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a: \(280-\left(x-140\right):35=270\)
=>(x-140):35=280-270=10
=>x-140=350
=>x=350+140
=>x=490
b: \(\left(190-2x\right):35-32=16\)
=>\(\left(190-2x\right):35=32+16=48\)
=>\(190-2x=35\cdot48=1680\)
=>2x=190-1680=-1490
=>x=-745
c: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=2^3\cdot5\)
=>\(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=8\cdot5=40\)
=>41-(2x-5)=720:40=18
=>2x-5=41-18=23
=>2x=28
=>x=14
d: \(\left(x:23+45\right)\cdot37-22=2^4\cdot105\)
=>\(\left(\frac{x}{23}+45\right)\cdot37=16\cdot105+22=1702\)
=>\(\frac{x}{23}+45=46\)
=>\(\frac{x}{23}=1\)
=>x=23
e: \(\left(3x-4\right)\left(x-1\right)^3=0\)
=>\(\left[\begin{array}{l}3x-4=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac43\\ x=1\end{array}\right.\)
f: \(2^{2x-1}:4=8^3\)
=>\(2^{2x-1-2}=2^9\)
=>2x-3=9
=>2x=12
=>x=6
g: \(x^{17}=x\)
=>\(x^{17}-x=0\)
=>\(x\left(x^{16}-1\right)=0\)
=>\(\left[\begin{array}{l}x=0\\ x^{16}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{16}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-1\end{array}\right.\)
h: \(\left(x-5\right)^4=\left(x-5\right)^6\)
=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)
=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)
=>\(\left(x-5\right)^4\cdot\left(x-4\right)\left(x-6\right)=0\)
=>x∈{4;5;6}
i: \(\left(x+2\right)^5=2^{10}\)
=>\(\left(x+2\right)^5=\left(2^2\right)^5=4^5\)
=>x+2=4
=>x=2
k: 1+2+3+...+x=78
=>\(\frac{x\left(x+1\right)}{2}=78\)
=>x(x+1)=156
=>\(x^2+x-156=0\)
=>(x+13)(x-12)=0
=>x=-13(loại) hoặc x=12(nhận)
l: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\frac{30}{3}=10\)
n: \(5^{x}:5^2=125\)
=>\(5^{x-2}=5^3\)
=>x-2=3
=>x=5
m: \(\left(x+1\right)^2=\left(x+1\right)^0\)
=>\(\left(x+1\right)^2=1\)
=>\(\left[\begin{array}{l}x+1=1\\ x+1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-2\end{array}\right.\)
o: Số số hạng của dãy số 2;4;..;52 là:
(52-2):2+1=50:2+1=25+1=26(số)
Tổng của dãy số 2;4;...;52 là:
\(\left(52+2\right)\cdot\frac{26}{2}=54\cdot13=702\)
(2+x)+(4+x)+...+(52+x)=780
=>26x+702=780
=>26x=78
=>x=3
p: \(70=2\cdot5\cdot7;80=2^4\cdot5\)
=>ƯCLN(70;80)=\(2\cdot5=10\)
70⋮x; 80⋮x
=>x∈ƯC(70;80)
=>x∈Ư(10)
mà x>8
nên x=10
q: \(12=2^2\cdot3;25=5^2;30=2\cdot3\cdot5\)
=>BCNN(12;25;30)=\(2^2\cdot3\cdot5^2=300\)
x⋮12; x⋮25; x⋮30
=>x∈BC(12;25;30)
=>x∈B(300)
mà 0<x<500
nên x=300
\(\left(x-1\right)=\left(2x-3\right)^2\)
\(\Leftrightarrow x-1=4x^2-12x+9\)
\(\Leftrightarrow4x^2-13x+10=0\)
\(\Leftrightarrow4x^2-8x-5x+10=0\)
\(\Leftrightarrow4x.\left(x-2\right)-5.\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(4x-5\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}x-2=0\\4x-5=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=2\\x=\frac{5}{4}\end{cases}}\)
Vậy: \(x=2\)hoặc \(x=\frac{5}{4}\)(Nếu đúng thì click cho mình nhoa!)
Lâu rồi mình ko giải, sai thì thôi nhé!
a) \(\left(10-2x\right)^2=25-\left(-11\right)\)'=
\(\Leftrightarrow\left(10-2x\right)^2=36\)
\(\Leftrightarrow\left(10-2x\right)^2=6^2\)
\(\Leftrightarrow\orbr{\begin{cases}10-2x=6\\10-2x=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=10-6\\2x=10-\left(-6\right)\end{cases}\Leftrightarrow}\orbr{\begin{cases}2x=4\\2x=16\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=8\end{cases}}}\)
Vậy \(x\in\left\{2;8\right\}\)
b) \(-2\left(-x+5\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-2\left(5-x\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-5\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-25+5x=8+4x\)
\(\Leftrightarrow5x-25=8+4x\)
\(\Leftrightarrow5x=8+4x+25\)
\(\Leftrightarrow5x=4x+33\)
\(\Leftrightarrow5x-4x=33\)
\(\Leftrightarrow1x=33\)
\(\Leftrightarrow x=33\)
Vậy \(x=33\)
a) (10 - 2x)2 = 25 - (-11)
(10 - 2x)2 = 36
(10 - 2x)2 = 62
=> 10 - 2x = 6
2x = 10 - 6
2x = 4
x =4:2
x=2
Vậy x = 2
b)-2(-x+5) - 3(5 - x) = 4(2+x)
2x - 10 - 15 +3x = 8 + 4x
2x - 25 + 3x = 8 +4x
2x + 3x - 4x = 8 + 25
5x - 4x = 33
x= 33
Vậy x = 33
A) x + 4 = -16
x = -16 - 4
x = -20
Vậy x = -20
b) 12- ( x - 5 ) =5.4
12 -x -5 = 20
x = 7 - 20
x = -13
Vậy x= -13
c) (-2)x - ( x - 17 ) = 34 - ( -x + 25 )
( -2 )x - x + 17 = 34 + x - 25
-3x + 17 = 11 + x
-3x - x = 11 - 17
-4x = -6
x = 1,5
Vậy x = 1,5
d) 17x - ( -16x - 37 ) = 2x + 43
17x + 16x - 2x = 43 -37
30x = 6
x = 0,2
Vậy x = 0,2
814 - ( x - 305 ) : 16 = 48
( x - 305 ) : 16 = 814 - 48
( x - 305 ) : 16 = 766
( x - 305 ) = 12256
x - 305 = 12561
Sorry mk ko giải đc trong 15 phút đâu , vậy mk thách bạn giải đc trong 5 phút đấy . Nếu bạn giải đc mk xin bạn nhận mk 20 lậy
a)280-(x-140):35=270
(x-140):35=280-270
(x-140):35= 10
x-140 =10x35
x-140 =350
x= 350+140
x=490
b)(190-2x):35-32=16
(190-2x):35 =16+32
(190-2x):35 = 48
190-2x= 48x35
190-2x=1680
2x=190-1680
2x=-1490
x=-1490:2
x=-745
c)720:[41-(2x-5)]=\(2^3\)x5
720:[41-(2x-5)=40
41-(2x-5)=720:40
41-(2x-5)=18
2x-5=41-18
2x-5=23
2x=23+5
2x=28
x=28:2
x=14
\(\left(\times:23+45\right)\cdot37-22=2^4\cdot105\)
\(\Rightarrow\times\cdot\frac{37}{23}+1665-22=16\cdot105\)
\(\Rightarrow\times\cdot\frac{37}{23}+1643=1680\)
\(\Rightarrow\times\cdot\frac{37}{23}=1680-1643=37\)
\(\Rightarrow\times=37:\frac{37}{23}=23\)
a) (190-2x) : 35 -32 = 16
=> (190-2x) : 35 =16+32
=> (190-2x) : 35 =48
=> 190-2x = 48.35 = 1680
=> 2x = 190-1680 = -1490
=> x = -1490/2= -745
b) (x : 23 + 45) . 37 -22 =2^4.105
=> (x : 23+45).37=2^4.105+22=1702
=> (x : 23 +45) = 1702/37 = 46
=> x : 23 = 46- 45 =1
=> x = 23
a) ( 190 - 2x ) : 35 - 32 = 16
( 190 - 2x ) : 35 =48
190-2x=1680
2x=-1490
x=-745
b) ( x : 23 + 45) . 37 - 22 = 24 . 105
( x : 23 + 45) . 37 - 22 = 1680
( x : 23 + 45) . 37 =1702
x : 23 + 45= 46
x:23=1
x=23
a) ( 190 - 2x ) : 35 -32 = 16
( 190 -2x ) : 35 = 48
190 - 2x =1680
2x =-1490
x =-745
b) ( x : 23 +45 ) . 37 - 22 = 24 . 105
( x : 23 +45 ) . 37 - 22 =1680
( x : 23 +45 ) . 37 =1702
( x : 23 +45 ) =46
x : 23 =1
x =23