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A . 89 - ( 73 - x ) = 20
73 - x = 89 - 20
73 - x = 69
\(\Rightarrow\)x = 4
B .
a. 4.(x+41) = 7
x + 41 = 7 : 4 = 1,75
x = 1,75 - 41 = -39,25
b. 4.(x-3) = 72 - 110 = 49 - 1 = 48
x - 3 = 48 : 4 = 12
x = 12 + 3 = 15
a) \(2^{4x}-3^{2x}=144-164:41\)
\(\Leftrightarrow16^x-9^x=144-4\)
\(\Leftrightarrow\) ......
bjan tự tính tiếp đc òi
a: \(\frac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}\)
\(=\frac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}=\frac{2^8\cdot5^7\left(2^3+3^3\right)}{2^5\cdot5^4\left(2^3+3^3\right)}\)
\(=2^3\cdot5^3=10^3=1000\)
b: \(149-\left(35:x+3\right)\cdot17=13\)
=>\(\left(35:x+3\right)\cdot17=149-13=136\)
=>35:x+3=136:17=8
=>35:x=8-3=5
=>\(x=\frac{35}{5}=7\)
c: \(121:11-\left(4x+5:3\right)=4\)
=>11-(4x+5/3)=4
=>4x+5/3=11-4=7
=>\(4x=7-\frac53=\frac{21}{3}-\frac53=\frac{16}{3}\)
=>\(x=\frac{16}{3}:4=\frac43\)
d: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=40\)
=>\(41-\left(2x-5\right)=\frac{720}{40}=18\)
=>2x-5=41-18=23
=>2x=28
=>\(x=\frac{28}{2}=14\)
e: Sửa đề: (x+1)+(x+2)+(x+3)+...+(x+100)=5700
=>100x+(1+2+3+...+100)=5700
=>\(100x+100\cdot\frac{101}{2}=5700\)
=>x+50,5=57
=>x=57-50,5
=>x=6,5
a) \(4\left(x+41\right)=400\)
\(\Rightarrow x+41=400:4\)
\(\Rightarrow x+41=100\)
\(\Rightarrow x=100-41\)
\(\Rightarrow x=59\)
a/ \(4.\left(x+41\right)=400\)
\(x+41=\dfrac{400}{4}=100\)
\(\Rightarrow x=59\)
b/ \(4.\left(x-3\right)=7^2-1^{10}\)
\(4.\left(x-3\right)=49-1\)
\(4.\left(x-3\right)=48\)
\(x-3=\dfrac{48}{3}=16\)
\(\Rightarrow x=19\)
#AEZn8
a ) 4 . ( x + 41 ) = 400
x + 41 = 400 : 4
x + 41 = 100
x = 100 - 41
x = 59
b ) 4 . ( x - 3 ) = 72- 110
4 . ( x - 3 ) = 49 - 1
4 . ( x - 3 ) = 48
x - 3 = 48 : 4
x - 3 = 12
x = 12 + 3
x = 15