Nhìu thế

Câu a:

7.(\(x-4\)) = \(7^4:7^3\)

7.(\(x-4\) )=7

(\(x-4\) )=7 : 7

(\(x-4\) )=1

\(x\) = 1+4

\(x\) = 5

Vậy \(x=5\)

Bài 1 tự làm!

Bài 2:

a, \(\left(3x-4\right)\left(x-1\right)^3=0\Rightarrow\left[{}\begin{matrix}3x-4=0\\\left(x-1\right)^3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=1\end{matrix}\right.\)

b, \(2^{2x-1}:4=8^3\Rightarrow2^{2x-1}:2^2=2^9\)

\(\Rightarrow2x-1-2=9\Rightarrow2x-3=9\Rightarrow2x-12\Rightarrow x=6\)

c, Đề chưa rõ

d, \(\left(x+2\right)^5=2^{10}\Rightarrow\left(x+2\right)^5=4^5\Rightarrow x+2=4\Rightarrow x=2\)

e, \(\left(3x-2^4\right).7^3=2.7^4\Rightarrow3x-2^4=2.7^4:7^3\Rightarrow3x-16=2.7=14\)

\(\Rightarrow3x=14+16=30\Rightarrow x=\dfrac{30}{3}=10\)

f, \(\left(x+1\right)^2=\left(x+1\right)^0\Rightarrow\left(x+1\right)^2=1\) (vì x⁰ = 1)

\(\Rightarrow x+1=1\Rightarrow x=0\)

Làm phần c nè!

c, \(\left(x-5\right)^4=\left(x-5\right)^6\Rightarrow\left(x-5\right)^4-\left(x-5\right)^6=0\)

\(\Rightarrow\left(x-5\right)^4.\left(x-5\right)^2=0\)

\(\Rightarrow x-5=0\Rightarrow x=5\)

c/ 2x - 1 = \(5^{98}:5^{96}\)

2x - 1 = \(5^2\) = 25

2x = 25 + 1 = 26

x = 26 : 2

x = 13

d/ 7x + 3 = \(3^5.2^3.9\)

7x + 3 = \(3^5.3^2.8=3^7.8=2187.8\)

7x + 3 = \(17496\)

7x = 17496 - 3 = 17493

x = 17493 : 7

x = 2499

e/\(2^{2x+6}=1\)

\(2^{2x+6}=2^0\)

2x + 6 = 0

2x = 0 - 6 = - 6

x = - 6 : 2

x = - 3

j/ \(2^x=8\)

\(2^x=2^3\)

x = 3

g/ \(2^x:2^3=16\)

\(2^{x-3}=2^4\)

x - 3 = 4

x = 4 + 3

x = 7

h/ \(2^x+2^{x+1}+2^{x+2}=56\)

\(2^x\left(1+2+2^2\right)\) = 56

\(2^x.7=56\)

\(2^x=56:7\)

\(2^x=8\)

\(2^x=2^3\)

x = 3

Bài a, b thiên phong giải r, mk chỉ làm những bài còn lại thôi. Chúc bạn học tốt!!!

a, \(x+2^3=5^2\Rightarrow x+8=25\Rightarrow x=17\)

b, \(2x+3=7^2\Rightarrow2x+3=49\Rightarrow x=\dfrac{49-3}{2}=23\)

Còn lại tự làm.

 x²³:216=x¹⁵.x⁵

x²³: 6³= x²⁰

==> 6³=x²³:x²⁰

==> 6³=x³

==> x=6

(5^x.5^x+2):5³=125

==> 5^2x+2:5³=5³

==> 5^2x+2=5³.5³

==> 5^2x+2=5⁶

==> 2x+2=6

2x=6–2

2x=4

x=4:2

x=2

(3^x.3^x+4):3³=243

==> 3^2x+4:3³=3⁵

3^2x+4=3⁵.3³

3^2x+4=3⁸

==> 2x+4=8

2x=8–4

2x=4

x=4:2

x=2

3^x+3^x+1+3^x+2=243

3^x.1+3^x.3¹+3^x.3²=243

3^x.(1+3¹+3²)=243

3^x. (1+3+9)=243

3^x.13=243

3^x=243:13

3^x=...

a)

\(\dfrac{7}{5}+\dfrac{5}{6}:5-\dfrac{3}{8}\cdot\left(-3\right)\\ =\dfrac{7}{5}+\dfrac{1}{6}+\dfrac{9}{8}\\ =\dfrac{168+20+135}{120}\\ =\dfrac{323}{120}\)

Bài 1 :

a/   \(a^3.a^9=a^{3+9}=a^{12}\)

b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)

c/  \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)

d/  \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)

e/  \(5^6:5^3+3^3.3^2\)

     \(=5^3+3^5=125+243=368\)

i/ \(4.5^2-2.3^2\)

   \(=2^2.5^2-2.3^2\)

   \(=2^2.25-2^2.14\)

   \(=2^2.\left(25-14\right)\)

   \(=2^2.11\)      

   \(=4.11=44\)

Bài 2 :

a, \(3^8:3^6=3^{8-6}=3^2\)

 \(7^5:7^2=7^{5-2}=7^3\)

 \(19^7:19^3=19^{7-3}=19^4\)

  \(2^{10}.8^3=2^{10}.\left(2^3\right)^3=2^{10}.2^9=2^{19}\)  

\(12^7:6^7=\left(12:6\right)^7=2^7=128\)

\(27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3=9\)

giúp mik với mn ơi mik cần gấp

a)5^x-2 - 3² = 2⁴ - ( 2⁸ * 2⁴- 2¹⁰ * 2² )

=> 5^x-2-3²=16

=> 5^x-2=25

=> (5^x)²=25

=> 5^x=5

=> x=1

b) ( 3 * x - 2⁴ ) * 7³  =  8 * 7⁴

=> (3.x-16)=8.7⁴:7³

=> 3x-16=56

=> 3x=72

=> x=24

c) x¹⁵ = x

=> x¹⁵:x=1

=> x¹⁴=1

=> x=1

d) ( x - 5 )⁴ =( x - 5 )⁶

=> (x-5)⁶:(x-5)⁴=1

=> (x-5)²=1

=> x-5=1

=> x=6

x¹⁵ = x \(\Rightarrow\)x = 1

Bài 1 :

a, Ta có : \(\left(-123\right)+\left|-13\right|+\left(-7\right)\)

= \(\left(-123\right)+13+\left(-7\right)=\left(-117\right)\)

b, Ta có : \(\left|-10\right|+\left|45\right|+\left(-\left|-455\right|\right)+\left|-750\right|\)

= \(10+45-455+750=350\)

c, Ta có : \(-\left|-33\right|+\left(-15\right)+20-\left|45-40\right|-57\)

= \(\left(-33\right)+\left(-15\right)+20-5-57=-90\)