a, (x-35)-120=0

x-35=120+0

x-35=120

x=120+35

x=155

b,7x-8=713

7x=713+8

7x=721

x=721:7

x=103

c,4x:17=0

4x=0.17

4x=0

x=0:4

x=0

d,75+(131-x)=205

131-x=205-75

131-x=130

x=131-130

x=1

e,2x-36=4^6:4^3

2x-36=4^6-3

2x-36=4^3

2x-36=48

2x=48-36

2x=12

x=12:2

x=6

f, 2011^2.2011^x=2011^6

2011^x=2011^6: 2011^2

2011^x=2011^6-2

2011^x=2011^4

x=4

bn

\(\text{a/ ( x-35 ) - 120 = 0}\)

\(\Rightarrow\left(x-35\right)=120\)

\(\Rightarrow x=120+35\)

\(x=155\)

\(\text{b/ 7x - 8 = 713}\)

\(\Rightarrow7x=713+8=721\)

\(x=721:7=103\)

\(\text{c/ 4x : 17 = 0}\)

\(4x=0\)

\(x=0\)

\(\text{d/ 75+(131-x) = 205}\)

\(131-x=205-75=130\)

\(x=131-130=1\)

\(e.2x-36=4^6:4^3\)

\(2x-36=4^3=64\)

\(2x=64+36=100\)

\(x=100:2=50\)

\(f.2011^2.2011^x=2011^6\)

\(\text{Ta có công thức }:x^n.x^m=x^{n+m}\)

\(\Rightarrow x=6-2=4\)

2+4+6+8+...+(2x)=120

=> (1+2+3+4+...+x).2=120

=> 1+2+3+4+...+x = 120:2=60

=> (x+1).x : 2 = 60

=> (x+1).x=60.2 = 120

=> Không có x thỏa mãn

giúp tôi với tôi đang gấp , đi mà , năn nỉ đó . huhu

x​ = 85. Nếu đúng thì k cho mình nha

​

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a) \(31x+\left(1+2+3+...+30\right)=620\)

\(31x+\left[\left(30:2\right).\left(30+1\right)\right]=620\)

\(31x+465=620\)

\(31x=620-465=155\)

\(x=155:31\)

\(x=5\)

b,c mik quên cách làm :P

\(a) \frac{4}{5}.x=\frac{8}{35}\)

\(\implies x= \frac{8}{35}:\frac{4}{5}\)

\(\implies x=\frac{8}{35}.\frac{5}{4}\)

\(\implies x=\frac{2}{7}\). Vậy \(x=\frac{2}{7}\)

\(b) \frac{3}{5}x-\frac{1}{2}=\frac{1}{7}\)

\(\implies \frac{3}{5}x=\frac{1}{7}+\frac{1}{2}\)

\(\implies \frac{3}{5}x=\frac{9}{14}\)

\(\implies x=\frac{9}{14}:\frac{3}{5}\)

\(\implies x=\frac{9}{14}.\frac{5}{3} \)

\(\implies x=\frac{15}{14}\). Vậy \(x=\frac{15}{14}\)

\(c) x-25\% x=0,5\)

\(\implies 75\% x=0,5\)

\(\implies \frac{3}{4}x=\frac{1}{2}\)

\(\implies x=\frac{1}{2}:\frac{3}{4}\)

\(\implies x=\frac{1}{2}.\frac{4}{3}\)

\(\implies x=\frac{2}{3}\). Vậy \(x=\frac{2}{3}\)

\(d) (\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}).120+x:\frac{1}{3}=-4\)

Có: \(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\)

\(=\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\)

\(=\frac{1}{24}-\frac{1}{30}\)

\(=\frac{1}{120}\)

Thay vào ta có: \(\frac{1}{120}.120+x:\frac{1}{3}=-4\)

\(\implies 1+x:\frac{1}{3}=-4\)

\(\implies x:\frac{1}{3}=-5\)

\(\implies x=-5.\frac{1}{3}\)

\(\implies x=\frac{-5}{3}\). Vậy \(x=\frac{-5}{3}\)

~ Hok tốt a~

\(\frac{4}{5}.x=\frac{8}{35}\)                                                                        \(\frac{3}{5}x-\frac{1}{2}=\frac{1}{7}\)

\(x=\frac{8}{35}:\frac{4}{5}\)                                                                        \(\frac{3}{5}x=\frac{1}{7}+\frac{1}{2}\)

\(x=\frac{8}{35}.\frac{5}{4}\)                                                                          \(\frac{3}{5}x=\frac{9}{14}\)

\(x=\frac{2}{7}\)                                                                                      \(x=\frac{9}{14}:\frac{3}{5}\)

Vậy \(x=\frac{2}{7}\)                                                                               \(x=\frac{9}{14}.\frac{5}{3}\)

\(x-25\%x=0.5\)                                                                   \(x=\frac{15}{14}\)

 \(x-\frac{1}{4}x=\frac{1}{2}\)                                                                   Vậy \(x=\frac{15}{14}\)

\(x\left(1-\frac{1}{4}\right)=\frac{1}{2}\)                                   \(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+x:\frac{1}{3}=-4\)

\(x=\frac{1}{2}:\frac{3}{4}\)                                       \(\left(\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+...+\frac{1}{29}-\frac{1}{30}\right).120+x:\frac{1}{3}=-4\)               \(x=\frac{2}{3}\)                                              \(\left(\frac{1}{24}-\frac{1}{30}\right).120+x:\frac{1}{3}=-4\)

Vậy \(x=\frac{2}{3}\)                                        \(\frac{1}{120}.120+x:\frac{1}{3}=-4\)

                                                                   \(1+x:\frac{1}{3}=-4\)

                                                                    \(x:\frac{1}{3}=\left(-4\right)-1\)

                                                                 \(x:\frac{1}{3}=-5\)

                                                                      \(x=\left(-5\right).\frac{1}{3}\)

                                                                      \(x=-\frac{5}{3}\)

                                                                    Vậy \(x=-\frac{5}{3}\)

Giải :

0,8 x 120 + 4 x 2 x 6 +8 x 2 +8 x 80

= 8 x 12 + 8 x 6 + 8 x 2 + 8 x 80

= 8 x ( 12 + 6 + 2 + 80 ) 

= 8 x 100

= 800

= 800 nha bạn

hok tốt

bạn nào trên 10 sp hoặc 10 sp k giúp mình ạ

a,\(\left(x-15\right):50+22=24\)

\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)

\(< =>x=100+15=115\)

b,\(42-\left(2x+32\right)+12:2=6\)

\(< =>42-2x-32=0\)

\(< =>10-2x=0< =>x=\frac{10}{2}=5\)

Làm nốt :

c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)

=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86

=> 134 - 2{156 - 6 . [54 - 30]} . x = 86

=> 134 - 2{156 - 6. 24} . x = 86

=> 134 - 2{156 - 144} . x = 86

=> 134 - 2.12 . x = 86

=> 134 - 24 . x = 86

=> 24.x = 48

=> x = 2

Bài 2 : a) 120 : [21 - (4x - 4)] = 2³.3

=> 120 : [21 - (4x - 4)] = 8.3

=> 120 : [21 - (4x - 4)] = 24

=> 21 - (4x - 4) = 5

=> 4x - 4 = 16

=> 4x = 20

=> x = 5

b) 3.[205 - (x - 9)] - 486 = 0

=> 3.[205 - (x - 9)] = 486

=> 205 - (x - 9) = 162

=> x - 9 = 205 - 162 = 43

=> x = 43 + 9 = 52

c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4

=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4

=> 204 - 2{200 - 5 .[64 - 34]}.x = 4

=> 204 - 2{200 - 5.30} . x = 4

=> 204 - 2{200 - 150}.x = 4

=> 204 - 2.50 . x = 4

=> 2.50.x = 200

=> 100.x = 200

=> x = 2