^2-\frac{3xy}{2}+\frac{5y^2}{2}\)

e, \(\left(18x^3y^5-9x^2y^2+6xy^2\right):3xy^2=6x^2y^3-3x+2\)

f, \(\left(x^4+2x^2y^2+y^4\right):\left(x^2+y^2\right)=\left(x^2+y^2\right)^2:\left(x^2+y^2\right)=x^2+y^2\)

a: =xy(1/3+4-2)=7/3xy

b: =xy^2(-1+3/2+4/3)=(1/3+3/2)xy^2=11/6xy^2

c: =4x^2y^2+2/3x^2y^2-4/3x^2y=-4/3x^2y+14/3x^2y^2

d: =3x^2y^2z+4x^2y^2z-8x^2y^2z=-x^2y^2z

a: =-2x^2y^3z^2

Hệ số: -2

bậc: 7

b: =-1/3x^3y^3

hệ số: -1/3

bậc: 6

c: =-1/2x^6y^5

hệ số: -1/2

bậc: 11

d: =-2/3x^3y^4

hệ số: -2/3

bậc: 7

e: =3/4x^3y^4

hệ số:3/4

bậc: 7

a) 5x² ( 3x² -7x+2)-15x(x-3)

=15x⁴-35x³+10x²-15x²+45x

=15x⁴-35x³-5x²+45x

c) (x+3)(x-3)(x-2)(x+1)

=(x²-9)(x²+x-2x-2)

=(x²-9)(x²-x-2)

=x⁴-x³-2x²-9x²+9x+18

=x⁴-x³-11x²+9x+18

d)(2x+1)²+(4x-1)²+2(2x+1)(4x+1)

=2x²+4x+1-16x²-8x+1

=2x²+4x+1-16x²-8x+1+16x²-4x+8x-2

=2x²+7

e) (2x²-3x)(5x²-2x+1)-10x²(x+3)

=10x⁴ -4x³+2x²-15x³+6x²-3 -10x²-30x

=10x⁴-19x³-2x²-30x-3

thanks bn nka

a: \(\dfrac{x^2-xy+y^2}{x^2+2xy+y^2}\cdot\dfrac{x^2+3xy+2y^2}{x^2-3xy+2y^2}\)

\(=\dfrac{x^2-xy+y^2}{\left(x+y\right)^2}\cdot\dfrac{\left(x+2y\right)\left(x+y\right)}{\left(x-2y\right)\left(x-y\right)}\)

\(=\dfrac{\left(x^2-xy+y^2\right)\left(x+2y\right)}{\left(x-2y\right)\left(x^2-y^2\right)}\)

b: \(\dfrac{x^2+1}{3x}:\dfrac{x^2+1}{x-1}:\dfrac{x^3-1}{x^2+x}:\dfrac{x^2+2x+1}{x^2+x+1}\)

\(=\dfrac{x-1}{3x}\cdot\dfrac{x\left(x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\cdot\dfrac{x^2+x+1}{\left(x+1\right)^2}\)

\(=\dfrac{x\left(x+1\right)}{3x\left(x+1\right)^2}=\dfrac{1}{3\left(x+1\right)}\)

đề bài là rút gọn à