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a) 219 - 7(x + 1) = 100 <=> 7(x+1) = 219 - 100
<=> 7(x+1) = 119 <=> x + 1 = 119 : 7 <=> x + 1 = 17
b) (3x - 6).3 = 3434 <=> 3x - 6 = 3434 : 3 <=> 3x - 6 = 3333
<=> 3x = 27 + 6 <=> 3x = 33 <=> x = 11
a) 219−7(x+1)=100
- 7(x+ 1)= 100 - 219
- 7(x+ 1)= - 119
x+1 = -119 : (-7)
x+1 = 17
x= 17-1
x= 16
b) (3x - 6). 3 = 34
(3x - 6). 3 = 81
(3x - 6)= 81: 3
(3x - 6)= 27
3x= 27+ 6
3x= 33
x= 33:3
x= 11
b) (3x−6).3=34
219 - 7 . ( x+1) = 100
7 . ( x + 1 ) = 219 - 100 = 119
x+ 1= 119:7= 17
x = 17-1=16
(3x - 6 ). 3100 = 3103 2018x-3 = 2018
3x - 6 = 3103 : 3100 2018x-3 = 20181
3x - 6 = 33 =27 Do x-3=1 cho nên suy ra x=4
3x = 27 + 6
3x = 33
x = 33:3
x = 11
a: =>3/2x=5/6
hay x=5/6:3/2=5/6x2/3=10/18=5/9
b: \(\Leftrightarrow219\cdot1-7\left(x+1\right)=100\)
=>7(x+1)=119
=>x+1=17
hay x=16
\(\left|x+5\right|=5\)
<=> \(\hept{\begin{cases}x+5=5\\x+5=-5\end{cases}}\)
<=> \(\hept{\begin{cases}x=0\\x=-10\end{cases}}\)
\(\left|x+1\right|+7=10\)
<=> \(\left|x+1\right|=3\)
<=> \(\hept{\begin{cases}x+1=3\\x+1=-3\end{cases}}\)
<=> \(\hept{\begin{cases}x=2\\x=-4\end{cases}}\)
\(\left|x-3\right|-6=5\)
<=> \(\left|x-3\right|=11\)
<=> \(\hept{\begin{cases}x-3=11\\x-3=-11\end{cases}}\)
<=> \(\hept{\begin{cases}x=14\\x=-8\end{cases}}\)
\(\left|x+2\right|-6\left(x-4\right)=20-6x\)
<=> \(\left|x+2\right|-6x+24=20-6x\)
<=> \(\left|x+2\right|=-4\)
<=> \(\hept{\begin{cases}x+2=-4\\x+2=4\end{cases}}\)
<=> \(\hept{\begin{cases}x=-2\\x=2\end{cases}}\)
a) \(|x+5|=5\)
\(\Rightarrow\orbr{\begin{cases}x+5=5\\x+5=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)
Vậy x = 0 hoặc x = -10
b) \(|x+1|+7=10\)
\(\Rightarrow|x+1|=10-7\)
\(\Rightarrow|x+1|=3\)
\(\Rightarrow\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)
Vậy x = 2 hoặc x = -4
c) \(|x-3|-6=5\)
\(\Rightarrow|x-3|=5+6\)
\(\Rightarrow|x-3|=11\)
\(\Rightarrow\orbr{\begin{cases}x-3=11\\x-3=-11\end{cases}}\Rightarrow\orbr{\begin{cases}x=14\\x=-8\end{cases}}\)
Vậy x = 14 hoặc x = -8
d) \(|x+2|-6\left(x-4\right)=20-6x\)
\(\Rightarrow|x+2|-6x+24=20-6x\)
\(\Rightarrow|x+2|=20-6x-24+6x\)
\(\Rightarrow|x+2|=\left(20-24\right)+\left(-6x+6x\right)\)
\(\Rightarrow|x+2|=-4\)
Vì \(|x|\ge0\)mà \(|x+2|=-4\)
\(\Rightarrow\)Không có giá trị x thỏa mãn
_Chúc bạn học tốt_
a, 45 chia hết cho x
=> x thuộc Ư(45)
=> x thuộc {1;45;3;15;5;9}
vậy...
b, x chia hết cho 12
=> x thuộc B(12)
=> x thuộc {0;12;24;36;48;60;...}
vậy.....
c, 219-7.(x+1)=100
7.(x+1)=219-100
7.(x+1)=119
x+1 = 17
x = 17-1
x = 16 vậy...
a, 45 \(⋮\)x \(\Rightarrow\)x\(\in\)Ư ( 45 ) = { \(\pm\)1;\(\pm\)3;\(\pm\)5;\(\pm\)9;\(\pm\)15;\(\pm\)45}
b, \(x⋮12\Rightarrow x\in B\left(12\right)=\left\{0;12;24;36;48....\right\}\)
\(c,219-7\left(x+1\right)=100\)
\(\Rightarrow7\left(x+1\right)=219-100\)
\(\Rightarrow7\left(x+1\right)=119\)
\(\Rightarrow x+1=119:7\)
\(\Rightarrow x+1=17\)
\(\Rightarrow x=16\)
Câu 1a:
75% - 1 1/2 + 0,5 : 5/12 - (-1/2)^2
= 0,75 - 1,5 + 0,5 x 12/5 - 0,25
= (0,75 - 0,25) - 1,5 + 1,2
= 0,5 - 1,5 + 1,2
= - 1 + 1,2
= 0,2
Bài 1b:
(5/7.0,6 - 5: 3 1/2). (40% - 1,4).(-2)^3
= (3/7 - 5 x 2/7).(0,4 - 1,4).8
= - 1.(-1).8
= 8
a, 219 - 7.(x + 1) = 100
7.(x + 1) = 219 - 100
7.(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
a, 219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1=119/7
x+1=17
x=17-1
x=16
Vậy x=16
b, 20+23(x+3)=52.4
20+8(x+3)=100
8(x+3)=100-20
8(x+3)=80
x+3=80/8
x+3=10
x=10-3
x=7
Vậy x=7
a) 219 - 7(x + 1) = 100
=> 7(x + 1) = 119
=> x + 1 = 17
=> x = 16
a) \(219-7\left(x+1\right)=100\)
\(7\left(x+1\right)=219-100\)
\(7\left(x+1\right)=119\)
\(x+1=17\)
\(x=16\)
b) \(20+2^3\left(x+3\right)=5^2\cdot4\)
\(20+8\left(x+3\right)=25\cdot4\)
\(20+8\left(x+3\right)=100\)
\(8\left(x+3\right)=80\)
\(x+3=10\)
\(x=7\)
\(7.\left(x+1\right)=219-100\)
\(7.\left(x+1\right)=119\)
\(x+1=199:7\)
\(x+1=\frac{199}{7}\)
\(x=\frac{199}{7}-1=\frac{192}{7}\)
a) Ta có \(219-7.\left(x+1\right)=100\)
\(\Rightarrow7.\left(x+1\right)=219-100\)
\(\Rightarrow7.\left(x+1\right)=119\)
\(\Rightarrow x+1=17\)
\(\Rightarrow x=16\)
b,Ta có \(20+2^3.\left(x+3\right)=5^2.4\)
\(\Rightarrow20+8.\left(x+3\right)=25.4\)
\(\Rightarrow20+8.\left(x+3\right)=100\)
\(\Rightarrow8.\left(x+3\right)=80\)
\(\Rightarrow x+3=10\)
\(\Rightarrow x=7\)
a) 219 - 7(x+1) = 100
219 - (7x+7) = 100 =) 7x+7 = 219 - 100 =) 7x+7 = 119 =) 7x = 119 - 7 =) 7x = 112 =) x = 112 ; 7 =) x = 16
b) 20 + 23 ( x + 3 ) = 52 . 4 =) 20 + 8 ( x + 3 ) = 25 . 4 =) 20 + (8x + 24) = 100 =) 8x + 24 = 100 - 20 =) 8x + 24= 80 =) 8x = 80 - 24
=) 8x = 56 =) x = 56 : 8 =) x = 7
\(219-7.\left(x+1\right)=100\)
\(219-7x-7=100\)
\(212-7x=100\)
\(7x=212-100\)
\(7x=112\)
\(x=\frac{112}{7}=16\)
Vậy \(x=16\)
\(20+2^3.\left(x+3\right)=5^2.4\)
\(20+8x+24=25.4\)
\(8x=100-44\)
\(8x=56\)
\(x=\frac{56}{7}=7\)
Vậy \(x=7\)
Tham khảo nhé~
b, 20 + 23. ( x + 3) = 52. 4
20 + 8.(x + 3) = 25 . 4
20 + 8 . ( x + 3) = 100
8 .(x + 3) = 100 - 20
8. (x + 3) = 80
x + 3 = 80 : 8
x + 3 = 10
x = 10 - 3
x = 7
a) 219-7.(x+1)=100
=> 219-100 = 7.(x+1)
=> 7(x+1) = 119
=> x+1 =119:7
=> x+1 = 17
=> x = 17-1
=> x = 16
b)20+23(x+3)=52.4
=> 20+8(x+3) = 25.4
=>20+8(x+3) =100
=> 8(x+3) =100-20
=> 8(x+3) = 80
=> x+3 =80:8
=> x+3 =10
=> x =10-3
=> x = 7
a) x =16
b) x= 7
a)7.(x+1)=219-100
7.(x+1)=119
x+1=119:7
x+1=17
x =17-1
x =16
b)20+8.(x+3)=25.4
20+8.(x+3)=100
8.(x+3)=100-20
8.(x+3)=80
x+3 =80:8
x+3 =10
x =10-3
x = 7
EZ mà hi hi