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\(b,\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{1}{7}\)
\(\dfrac{1}{5}:x=\dfrac{7}{35}-\dfrac{5}{35}\)
\(\dfrac{1}{5}:x=\dfrac{2}{35}\)
\(x=\dfrac{1}{5}:\dfrac{2}{35}\)
\(x=\dfrac{1}{5}.\dfrac{35}{2}\)
\(x=\dfrac{7}{2}\)
<=>\(x+x-\frac{25x}{100}-\frac{25}{100}=60\)
<=>\(2x-\frac{50x}{100}=60\)
<=>\(\frac{150x}{100}=60\)
<=> 150x=6000
<=> x=40
giải lun nha
x-(4x/8+1x/8)=45/4
x-5x/8=45/4
-4x=45/4.8
-4x=90
x=90/(-4)
x=22,5
nếu đúng thì cho mk **** nha mk đang cần
\(x-\left(\frac{50x}{100}+\frac{25x}{100}\right)=\frac{45}{4}\)
\(x-\left(\frac{50x+25x}{100}\right)=\frac{45}{4}\)
\(x-\frac{75x}{100}=\frac{45}{4}\)
\(x-x\times\frac{3}{4}=\frac{45}{4}\)
\(x\times\left(1-\frac{3}{4}\right)=\frac{45}{4}\)
\(x\times\frac{1}{4}=\frac{45}{4}\)
\(x=\frac{45}{4}\div\frac{1}{4}\)
\(x=45\)
\(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(x-\left(\frac{100x}{200}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(x-\left(\frac{100x+25x}{200}\right)=\frac{45}{4}\)
\(x-\frac{125x}{200}=\frac{45}{4}\)
\(x-x\frac{5}{8}=\frac{45}{4}\)
\(x\left(1-\frac{5}{8}\right)=\frac{45}{4}\)
\(x.\frac{3}{8}=\frac{45}{4}\)
\(x\)=\(\frac{45}{4}:\frac{3}{8}\)
\(x\)=\(30\)
a) x-\(\left(\frac{50x}{100}+\frac{25x}{200}\right)\)=\(11\frac{1}{4}\)
<=>x - \(\frac{1}{2}x-\frac{1}{8}x\)=\(\frac{11.4+1}{4}\)
<=>\(\frac{3}{8}x=\frac{45}{4}\)
<=>x=\(\frac{45}{4}:\frac{3}{8}\)
<=>x=30
Vậy x=30
1) \(x+\dfrac{30}{100}x=-1,31\)
\(\Leftrightarrow x+\dfrac{3}{10}x=-\dfrac{131}{100}\)
\(\Leftrightarrow100x+30x=-131\)
\(\Leftrightarrow130x=-131\)
\(\Leftrightarrow x=-\dfrac{131}{130}\)
Vậy \(x=-\dfrac{131}{130}\)
b) \(\left(4,5-2x\right)\cdot\left(-1\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow\left(\dfrac{9}{2}-2x\right)\cdot\left(-\dfrac{4}{7}\right)=\dfrac{11}{4}\)
\(\Leftrightarrow-\dfrac{18}{7}+\dfrac{8}{7}x=\dfrac{11}{4}\)
\(\Leftrightarrow-72+32x=77\)
\(\Leftrightarrow32x=77+72\)
\(\Leftrightarrow32x=149\)
\(\Leftrightarrow x=\dfrac{149}{32}\)
Vậy \(x=\dfrac{149}{32}\)
\(A=1+2+3+4+5+....+99+100\)
\(A=100(100+1):2=5050\)
\(B=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+.....+\dfrac{1}{9900}\)
\(B=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+.....+\dfrac{1}{99.100}\)
\(B=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+....+\dfrac{1}{99}-\dfrac{1}{100}\)
\(B=1-\dfrac{1}{100}=\dfrac{99}{100}\)
a: =>3/2x=5/6
hay x=5/6:3/2=5/6x2/3=10/18=5/9
b: \(\Leftrightarrow219\cdot1-7\left(x+1\right)=100\)
=>7(x+1)=119
=>x+1=17
hay x=16
x-(60-x)=25x/100+25x/100
x-60+x=25x+25x/100
x-60+x=x(25+25)/100
x-60+x=x.50/100
x-60+x=x.50/50.2
x-60+x=x/2
.....
tới đây thui, mình ko biết làm nữa
ko biết là đúng hay sai đâu nhoa