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1.
2|x-6|+7x-2=|x-6|+7x
2|x-6| - |x-6|=7x-(7x-2)
|x-6| = 2
=>x-6 = +2
*x-6=2 *x-6 = -2
x =2+6 x = (-2)+6
x =8 x = 4
2.
|x-5|-7(x+4)=5-7x
|x-5|-7x-28 =5-7x
|x-5|-28 =5-7x+7x
|x-5|-28 = 5
|x-5| = 5+28
|x-5| = 33
=>x-5 = +33
*x-5=33 *x-5=-33
x =38 x = -28
3.
3|x+4|-2(x-1)=7-2x
3|x+4|-2x+2 =7-2x
3|x+4|-2 =7-2x+2x
3|x+4|-2 =7
3|x+4| =7+2
3|x+4| = 9
|x+4| =9:3
|x+4| = 3
=>x+4 = +3
*x+4=3 *x+4=-3
x =-1 x = -7
Câu a:
2.(x + 2/5) + 1 1 /4 = 11/20
2x + 4/5 + 5/4 = 11/20
2x = 11/20 - 5/4 - 4/5
2x = 11/20 - 25/20 - 16/20
2x = -30/20
2x = -3/2
x = -3/2 : 2
x = - 3/4
Vậy x = - 3/4
Câu b:
x - 1 1/8 - 2/3x - 5/6x = 75%
(x - 2/3x - 5/6x) = 75% + 1 1/8
x (1 - 2/3 - 5/6) = 3/4 + 9/8
x (6/6 - 4/6 - 5/6) = 6/8 + 9/8
x.(-1/2) = 15/8
x = 15/8 : (-1/2)
x = 15/8 x (-2)
= -15/4
a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
a, (x-15):5+22=24
( x - 15 ) : 5 = 2
x-15 = 10
x = 25
Câu a:
(x -15) : 5 + 22 = 24
(x -15) : 5 = 24 - 22
(x -15) : 5 = 2
x - 15 = 2 x 5
x - 15 = 10
x = 10 + 15
x = 25
Vậy x = 25
Lâu rồi mình ko giải, sai thì thôi nhé!
a) \(\left(10-2x\right)^2=25-\left(-11\right)\)'=
\(\Leftrightarrow\left(10-2x\right)^2=36\)
\(\Leftrightarrow\left(10-2x\right)^2=6^2\)
\(\Leftrightarrow\orbr{\begin{cases}10-2x=6\\10-2x=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=10-6\\2x=10-\left(-6\right)\end{cases}\Leftrightarrow}\orbr{\begin{cases}2x=4\\2x=16\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=8\end{cases}}}\)
Vậy \(x\in\left\{2;8\right\}\)
b) \(-2\left(-x+5\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-2\left(5-x\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-5\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-25+5x=8+4x\)
\(\Leftrightarrow5x-25=8+4x\)
\(\Leftrightarrow5x=8+4x+25\)
\(\Leftrightarrow5x=4x+33\)
\(\Leftrightarrow5x-4x=33\)
\(\Leftrightarrow1x=33\)
\(\Leftrightarrow x=33\)
Vậy \(x=33\)
a) (10 - 2x)2 = 25 - (-11)
(10 - 2x)2 = 36
(10 - 2x)2 = 62
=> 10 - 2x = 6
2x = 10 - 6
2x = 4
x =4:2
x=2
Vậy x = 2
b)-2(-x+5) - 3(5 - x) = 4(2+x)
2x - 10 - 15 +3x = 8 + 4x
2x - 25 + 3x = 8 +4x
2x + 3x - 4x = 8 + 25
5x - 4x = 33
x= 33
Vậy x = 33
Tìm x biết : /2x-1/=3
Th1 : | 2x - 1 | = 3
2x = 4
x = 2
Th2 : : /2x-1/=-3
2x - 1 = -2
x = -1
k nha
a) x=4 và x=-1
b) \(\frac{16}{25}\)
1) /2x-1/ tương đương 2x-1=3 hoặc -3
th1) 2x-1=3
suy ra 2x=4
x=2
th2) 2x-1=-3
suy ra 2x=-2
x=-1
2) (4/5)^5 \(\times\)x= (4/5)^7
\(\Leftrightarrow\)x = (4/5)^7 \(\div\)(4/5)^5
\(\Leftrightarrow\)x=(4/5)^2=16/25