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a. 1440 : [ 120 - (3x + 9 ) ] = 120
120 - (3x + 9) = 1440 : 120 = 12
3x + 9 = 120 - 12 = 108
3x = 108 - 9 = 99
x = 99 : 3 = 33
b. 120 + [ ( 999 - 9x ) : 60 ] . 24 = 480
[ ( 999 - 9x ) : 60 ] . 24 = 480 - 120 = 360
( 999 - 9x ) : 60 = 360 : 24 = 15
( 999 - 9x ) = 15 . 60 = 900
9x = 999 - 900 = 99
x = 99 : 9 = 11
a. => \(2^{6+x}=2^{10}\)
=> 6+x=10
=> x=10-6
Vậy x=4.
b. => \(7^{3x-1}:7^2=7^6\)
=> 73x-1-2=76
=> 73x-3=76
=> 3x-3=6
=> 3x=6+3
=> 3x=9
Vậy x=3.
c. =>\(7^{5x-1}-25=24\)
=>75x-1=24+25
=>75x-1=49
=>75x-1=72
=>5x-1=2
=>5x=3
Vậy x=\(\frac{3}{5}\).
d. => \(10^{x-3}=10^0\)
=>x-3=0
Vậy x=3.
e. => 2x=10
=> x=10:2
Vậy x=5.
a ) 16x : 4x = 16
(16:4)x=16
4x=42 hoặc (-4)2
Vậy x=2
b) ( 2x + 1 )3 = -64
( 2x + 1 )3 = (-4)3
2x+1=-4
2x=-5
x=\(-\frac{5}{2}\)
Vậy x=\(-\frac{5}{2}\)
c ) ( 3x - 1 )2 = 16
( 3x - 1 )2 = 42=(-4)2
Suy ra:3x-1=4;3x=5;x=\(\frac{5}{3}\)
3x-1=-4;3x=-3;x=-1
Vậy x=-1;\(\frac{5}{3}\)
d ) 9x+1 = 32
9x+1 = 91
x+1=1
x=0
Vậy x=0
a) 16x : 4x = 16
=> ( 16 : 4 )x = 16
=> 4x = 16
<=> 4x = 42
=> x = 2
b) ( 2x + 1 ) 3 = -64
=> ( 2x + 1 )3 = ( -4 )3
=> 2x + 1 = -4
=> 2x = -4 - 1
=> 2x = -5
=> x = \(-\frac{5}{2}\)
c) ( 3x - 1 )2 = 16
\(\Rightarrow\begin{cases}\left(3x-1\right)^2=4^2\\\left(3x-1\right)^2=\left(-4\right)^2\end{cases}\)\(\Rightarrow\begin{cases}3x-1=4\\3x-1=-4\end{cases}\)\(\Rightarrow\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}\)
d) 9x+1 = 32
=> (32 ) x+1 = 32
=> 32.(x+1) = 32
=> 2(x + 1 ) = 2
=> x + 1 = 1
=> x = 0
a) 2x - 2x + 3 = -56
<=> 2x(1 - 23) = -56
<=> 2x.(- 7) = -56
<=> 2x = 8
<=> 2x = 23
<=> x =3
Vậy x = 3
b) 3x + 1 + 3x = 108
<=> 3x(3 + 1) = 108
<=> 3x = 27
<=> 3x = 33
<=> x = 3
Vậy x = 3
c) 27.3x + 1 = 33x
<=> 33.3x + 1 = 33x
<=> 3x + 4 = 33x
<=> x + 4 = 3x
<=> 2x = 4
<=> x =2
Vậy x = 2
d) 3x + 2 - 3x = 72
<=> 3x(32 - 1) = 72
<=> 3x = 9
<=> 3x = 32
<=> x = 2
e) (x - 5)12 - (x - 5)10 = 0
<=> (x - 5)10[(x - 5)2 - 1] = 0
<=> \(\orbr{\begin{cases}\left(x-5\right)^{10}=0\\\left(x-5\right)^2-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^{10}=0\\\left(x-5\right)^2=1\end{cases}}\)
Khi (x - 5)10 = 0
<=> x - 5 = 0
<=> x = 5
Khi (x - 5)2 = 1
<=> \(\orbr{\begin{cases}x-5=1\\x-5=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=4\end{cases}}\)
Vậy x \(\in\left\{4;5;6\right\}\)
Trả lời:
a. 2x - 2x+3 = - 56
<=> 2x - 2x . 23 = - 56
<=> 2x ( 1 - 23 ) = - 56
<=> 2x . ( - 7 ) = - 56
<=> 2x = 8
<=> 2x = 23
<=> x = 3
Vậy x = 3
b. 3x+1 + 3x = 108
<=> 3x . 3 + 3x = 108
<=> 3x ( 3 + 1 ) = 108
<=> 3x . 4 = 108
<=> 3x = 27
<=> 3x = 33
<=> x = 3
Vậy x = 3
c. 27 . 3x+1 = 33x
<=> 33 . 3x+1 = 33x
<=> 33+x+1 = 33x
<=> 3 + x + 1 = 3x
<=> 4 + x = 3x
<=> x - 3x = - 4
<=> - 2x = - 4
<=> x = 2
Vậy x = 2
d. 3x+2 - 3x = 72
<=> 3x . 32 - 3x = 72
<=> 3x ( 32 - 1 ) = 72
<=> 3x . 8 = 72
<=> 3x = 9
<=> 3x = 32
<=> x = 2
Vậy x = 2
e. (x - 5)12 - (x - 5)10 = 0
<=> ( x - 5 )10 [ ( x - 5 )2 - 1 ] = 0
<=> ( x - 5 )10 = 0 hoặc ( x - 5 )2 - 1 = 0
<=> x - 5 = 0 hoặc ( x - 5 )2 = 1
<=> x = 5 hoặc x - 5 = 1 hoặc x - 5 = - 1
<=> x = 5 hoặc x = 6 hoặc x = 4
Vậy x = 4; x = 5; x = 6
x^2 + (2x)^2 + (3x)^2 + (4x)^2 + (5x)^2 =200
=> x = 2
( đúng lắm đó mk làm trong violympic rồi )
Ta có x2 + (2x)2 + (3x)2 + (4x)2 + (5x)2 =200
<=> x2 + 4x2 +9x2 +16x2 + 25x2=200
<=> 55x2=200
<=> x2 =200/55
\(\Leftrightarrow x=+-\sqrt{\frac{200}{55}}\)
(3x-2)3:4=16
(3x-2)3 =16.4
(3x-2)3 =64
(3x-2)3 =43
3x-2 =4
3x =4+2
3x =6
x =6:3
x =2
512+3(23+22.x)=572
512+3(8+4.x)=572
3(8+4.x)=572-512
3(8+4.x)=60
8+4.x =60:3
8+4.x=20
4.x=20-8
4.x=12
x=12:4
x=3
tich dung cho minh nhe
(3x-2)^3:4=16
(3x-2)^3=16.4=64=4^3
=>3x-2=4
vậy x=2
512+3(2^3+2^2.x)=572
2^3+2^2.x=(572-512):3=20
8+4.x=20
4.x=20-8=12
x=12:4=3
vậy x=3
23x+1=16
23x.2=16
23x=8
23x=23
3x=3
x=1
23x+1 = 16
23x+1 = 24
=> 3x + 1 = 4
=> 3x = 4 - 1
3x = 3
x = 3 : 3
x = 1
4.35x-2=108
35x:32=27
35x=33.32
35x=35
5x=5
x=1
đau . là dấu nhân nhé
4.35x-2 = 108
35x-2 = 108 : 4
35x-2 = 27
35x-2 = 33
=> 5x - 2 = 3
=> 5x = 3 + 2
5x = 5
x = 5 : 5
x = 1
\(2^{3x+1}=16\)
\(\Leftrightarrow2^{3x+1}=2^4\)
\(3x+1=4\)
\(3x=4-1\)
\(3x=3\)
\(x=3:3\)
\(x=1\)Vậy x = 1
b, 4.35x-2 = 108
\(\Leftrightarrow\)35x-2 = 108 : 4
35x-2 = 27
35x-2 = 33
5x - 2 = 3
5x = 3 +2
5x = 5
x = 1 ...Vậy x = 1
c, 6.2 + 4.23x = 640
12 + 4.23x = 640
4.23x = 640 - 12
4.23x = 628
23x = 628 : 4
23x 157....k bt ( sai đề chắc rồi ! )
( don't k .....#EXOComingsoon.... )
\(2^{3x+1}=16\Leftrightarrow2^{3x+1}=2^4\Leftrightarrow3x+1=4\Leftrightarrow3x=4-1\)
\(\Leftrightarrow3x=3\Leftrightarrow x=3:3\Leftrightarrow x=1\)
\(4\cdot3^{5x-2}=108\Leftrightarrow3^{5x-2}=108:4\Leftrightarrow3^{5x-2}=27\)
\(\Leftrightarrow3^{5x-2}=27\Leftrightarrow3^{5x-2}=3^3\Leftrightarrow5x-2=3\Leftrightarrow5x=5\Leftrightarrow x=1\)
\(6\cdot2+4\cdot2^{3x}=640\Leftrightarrow12+4\cdot2^{3x}=640\Leftrightarrow4\cdot2^{3x}=640:12\)
\(\Leftrightarrow4\cdot2^{3x}=\frac{640}{12}\Leftrightarrow2^{3x}=\frac{640}{12}:4\Leftrightarrow2^{3x}=\frac{640}{48}\)
Cõ lẽ ý cuối mk làm sai nhưng vì hơi vội nên mk ko làm nữa