(3x-2)/2+5-(1+2+3+...+100)=10100

(3x-2)/2+5-5050=10100

(3x-2)/2=10100+5050-5

(3x-2)/2=15145

3/2x-1=15145

3/2x=15145+1

x=15146:3/2

x=30292/3

v~ cả cái bài đầu tiên @@

a) 

<=> 219 - 7x - 7 = 100

<=>         -7x       = 100 - 219 + 7

<=>          -7x      = -112

<=>             x       = -112 : (-7)

<=>             x       = 16

b)

<=> 9x - 18 = 34

<=> 9x         = 34 + 18

<=> 9x         = 52

<=>   x         = 52 : 9

<=>   x         = 52/9

a)219-7(x+1)=100

         7(x+1)=219-100

         7(x+1)=119

            x+1 =119:7

            x+1 =17

            x     =17-1

            x     =16

b)  (3x-6).3=34

    3x-6      =34:3

    3x-6      =\(\frac{34}{3}\)

    3x         =\(\frac{34}{3}\)- 6

    3x         =\(\frac{16}{3}\)

      x         =\(\frac{16}{3}\): 3

      x         =\(\frac{16}{9}\)

a/ => 7(x + 1) = 119

=> x + 1 = 17

=> x = 16

b/ => 3x - 6 = 3³ = 27

=> 3x = 33

=> x = 11

giúp mình nhanh lên nhé

a)219-7(x+1)=100

7(x+1)=219-100

7(x+1)=119

x+1=119:7

x+1=17

x=17-1

x=16

b)(3x-6).3=3⁴

(3x-6).3=81

3x-6=81:3

3x-6=17

3x=27+6

3x=33

x=33:3

x=11

li-ke cho mình nha Duong Thi Hoai My

(3x-6).3= 3 mũ 4

a. 219 - 7(x+1) = 100

    7(x+1)=119

     x+1=119:7

    x+1=17

    x=16

Vậy x=16

b. (3x - 6) . 3 = 3⁴

     3x-6=3⁴:3

     3x-6=3³

     3x=33

    x=11

Vậy x=11  

a) \(219-7\left(x+1\right)=100\)

\(\Leftrightarrow219-7x-7=100\)

\(\Leftrightarrow-7x=100-219+7=-112\)

\(\Leftrightarrow x=16\)

b) \(\left(3x-6\right)\cdot3=3^4\)

\(\Leftrightarrow\left(x-2\right)\cdot3^2=3^4\)

\(\Leftrightarrow x-2=3^2\)

\(\Leftrightarrow x=9+2=11\)

a)x+(x+1)+(x+2)+(x+3)+...+(x+99)+(x+100)=5555

=> 101x +5050 = 5555

=> 101x = 505

=> x = 505 : 101 = 5

Vậy, x = 5

b)1+2+3+4+...+x=820

=> ( x+1) x :2 = 820

=> (x+1)x = 1640

Mà 1640 = 40 . 41

=> x = 40 ( vì {x+1} - x = 1)

Vậy, x = 40

c) 3^x+1 = 9.27=243

=> 3^x+1 = 3⁵

=>x + 1 = 5

=> x = 4

Vậy, x=4

d) x+2x+3x+...+99x+100x=15150

=> [( 100 + 1) x 100 :2 ] x = 15150

=> 5050x = 15150

=> x = 15150:5050 = 3

Vậy, x =3

e)(x+1)+(x+2)+(x+3)+...+(x+100)=205550

=> 100x + 5050 = 205550

=> 100x =  205550 - 5050= 200500

=> x =  200500 : 100 = 2005

Vậy, x = 2005

f)3^x+3^x+1+3^x+2=351

=> 3^x + 3^x . 3 + 3^x x 9 = 351

=> 3^x ( 1+3+9) = 351

=> 3^x  . 13 = 351

=> 3^x  = 351 :13=27 mà 27 = 3³

=> x=3

Vậy, x=3

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