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1)
a) 35.23 + 35.41 + 64.65 = 35(23+41) + 64.65 = 35 . 65 + 64.65 =65. 99 = 65(100 - 1 ) = 6500 - 65 = 6435
b) 29.87 - 29.23 + 64.71 = 29(87-23) + 64.71 = 29.64 + 64.71 = 64(71+29) = 64.100= 6400
c) 48.19 + 48.115 + 134.52 = 48(19+115) + 134.52 = 48 . 134+134.52=134(52+48)=134.100=13400
d) 27.121 - 87.27 + 73.34 = 27(121-87) +73 .34 = 27 .34 + 73.34 = 34(73+27)=34.100=3400
e) 125.98-125.46-52.25 = 125(98-46) -52.25 = 125 . 52 - 52.25 =52(125-25) =52.100=5200
f)136.23 + 136.17 - 40.36 = 136(23+17) - 40.36 = 136.40 -40.36 = (136-36)40 = 100.40=4000
g) 17.93 + 116.83 + 17.23 = 17(93+23) + 116.83 = 17.116 + 116.83 =116(83+17) = 116.100=11600
h)19.27 +47.81 + 19.20 = 19(27+20) + 47.81 = 19. 47 + 47.81 = 47(81+19)=47.100 = 4700
i) 87.23 + 13.93 + 70.87 = 87(23+70) + 13.93 = 87 .93 + 13.93 = 93(87+13)=93.100=9300
2)Tìm x
a) [(6x-39):37].4 = 12
(6x - 39) : 37 = 12 : 4 = 3
x =(3.37 + 39): 6 = 25
b) ( x : 3 - 4 ) .5=15
x : 3 -4 = 3
x = (3+4).3 = 21
c) 128 - 3(x+4) =23
3x + 12 = 128 -23 = 105
x = (105-12):3 = 31
d) (3x - 34).73=2.74
3x - 81 = 2.74:73=2.7=14
x =(81 + 14 ) : 3= \(31\frac{2}{3}\)
e) x - [42 + (-28) ] = -8
x - 14 = -8
x- 14 + 14 = -8 + 14
x = 6
1. Tính nhanh:
a, 35.23+35.41+64.65
= 35. (23+41) +64.65
= 35. 64 + 64.65
= 64. ( 35 + 65 )
= 64 . 100
= 6400
b, 29.87 - 29.23 + 64.71
= 29.(87-23) + 64.71
= 29.64 + 64.71
= 64.(29 + 71)
= 64.100
= 6400
c, 48.19 + 48.115 + 134.52
= 48.(19 + 115) + 134.52
= 48.134 + 134.52
= 134.(48 + 52)
= 134.100
= 13400
d, 27.121 - 87.27 + 73.34
= 27.(121 - 87) + 73.34
= 27.34 + 73.34
= 34.(27 + 73)
= 34.100
= 3400
e, 125.98 - 125.46 - 52.25
= 125.(98 - 46) - 52.25
= 125.52 - 52.25
= 52.(125 - 25)
= 52.100
= 5200
f, 136.23 + 136.17 - 40.36
= 136.(23 + 17) - 40.36
= 136.40 - 40.36
= 40.(136 - 36)
= 40.100
= 4000
g, 17.93 + 116.83 + 17.23
= 17.(93+23) + 116.83
= 17.116 + 116.83
= 116.(17 + 83)
= 116.100
= 11600
Lát nữa mình làm tiếp, giờ mình phải đi học rồi
a; |\(x+2\)| = 0
\(x+2=0\)
\(x\) = - 2
Vậy \(x\) = - 2
b; |\(x-5\)| = |-7|
| \(x-5\) | = 7
\(\left[{}\begin{matrix}x=7\\x=-7\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=5+7\\x=-7+5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\)
Vậy \(x=12\)
\(x=-2\)
a: \(\Leftrightarrow2x-2+4x+8=-12\)
=>6x+6=-12
=>6x=-18
hay x=-3
b: \(\Leftrightarrow-10x-15-12+9x=13\)
=>-x-27=13
=>-x=40
hay x=-40
c: \(\Leftrightarrow-10x+70+20-5x=-15\)
\(\Leftrightarrow-15x=-105\)
hay x=7
d: \(\Leftrightarrow8x-12-7x+14=10\)
=>x+2=10
hay x=8
e: \(\Leftrightarrow-12x-18+14x+2=2\)
=>2x-16=2
hay x=9
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
mk sắp phải đi học rồi các bạn giúp mình với có đc ko mk nhớ sẽ đền đáp công ơn của bạn
Câu a:
1 + {-2 - [-3 + (-4 + |x|)]} = 1 - 2 + [(-3 - 4)]
1 + {-2 -[-3 - 4 + |x|]} = 1 - 2 + [-7]
1 + {-2 - [- 7 + |x|]} = 1 - 2 - 7
1 + {- 2 + 7 - |x|} = - 1 - 7
1 + {5 - |x|} = - 8
5 - |x| = - 8 - 1
5 - |x| = - 9
|x| = 5 + 9
|x| = 14
x = - 14 hoặc x = 14
Vậy x ∈ {-14; 14}
Câu b:
34 + (9 - 21) = 3417 - (x + 3417)
34 + (-12) = 3417 - x - 3417
34 - 12 = 3417 - 3417 - x
22 = - x
x = 22 : (-1)
x = - 22
Vậy x = - 22
a) \(2\left(x-5\right)-3\left(x+7\right)=14\)
\(\Leftrightarrow2x-10-3x-21=14\)
\(\Leftrightarrow-x-31=14\)
\(\Leftrightarrow-x=45\Leftrightarrow x=-45\)
b) \(5\left(x-6\right)-2\left(x+3\right)=12\)
\(\Leftrightarrow5x-30-2x-6=12\)
\(\Leftrightarrow3x-36=12\)
\(\Leftrightarrow3x=48\Leftrightarrow x=16\)
c) \(3\left(x-4\right)-\left(8-x\right)=12\)
\(\Leftrightarrow3x-12-8+x=12\)
\(\Leftrightarrow4x-20=12\)
\(\Leftrightarrow4x=32\Leftrightarrow x=8\)
d) \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x+35=0\Leftrightarrow x=5\)
d, \(\left(3x-2^4\right).7^3=2.7^4\)
\(\Rightarrow3x-2^4=2.7^4:7^3\)
\(\Rightarrow3x-16=2.7\\ \Rightarrow3x=14+16\\ \Rightarrow3x=30\Rightarrow x=10\)
Vậy.....
e, \(x-\left[42+\left(-28\right)\right]=-8\)
\(\Rightarrow x-14=-8\\ \Rightarrow x=6\)
Vậy.....
g, \(x-7=-5\)
\(\Rightarrow x=-5+7\Rightarrow x=2\)
Vậy.....
h, \(15-5\left(x+4\right)=-12-3\)
\(\Rightarrow15-5x-20=-15\)
\(\Rightarrow-5x=-15-15+20\)
\(\Rightarrow-5x=-10\Rightarrow x=2\)
Vậy.....
Chúc bạn học tốt!!!
d/ \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
\(\Rightarrow3x-16=\dfrac{2\cdot7^4}{7^3}=14\)
\(\Rightarrow3x=14+16=30\)
\(\Rightarrow x=\dfrac{30}{3}=10\)
e/ Đễ ==> tự lm thì tốt hơn nhé
g/ Đễ ==> tự lm thì tốt hơn nhé
h/ \(15-5\left(x+4\right)=-12-3\)
\(\Rightarrow15-5x-20=-15\)
\(\Rightarrow-5x=-15+20-15=-10\)
\(\Rightarrow x=\dfrac{-10}{-5}=2\)
i/ \(\left(7-x\right)-\left(25+7\right)=-25\)
\(\Rightarrow7-x-25-7=-25\)
\(\Rightarrow-x=-25-7+7+25\)
\(\Rightarrow-x=0\Rightarrow x=0\)
k/ \(\left|x+2\right|=0\Rightarrow x+2=0\Rightarrow x=-2\)
l/ \(\left|x-3\right|=7-\left(-2\right)\)
\(\Rightarrow\left|x-3\right|=9\)
\(\Rightarrow\left[{}\begin{matrix}x-3=9\\x-3=-9\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\)
m/ \(\left|x-5\right|=\left|-7\right|\Rightarrow\left|x-5\right|=7\)
\(\Rightarrow\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\)
i, \(\left(7-x\right)-\left(25+7\right)=-25\)
\(\Rightarrow7-x-25-7=-25\)
\(\Rightarrow-x=-25-7+25+7\)
\(\Rightarrow x=0\)
Vậy.....
k, \(\left|x+2\right|=0\)
\(\Rightarrow x+2=0\Rightarrow x=-2\)
Vậy.....
l, \(\left|x-3\right|=-7-\left(-2\right)\)
\(\Rightarrow\left|x-3\right|=-5\)
Với mọi giá trị của \(x\in Z\) ta có:
\(\left|x-3\right|\ge0\) mà \(-5< 0\) nên không tìm được giá trị nào của x thoả mãn \(\left|x-3\right|=-5\).
Vậy \(x\in\varnothing\)
m, \(\left|x-5\right|=\left|-7\right|\)
\(\Rightarrow\left|x-5\right|=7\\ \Rightarrow\left\{{}\begin{matrix}x-5=-7\\x-5=7\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=-2\\x=12\end{matrix}\right.\)
Vậy...,..
Chúc bạn học tốt!!!
ý l bn chép sai đề --> sai
d) Ta có
(3x - 24).73 = 2.74
(3x - 24).73 = 2.2401
(3x - 16).343 = 4802
3x - 16 = 4802 : 343
3x - 16 = 14
3x = 16 + 14
3x = 30
x = 30 : 3
x = 10
Vậy x = 10 là giá trị cần tìm
e) x - [42 + (-28)] = -8
x - 14 = -8
x = -8 + 14
x = 6
Vậy x = 6 là giá trị cần tìm
g) x - 7 = -5
x = -5 + 7
x = 2
Vậy x = 2 là giá trị cần tìm
h) 15 - 5(x + 4) = -12 - 3
15 - 5(x + 4) = -15
5(x + 4) = 15 - (-15)
5(x + 4) = 30
(x + 4) = 30 : 5
(x + 4) = 6
x = 6 - 4
x = 2
Vậy x = 2 là giá trị cần tìm
i) (7 - x) - (25 + 7) = -25
(7 - x) - 32 = -25
7 - x = -25 + 32
7 - x = 7
x = 7 - 7
x = 0
Vậy x = 0 là giá trị cần tìm
k) |x + 2| = 0
=> x + 2 = 0
x = 0 - 2
x = -2
Vậy x = -2 là giá trị cần tìm
l) |x - 3| = 7 - (-2)
|x - 3| = 9
=> \(\left[{}\begin{matrix}x-3=9\\x-3=-9\end{matrix}\right.\)
x - 3 = 9
x = 9 + 3
x = 12
x - 3 = -9
x = -9 + 3
x = -6
Vậy \(\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\) là giá trị cần tìm
m) |x - 5| = |-7|
|x - 5| = 7
=> \(\left[{}\begin{matrix}x-5=7\\x-5=-7\end{matrix}\right.\)
x - 5 = 7
x = 7 + 5
x = 12
x - 5 = -7
x = -7 + 5
x = -2
Vậy \(\left[{}\begin{matrix}x=12\\x=-2\end{matrix}\right.\) là giá trị cần tìm
d)\(\left(3x-2^4\right).7^3=2.7^4\Leftrightarrow\left(3x=16\right)=2.7=14\)
\(\Leftrightarrow3x=14+16=30\Leftrightarrow x=30:3=10\)
e) \(x-\left[42+\left(-28\right)\right]=-8\Leftrightarrow x-42+28=-8\)
\(\Leftrightarrow x-14=-8\Leftrightarrow x=14+-8=6\)
g)\(x-7=-5\Leftrightarrow x=-5+7=2\)
h)\(15-5\left(x+4\right)=-12-3\)
\(\Leftrightarrow15-5\left(x+4\right)=-15\Leftrightarrow5\left(x+4\right)=15+15=30\Leftrightarrow x+4=30:5=6\Leftrightarrow x=2\)i)\(\left(7-x\right)-\left(25+7\right)=-25\Leftrightarrow7-x-32=-25\)
\(-25-x=-25\Leftrightarrow x=-25--25=0\)
k)\(\left|x+2\right|=0\Leftrightarrow x+2=0\Leftrightarrow x=-2\)
l) \(\left|x-3\right|=7-\left(-2\right)\Leftrightarrow\left|x-3\right|=9\)
\(\Leftrightarrow x-3=9\Leftrightarrow x=12\)
\(\Leftrightarrow x-3=-9\Leftrightarrow x=-6\)
m) \(\left|x-5\right|=\left|-7\right|\Leftrightarrow\left|x-5\right|=7\)
\(\Leftrightarrow x-5=7\Leftrightarrow x=12\)
\(\Leftrightarrow x-5=-7\Leftrightarrow x=-2\)