a) x : ( -2,14) = (-3,12) :1,2

x : ( -2,14) = -2,6

x = -2,6 x ( -2,14)

x = 5,564

Vậy x = 5,564

b)\(2\dfrac{2}{3}\) : x = \(2\dfrac{1}{12}\) : ( -0,06)

\(2\dfrac{2}{3}\) : x = \(-\dfrac{625}{18}\)

x = \(2\dfrac{2}{3}\) : \(-\dfrac{625}{18}\)

x =

x = -0,0768

Vậy x = -0,0768

( Mình bấm nhầm, bổ sung nha)

Cứ linh tinh đấy thì sao

X x 4 +119=235

=> x . (-2,14) = -2,6

=> x = 2,6/2,14

a) x : (-2,14) = (-3,12) : 1,2

=> x:(-2,14)= -2,6

=> x= -5,564

b) \(2\frac{2}{3}:x=2\frac{1}{12}:\left(-0,060\right)\)

=> \(\frac{8}{3}:x=\frac{-625}{18}\)

=> x= \(\frac{8}{3}:\frac{-625}{18}\)

=> x= \(\frac{-48}{625}\)

c) \(x:\left(-2,14\right)=\left(-3,12\right):1,2\)

=> \(x:\left(-2,14\right)=-2,6\)

=> \(x=\left(-2,6\right).\left(-2,14\right)\)

=> \(x=5,564\)

Vậy \(x=5,564.\)

d) \(2\frac{2}{3}:x=2\frac{1}{2}:\left(-0,06\right)\)

=> \(\frac{8}{3}:x=\frac{25}{12}:\left(-\frac{3}{50}\right)\)

=> \(\frac{8}{3}:x=-\frac{625}{18}\)

=> \(x=\frac{8}{3}:\left(-\frac{625}{18}\right)\)

=> \(x=-\frac{48}{625}\)

Vậy \(x=-\frac{48}{625}.\)

Chúc bạn học tốt!

ủa còn a với b đâu bn???

Bài 1a:

\(\frac{4,6}{1,4}\) = \(\frac{11,5}{5x}\)

4,6 x 5\(x\) = 11,5 x 1,4

23\(x\) = 16,1

\(x\) = 16,1 : 23

\(x\) = 0,7

Vậy \(x\) = 0,7

Bài 1b:

\(\frac{x^2}{6}\) = \(\frac{24}{25}\)

25\(x^2\) = 24.6

25\(x^2\) = 144

\(x^2\) = 144/25

\(x\) = - 12/5 hoặc \(x\) = 12/5

Vậy \(x\) ∈ {-12/5; 12/5}

Bài 1c:

\(\frac{x+2}{2}\) = \(\frac{1}{1-x}\)

(\(x\) + 2)(1 - \(x\)) = 1.2

\(x\) - \(x^2\) + 2 - 2\(x\) = 2

\(x^2\) + (2\(x\) - \(x\)) + 2 - 2 = 0

\(x^2\) + \(x\) + 0 = 0

\(x\)(\(x\) + 1) = 0

\(x\) = 0

\(x\) + 1 = 0

\(x\) = - 1

Vậy \(x\) ∈ {-1; 0}

x: (-2,14) = -8/3

x= (-8/3)x (-2,14)

x=428/75

\(\frac{428}{75}\)

Bài 2: 

a: =>x/4=1/8

hay x=1/2

b: \(\Leftrightarrow\dfrac{x}{-5}=\dfrac{11}{6}\)

hay x=-55/6

c: \(\Leftrightarrow\dfrac{-3.5}{x}=\dfrac{4.25}{8}\)

hay x=-112/17

\(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)

\(\Leftrightarrow x^2+4x-x-4=x^2+3x-2x-6\)

\(\Leftrightarrow x^2+4x-x-4-x^2-3x+2x+6=0\)

\(\Leftrightarrow2x+2=0\)

\(\Leftrightarrow2x=-2\)

\(\Leftrightarrow x=-1\)VẬY X=-1 LÀ NGHIỆM CỦA PHƯƠNG TRÌNH \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

Ta có : \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)

\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)

\(\Rightarrow x^2+4x-x-4=x^2+3x-2x-6\)

\(\Rightarrow3x-4=x+6\)

\(\Rightarrow3x-x=-4+6\)

\(\Rightarrow2x=-2\)

\(\Rightarrow x=-1\)