a: \(\Leftrightarrow\left[\left(3x+14\right):4-3\right]:2=1\)

=>(3x+14):4-3=2

=>(3x+14):4=5

=>3x+14=20

=>3x=6

hay x=2

b: \(\Leftrightarrow\left[\left(x:4+17\right):10+3\cdot16\right]:10=5\)

\(\Leftrightarrow\left(x:4+17\right):10=50-48=2\)

=>x:4+17=20

=>x:4=3

hay x=12

c: \(\Leftrightarrow2\cdot15^2+\left[2\cdot125-\left(2x+4\right)\cdot5\right]:19=453\)

\(\Leftrightarrow250-\left(2x+4\right)\cdot5=\left(453-450\right)\cdot19=57\)

=>5(2x+4)=197

=>2x+4=197/5

=>2x=177/5

hay x=177/10

d: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)

=>19x+50=126

=>19x=76

hay x=4

e: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}\)

\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)

hay x=14

f: \(\Leftrightarrow3\left(x+2\right):7=30\)

=>3(x+2)=210

=>x+2=70

hay x=68

g: \(2480-1570+200-x+5=1010\)

=>1115-x=1010

hay x=105

a) ( 6x - 84) : 2 - 72 = 201 

( 6x - 84) : 2=201+72

( 6x - 84) : 2=273

 6x - 84=273x2

 6x - 84=546

6x=546+84

6x=630

x=630:6

x=105

b) ( 3x - 3⁴ ) . 6³ = 6⁵

3x - 3⁴=6⁵:6³

3x - 3⁴=6²

3x-81=36

3x=36+81

3x=117

x=117:3

x=39

a) ( 6x - 84) : 2 - 72 = 201

   => (6x - 84) : 2 = 273

   => 6x - 84 = 546

   => 6x = 630

   => x = 105

b) ( 3x - 3⁴ ) . 6³ = 6⁵

   => 3x - 3⁴ = 6⁵ : 6³ = 6² = 36

   => 3x = 36 + 3⁴ = 36 + 81 = 117  

   => x = 39

3ⁿ=5²+2¹

3ⁿ=25+2

3ⁿ=27

3ⁿ=3³

=>n=3

3ⁿ = 5^3: 5 + 2⁵ : 2⁴

3ⁿ = 5^3-1 + 2^5-4

3ⁿ = 5² + 2¹

3ⁿ = 25 + 2

3ⁿ = 27

3ⁿ = 3³ 

=> n=3

a, 13.(x-9)=169

           x-9  =169:13

           x-9  =13

b, 230+[16+(x,-5)]=315.2\(^3\)

     230+[16+(x,-5)]=2520

               16+(x,-5)=2520-230

                16+(x-5)=2290

                        x-5  =2290-16

                        x-5  =2274

                        x      =2274+5

                        x      =2279

 c, 13x-3\(^2\)x=2003\(^1\)+1\(^{2016}\)

      13x-9x=2004

      (13-9)x=2004

           4 . x=2004

                 x=2004:4

                 x=501

a, \(\left|2x+1\right|=3\)

=> 2x + 1 = 3 hoặc 2x + 1 = -3

=> 2x = 3 - 1 hoặc 2x = -3 - 1

=> 2x = 2 hoặc 2x = -4

=> x = 1 hoặc x = -2

b, \(2\frac{1}{2}x+1\frac{1}{2}=2\frac{2}{3}\)

=> \(\frac{5}{2}x+\frac{3}{2}=\frac{8}{3}\)

=> \(\frac{5}{2}x=\frac{8}{3}-\frac{3}{2}\)

=> \(\frac{5}{2}x=\frac{16-9}{6}\)

=> \(\frac{5}{2}x=\frac{7}{6}\)

=> \(x=\frac{7}{6}:\frac{5}{2}=\frac{7}{6}\cdot\frac{2}{5}=\frac{7}{3}\cdot\frac{1}{5}=\frac{7}{15}\)

c, \(3\cdot5^{x-3}+1=16\)

=> 3 . 5^x-3 = 16 - 1

=> 3 . 5^x-3 = 15

=> 5^x-3 = 15 : 3

=> 5^x-3 = 5

=> x - 3 = 5 : 5

=> x - 3 = 1

=> x = 1 + 3 = 4

d, \((x-1)^2=25\)

=> \((x-1)^2=5^2\)

=> x - 1 = 5 hoặc x - 1 = -5

=> x = 6 hoặc x = -4

e, \((-2)^2+\left|3x+1\right|=(-28)\cdot7\)

=> 4 + |3x + 1| = -196

=> |3x + 1| = -196 - 4 = -200

=> |3x + 1| = -200

Không thỏa mãn điều kiện

a) 3^x = 3² . 3³

3^{x      =} 3⁵

=> x = 5

b)5^x =125 .25

5^{x     =} 5³  . 5²

5^x    = 5⁵

=> x = 5

c) 8 =2^x

2³  = 2^x

=> x = 3

d) x = 4

e)x = 3

f)x = 4