k) \(2x-49=5.3^2\)

\(2x-49=45\)

\(2x=49+45\)

\(2x=94\)

\(x=47\)

l) \(3^2.\left(x+14\right)-5^2=5.2^2\)

\(9.\left(x+14\right)-25=20\)

\(9.\left(x+14\right)=45\)

\(x+14=5\)

\(x=-9\)

m) \(6x+x=5^{11}:5^9+3^1\)

\(7x=5^{11-9}+3\)

\(7x=5^2+3\)

\(7x=28\)

\(x=4\)

n) \(7x-x=5^{21}:5^{19}+3.2^2-\left(-7^{-0}\right)\)

\(6x=5^{21-19}+12-1\)

\(6x=5^2+11\)

\(6x=36\)

\(x=6\)

o) \(7x-2x=6^{17}:6^{15}+44:11\)

\(5x=6^{17-15}+4\)

\(5x=6^2+4\)

\(5x=40\)

\(x=8\)

o)7x-x=5²¹:5¹⁹+3.2²-7⁰

=> 6x = 5^2 + 12 -1

=> 6x = 36

=> x = 36/6 = 6

Kết quả 6

Học tốt

i) \(2345-1000\div\left[19-2\left(21-18\right)^2\right]\)

\(=\)\(2345-1000\div\left[19-2.3^2\right]\)

\(=\)\(2345-1000\div\left[19-2.9\right]\)

\(=\)\(2345-1000\div\left[19-18\right]\)

\(=\)\(2345-1000\div1\)

\(=\)\(2345-1000\)

\(=\)\(1345\)

j) \(128-\left[68+8\left(37-35\right)^2\right]\div4\)

\(=\)\(128-\left[68+8.2^2\right]\div4\)

\(=\)\(128-\left[68+8.4\right]\div4\)

\(=\)\(128-\left[68+32\right]\div4\)

\(=\)\(128-100\div4\)

\(=\)\(128-25\)

\(=\)\(3\)

k) \(568-\left\{5\left[143-\left(4-1\right)^2\right]+10\right\}\div10\)

\(=\)\(568-\left\{5\left[143-3^2\right]+10\right\}\div10\)

\(=\)\(568-\left\{5\left[143-9\right]+10\right\}\div10\)

\(=\)\(568-\left\{5.134+10\right\}\div10\)

\(=\)\(568-\left\{670+10\right\}\div10\)

\(=\)\(568-680\div10\)

\(=\)\(568-68\)

\(=\)\(500\)

a) \(107-\left\{38+\left[7.3^2-24\div6+\left(9-7\right)^3\right]\right\}\div15\)

\(=\)\(107-\left\{38+\left[7.3^2-24\div6+2^3\right]\right\}\div15\)

\(=\)\(107-\left\{38+\left[7.9-4+8\right]\right\}\div15\)

\(=\)\(107-\left\{38+\left[63-4+8\right]\right\}\div15\)

\(=\)\(107-\left\{38+67\right\}\div15\)

\(=\)\(107-105\div15\)

\(=\)\(107-7\)

\(=\)\(7\)

b) \(307-\left[\left(180-160\right)\div2^2+9\right]\div2\)

\(=\)\(307-\left[20\div4+9\right]\div2\)

\(=\)\(307-\left[5+9\right]\div2\)

\(=\)\(307-14\div2\)

\(=\)\(307-7\)

\(=\)\(300\)

c) \(205-\left[1200-\left(4^2-2.3\right)^3\right]\div40\)

\(=\)\(205-\left[1200-\left(16-6\right)^3\right]\div40\)

\(=\)\(205-\left[1200-10^3\right]\div40\)

\(=\)\(205-\left[1200-1000\right]\div40\)

\(=\)\(205-200\div40\)

\(=\)\(205-5\)

\(=\)\(200\)

\(5^{20}:\left(5^{15}.6+5^{15}.19\right)\)

\(=5^{20}:\left(5^{15}\left(6+19\right)\right)\)

\(=5^{20}:\left(5^{15}.25\right)\)

\(=5^{20}:\left(5^{15}.5^2\right)\)

\(=5^{20}:\left(5^{15+2}\right)\)

\(=5^{20}:5^{17}\)

\(=5^{20-17}\)

\(=5^3=125\)

a)  5²⁰ : (5¹⁵.6 + 5¹⁵.19)

= 5²⁰  : [ 5¹⁵ . ( 6 + 19 ) ]

= 5²⁰  : [ 5¹⁵ . 25 ]

=  5²⁰  : [ 5¹⁵ . 5² ]

=  5²⁰  : [ 5^{15 + 2} ]

=  5²⁰  : 5¹⁷

= 5^{20 - 17}

= 5³

^{= 125.}

^{Hok tốt !}

a) 1⁵ + 2³ = 1 + 8 = 9 = 3² ( là số chính phương )

b) 5² + 12² = 25 + 144 = 169 = 13² ( là số chính phương )

c) 2⁶ + 6² = 64 + 36 = 100 = 100² ( là số chính phương )

d) 1³ + 2³ + 3³ + 4³ + 5³ + 6³

= 1 + 8 + 27 + 64 + 125 + 216

= 441 = 21² ( là số chính phương )

a) 1⁵ + 2³=1 + 8 = 9 (là số chính phương)

b) 5² + 12²= 25 + 144= 169 (là số chính phương)

c) 2⁶ + 6²= 64 + 36=100 (là số chính phương)

d) 14² – 12²= 196 - 144=52 (không là số chính phương)

e) 1³ + 2³ + 3³ + 4³ + 5³ + 6³= 1 + 8 + 27 + 64 + 125 + 216 = 411 (là số chính phương)

a/\(A=\left(3+5\right)^2=8^2=64\)

\(B=3^2+5^2=9+25=34\)

\(\Rightarrow A>B\)

b/ \(C=\left(3+5\right)^3=8^3=512\)

\(D=3^3+5^3=27+125=152\)

\(\Rightarrow C>D\)

a/ A= (3+5)² = 8² = 64

   B = 3² + 5² = 9 + 25 = 34

vì 64>34 => A > B

b/ C = (3+5)³ = 8³ = 512

    D = 3³ + 5³ = 27 + 125 = 152

Vì 512>152 => C > D

a/ A = 8²

A = 64

B = 9 + 25, B = 34

b/ C = 8³, CC = 512

D = 27 + 125

D = 152

a) \(5x+x=39-3^{11}:3^9\)

\(6x=39-3^2\)

\(x=30:6\)

\(x=5\)

vậy \(x=5\)

b) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)

\(6x=5^2+12-1\)

\(6x=36\)

\(x=6\)

vậy \(x=6\)

câu c tương tự nha

a) x=5,b)x=6 ,c)x=8 nha mình tự làm đấy