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a)x/5=32/80
=>80x=32*5
x=160/8
x=20
b)13/x=26/30
=>26x=13*30
x=390/26
x=15
c)-x/7=22/-77
=>(-x)*(-77)=22*7
x*77=154
x=154/77
x=2
a: x/5=32/80
nên x/5=2/5
hay x=2
13/x=26/30
nên 13/x=13/15
hay x=15
-x/7=22/-77
=>x/7=2/7
hay x=2
b: x/9=28/36
=>x/9=7/9
hay x=7
-10/x=50/55
=>-10/x=10/11
hay x=-11
a)
1) x/5 = 32/80
\(x : 5 = 32 : 80\) \(x = 5 \cdot \frac{32}{80}\) \(x = 5 \cdot \frac{2}{5}\) \(x = 2\)
2) 13/x = 26/30
\(13 : x = 26 : 30\) \(13 \cdot 30 = x \cdot 26\) \(390 = 26 x\) \(x = 390 : 26\) \(x = 15\)
3) -x/7 = 22/(-77)
\(- x : 7 = 22 : \left(\right. - 77 \left.\right)\) \(- x = 7 \cdot \frac{22}{- 77}\) \(- x = 7 \cdot \left(\right. - \frac{2}{7} \left.\right)\) \(- x = - 2\) \(x = 2\)
b)
1) x/9 = 28/36
\(x : 9 = 28 : 36\) \(x = 9 \cdot \frac{28}{36}\) \(x = 9 \cdot \frac{7}{9}\) \(x = 7\)
2) -10/x = 50/55
\(- 10 : x = 50 : 55\) \(- 10 \cdot 55 = 50 x\) \(- 550 = 50 x\) \(x = - 550 : 50\) \(x = - 11\)
3) 23/(-x) = 46/50
\(23 : \left(\right. - x \left.\right) = 46 : 50\) \(23 \cdot 50 = 46 \left(\right. - x \left.\right)\) \(1150 = - 46 x\) \(x = 1150 : \left(\right. - 46 \left.\right)\) \(x = - 25\)
✅ Kết quả cuối cùng
a)
- x = 2
- x = 15
- x = 2
b)
- x = 7
- x = -11
- x = -25
\(\frac{-3}{14}\) - \(\frac{5}{-14}\)
= \(\frac{-3}{14}+\frac{5}{14}\)
= \(\frac{2}{14}\)
= \(\frac17\)
- \(\frac54\) - \(\frac34\)
= -(\(\frac54+\frac34\))
= - \(\frac84\)
= - 2
\(\frac{15}{6}-\frac{-10}{20}\)
= \(\frac52\) + \(\frac12\)
= \(\frac62\)
= 3
\(\frac{26}{-35}\) - \(\frac{6}{35}\)
= - (\(\frac{26}{35}\) + \(\frac{6}{35}\))
=- \(\frac{32}{35}\)
a. Ta có 333/444 = 333:111/444:111=3/4
tick đi mình làm tiếp cho
a)11 3/13-(2 4/7+5 3/13)=11+3/13-(2+4/7+5+3/13)=11+3/13-2-4/7-5-3/13=(11-2-5)+(3/13-4/7-3/13)=4+(0-4/7)=4+-4/7=28/7-4/7=28-4/7=24/7=3 3/7(phải tính ta hỗn số nha bn)
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\(\text{}\text{}11\frac{3}{13}-\left(2\frac{4}{7}+5\frac{3}{13}\right)=11\frac{3}{13}-2\frac{4}{7}-5\frac{3}{13}=11\frac{3}{13}-5\frac{3}{13}-2\frac{4}{7}=6-2\frac{4}{7}=5\frac{7}{7}-2\frac{4}{7}=3\frac{3}{7}\)
1/21+1/28+1/36+...+2/[x.(x+1)]=2/9
=>2/42+2/56+2/72+...+2/[x.(x+1)]=2/9
=>2.(1/42+1/56+1/72+...+1/[x.(x+1)])=2/9
=>2.(1/6-1/7+1/7-1/8+1/8-1/9+...+1/x-1/(x+1))=2/9
=>1/6-1/(x+1)=1/9
=>1/(x+1)=1/18
=>x+1=18
=>x=17
Đặt \(A=\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x.\left(x+1\right)}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{21.2}+\frac{1}{28.2}+\frac{1}{36.2}...+\frac{2}{x.\left(x+1\right).2}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{x\left(x+1\right)}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{6.4}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x\left(x+1\right)}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+1}\)
\(\Rightarrow\frac{1}{2}A=\frac{1}{6}-\frac{1}{x+1}\)
\(\Rightarrow A=\left(\frac{1}{6}-\frac{1}{x+1}\right):\frac{1}{2}\)
Theo bài ra ta có :
\(\left(\frac{1}{6}-\frac{1}{x+1}\right):\frac{1}{2}=\frac{2}{9}\)
\(\Rightarrow\frac{1}{6}-\frac{1}{x+1}=\frac{2}{9}.\frac{1}{2}\)
\(\frac{1}{6}-\frac{1}{x+1}=\frac{2}{18}\)
\(\frac{1}{x+1}=\frac{1}{6}-\frac{2}{18}\)
\(\frac{1}{x+1}=\frac{3}{18}-\frac{2}{18}\)
\(\frac{1}{x+1}=\frac{1}{18}\)
\(\Rightarrow x+1=18\)
\(\Rightarrow x=18-1\)
\(\Rightarrow x=17\)
Vậy x = 17