Bài1

a. x=1/4+-2/13; x/-3=-2/3+1/7; x=7/-25+1/5

x = 1/4 + (-2/13)

x = 1/4 - 2/13

x = 13/52 - 8/52

x = 5/52

Vậy x = 5/52

x/-3 = -2/3 + 1/7

x/-3 = - 14/21 + 3/21

x/-3 = - 11/21

x = - 11/21 x (-3)

x = 11/7

Vậy x = 11/7

x=7/-25+1/5

x = - 7/25 + 5/25

x = - 2/25

Vậy x = - 2/25

Bài 1:

b. x=5/11+4/-9;5 /9+x/-1=-1/3; x+7/12=7/18-1/8

x = 5/11 + 4/-9

x = 5/11 - 4/9

x = 45/99 - 44/99

x = 1/99

Vậy x = 1/99

5 /9+x/-1=-1/3

x/-1 = - 1/3 - 5/9

-x = - 3/9 - 5/9

- x = - 8/9

x = - 8/9 : (-1)

x = 8/9

Vậy x = 8/9

x+7/12=7/18-1/8

x + 7/12 = 28/72 - 9/72

x + 7/12 = 19/72

x = 19/72 - 7/12

x = - 23/72

Vậy x = - 23/72

\(a,x-\frac{1}{9}=\frac{8}{3}\Rightarrow x=\frac{8}{3}+\frac{1}{9}=\frac{24}{9}+\frac{1}{9}=\frac{25}{9}\)

\(b,\frac{-x}{4}=\frac{-9}{x}\Leftrightarrow\frac{x}{-4}=\frac{-9}{x}\Leftrightarrow x.x=\left(-4\right).\left(-9\right)\Rightarrow x^2=36=6^2=\left(-6\right)^2\Rightarrow x=6;-6\)

\(c,\frac{x}{4}=\frac{18}{x+1}\Leftrightarrow x.\left(x+1\right)=4.18=x.\left(x+1\right)=72\Rightarrow8.\left(8+1\right)=72\Rightarrow x=8\)

25/9-1/9=8/3

-9/4=-9/4

8/4=18/18+1

duyệt đi

Quy đồng mẫu số các phân số: 9/72 ; 4x/72 ; 3y/72 ; 16/72.

=> 9<4x<3y<16. Vậy x=3;y=5

\(A=\frac{4+x}{x+3}=\frac{x+3+1}{x+3}=1+\frac{1}{x+3}\)(x\(\ne\)-3)

de A thuoc Z ma x thuoc Z \(\Leftrightarrow x+3\in\)Ư(3)={1;-1;3;-3}

ta co bang

vay de A thuoc Z khi x \(\in\){-2;-4;0;-6}

co \(|^{ }_{ }x+1|^{ }_{ }\ge0\)voi moi x

\(\Rightarrow|^{ }_{ }x+1|^{ }_{ }-2\ge-2\)hay B \(\ge\)-2

dau "=" xay ra khi x+1=0\(\Leftrightarrow\)x=-1

vay voi x=-1 thi B dat gia tri nho nhat la -2

a, => |15-x| = 2+3

=> |15-x| = 5

=> 15-x = -5 hoặc 15-x = 5

=> x = 10 hoặc x = 10

Vậy ......

Tk mk nha

a/|15-x|=|-2|+|-3|

=>|15-x|=2+3=5

=>\(15-x=\hept{\begin{cases}5\\-5\end{cases}}\)

=>\(x=\hept{\begin{cases}10\\15\end{cases}}\)

.........

k nha , thanks

(x²-4)(x²-16)=0

<=>x²-4=0<=>x²=4<=>x E {-2;2}

hoặc x²-16=0<=>x²=16<=>x E {-4;4}

vậy x E {-4;-2;2;4}

\(\frac{5}{n+1}=\frac{n+1}{5}\)

\(\Leftrightarrow\left(n+1\right)^2=5^2\)

\(\Leftrightarrow\sqrt{\left(n+1\right)^2}=\sqrt{5^2}\)

\(\Leftrightarrow n+1=5\)

\(\Leftrightarrow n=5-1\)

\(\Leftrightarrow n=4\)

\(\frac{2x+1}{5}=\frac{x+2}{8}\)

\(\Leftrightarrow8\left(2x+1\right)=5\left(x+2\right)\)

\(\Leftrightarrow16x+8=5x+10\)

\(\Leftrightarrow11x=2\)

\(\Leftrightarrow x=\frac{2}{11}\)

c)\(\Leftrightarrow\)(x+1)+2 chia hết  x+1
\(\Rightarrow\)2 chia hết x+1
\(\Rightarrow\)x+1 ∈ {1,-1,2,-2}
\(\Rightarrow\)x ∈ {0,-2,1,-3}

c) \(x+3⋮x+1\)

\(\Rightarrow x+1+2⋮x+1\)

\(\Rightarrow2⋮x+1\) ( vì \(x+1⋮x+1\) )

\(\Rightarrow x+1\in\text{Ư}_{\left(2\right)}\)

\(\text{Ư}_{\left(2\right)}=\text{ }\left\{1;-1;2;-2\right\}\)

vậy................

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