A/ \(\frac{4}{5}+\frac{1}{5}x=\left(-\frac{1}{28}\right)\)

\(\frac{1}{5}x=\left(-\frac{1}{28}\right)-\frac{4}{5}\)

\(\frac{1}{5}x=\left(-\frac{5}{140}\right)-\frac{112}{140}\)

\(\frac{1}{5}x=-\frac{117}{140}\)

\(x=\left(-\frac{117}{140}\right):\frac{1}{5}\)

\(x=\left(-\frac{117}{28}\right)\)

B/ \(\left(\frac{3x}{7}+1\right):\left(-4\right)=-\frac{1}{28}\)

\(\frac{3x}{7}+1=\left(-\frac{1}{28}\right).\left(-4\right)\)

\(\frac{3x}{7}+1=\frac{1}{7}\)

\(\frac{3x}{7}=\frac{1}{7}-1\)

\(\frac{3x}{7}=\frac{1}{7}-\frac{7}{7}\)

\(\frac{3x}{7}=-\frac{6}{7}\)

\(\Rightarrow3x=\left(-6\right)\)(theo cách l8)

\(\Rightarrow x=\left(-6\right):3=\left(-2\right)\)

a)   X=-117/28

b)   X=-4

Chưa chắc đã đúng nha bạn

a. \(\frac{4}{5}+\frac{1}{5}x=\frac{1}{28}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{1}{28}-\frac{4}{5}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{5}{140}-\frac{112}{140}\)

\(\Leftrightarrow\frac{1}{5}x=\frac{-107}{140}\)

\(\Leftrightarrow x=\frac{-107}{140}\div\frac{1}{5}\)

\(\Leftrightarrow x=\frac{-107}{140}\times5\)

\(\Leftrightarrow x=\frac{-107}{28}=\)

b. \(\left(\frac{3x}{7}+1\right)\div\left(-4\right)=\frac{-1}{28}\)

\(\Leftrightarrow\left(\frac{3x}{7}+\frac{7}{7}\right)=\frac{-1}{28}\times\left(-4\right)\)

\(\Leftrightarrow\frac{3x+1}{7}=\frac{1}{7}\)

\(\Leftrightarrow3x+1=1\)

\(\Leftrightarrow3x=1-1\)

\(\Leftrightarrow3x=0\Leftrightarrow x=0\)

1.a)x=-21

b)x=87

c)x=20,5

Bài 2: 

x = (-2)

y = 3

1 / Tìm x thuộc Z biết :

a) x-(-7-9) = 0

x + 7 + 9 = 0

x = - 7 - 9

x = - 16

Vậy x = - 16

b) x-2x-3=5-(-7)

x - 2x = 5 + 7 + 3

- x = 12 + 3

- x = 15

x = 15 : (-1)

x = - 15

Vậy x = -15

1 / Tìm x thuộc Z biết :

c) |x-7| = 5

x - 7 = - 5 hoặc x - 7 = 5

TH1; x - 7 = - 5

x = - 5 + 7

x = 2

Th2: x - 7 = 5

Vậy x = 5 + 7

x = 12

Vậy x ∈ {2; 12}

d)3x - |x|=24

|x| = 3x - 24

Vì |x| ≥ 0 nên 3x - 24 ≥ 0 suy ra 3x ≥ 24 suy ra x ≥ 8

Với x ≥ 8 ta có:

|x| = 3x - 24

x = - 3x + 24 hoặc x = 3x - 24

TH1: x = -3x + 24

x + 3x = 24

4x = 24

x = 24 : 4

x = 6 (loại)

TH2: x = 3x - 24

3x - x = 24

2x = 24

x = 24 : 2

x = 12

Vậy x = 12

1a) \(\frac{x-3}{x+7}=\frac{-5}{-6}\)

=> \(\frac{x-3}{x+7}=\frac{5}{6}\)

=> (x - 3).6 = 5.(x + 7)

=> 6x - 18 = 5x + 35

=> 6x - 5x = 35 + 18

=> x = 53

b) \(\frac{x-7}{x+3}=\frac{4}{3}\)

=> (x - 7). 3 = (x + 3). 4

=> 3x - 21 = 4x + 12

=> 3x - 4x = 12 + 21

=> -x = 33

=> x = -33

c) \(\frac{x-10}{6}=-\frac{5}{18}\)

=> (x - 10) . 18 = -5 . 6

=> 18x - 180 = -30

=> 18x = -30 + 180

=> 18x = 150

=> x = 150 : 18 = 25/3

d) \(\frac{x-2}{4}=\frac{25}{x-2}\)

=> (x - 2)(x - 2) = 25 . 4

=> (x - 2)² = 100

=> (x - 2)² = 10²

=> \(\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}}\)

=> \(\orbr{\begin{cases}x=12\\x=-8\end{cases}}\)

e) \(\frac{7}{x}=\frac{x}{28}\)

=> 7 . 28 = x . x

=> 196 = x²

=> x² = 14²

=> \(\orbr{\begin{cases}x=14\\x=-14\end{cases}}\)

f) \(\frac{40+x}{77-x}=\frac{6}{7}\)

=> (40 + x) . 7 = (77 - x).6

=> 280 + 7x = 462 - 6x

=> 280 - 462 = -6x + 7x

=> -182 = x

=> x = -182

a, 28+2x=35-(-13)

=> 2x=35+13-28

=>2x=20

=> x=10. vậy x=10

chúc bn hok tốt k cho mik nha

\(a,2.\left(x-5\right)-3.\left(x+7\right)=14\)

            \(2x-10-3x-21=14\)

                                 \(-x-31=14\)

                                                \(x=-31-14\)

                                                \(x=-45\)

\(b,5.\left(x-6\right)-2\left(x+3\right)=12\)

             \(5x-30-2x-6=12\)

                                \(3x-36=12\)

                                           \(3x=12+36\)

                                           \(3x=48\)

                                              \(x=16\)

\(c,-5.\left(2-x\right)+4.\left(x-3\right)=10.x-15\)

              \(-10+5x+4x-12=10x-15\)

                                    \(-6x-22=10x-15\)

                                  \(-6x-10x=-15+22\)

                                             \(-16x=7\)

                                                      \(x=-\frac{7}{16}\)

Câu d , e f tương tự nha

bạn làm rất   đúng ,cảm ơn bn nhìu