a) x=5

b) x=1

c) x=5

d)x=14

a: \(\left(2x-9\right)^3=27\)

=>2x-9=3

hay x=6

b: \(32:\left(3x-2\right)=2^3\)

=>3x-2=32:8=4

=>3x=6

hay x=2

c: \(6⋮x-1\)

\(\Leftrightarrow x-1\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)

hay \(x\in\left\{2;0;3;-1;4;-2;7;-5\right\}\)

a) \(\left(2x+3\right)^2=\frac{9}{25}\)

\(\Rightarrow\left(2x+3\right)^2=\left(\frac{3}{5}\right)^2\) hoặc \(\left(2x+3\right)^2=\left(-\frac{3}{5}\right)^2\)

\(\Rightarrow2x+3=\frac{3}{5}\) hoặc \(2x+3=-\frac{3}{5}\)

\(\Rightarrow2x=-\frac{12}{5}\) hoặc \(2x=-\frac{18}{5}\)

\(\Rightarrow x=-\frac{6}{5}\) hoặc \(x=-\frac{9}{5}\)

Vậy.......

b) \(\left(3x-1\right)^3=\frac{1}{27}\)

\(\left(3x-1\right)^3=\left(\frac{1}{3}\right)^3\)

\(\Rightarrow3x-1=\frac{1}{3}\)

\(\Rightarrow3x=\frac{4}{3}\)

\(\Rightarrow x=\frac{4}{9}\)

Vậy.......

a) (2x+3)²=\(\frac{9}{25}\)

2x+3=\(\sqrt{\frac{9}{25}}\)=\(\frac{3}{5}\)

2x=\(\frac{-12}{5}\)

x=\(\frac{-6}{5}\)

b) (3x-1)³=\(\frac{-1}{27}\)

3x-1=\(\frac{-1}{3}\)

3x=\(\frac{2}{3}\)

x=\(\frac{2}{9}\)

a)   ( 2x + 3)^2 = 121

        2x + 3^2   = 121

         2x + 9      = 121

                 2x    = 121 - 9

                  2x   =   112

                     x  =  112 : 2

                      x = 56

Mấy câu sau tự làm nhé bạn 

a) (2x + 3)² = 121

    (2x + 3)² = 11²

^=>   2x + 3 = 11

     2x       = 11 - 3

     2x       = 8

       x      = 8 : 2

       x       = 4

b) (75 - 3x)³ = 27

    ( 75 - 3x)³ = 3³

=> 75 - 3x     = 3

            3x     = 75- 3

            3x     =  72

              x     = 72 : 3

              x      = 24

Nếu bài dễ thì cố gắng tự làm bạn nhé.

Bài 1:

a) \(2x+3=5\)

\(\Leftrightarrow2x=5-3=2\)

\(\Leftrightarrow x=2:2=1\)

Vậy: x=1

b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)

Vậy: \(x\in\left\{3;0\right\}\)

c) \(3x+4=2x-7\)

\(\Leftrightarrow2x-3x=7+4\)

\(\Leftrightarrow-1x=11\)

\(\Leftrightarrow x=-11\)

Vậy: x=-11

d) \(\left(4x-1\right)^3=27\)\(=3^3\)

\(\Rightarrow4x-1=3\)

\(\Leftrightarrow4x=3+1=4\)

\(\Leftrightarrow x=4:4=1\)

Vậy: x=1

e) \(\left(x-7\right).2=3.\left(2x+4\right)\)

\(\Leftrightarrow2x-14=6x+12\)

\(\Leftrightarrow2x-6x=12+14\)

\(\Leftrightarrow-4x=26\)

\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)

Vậy: \(x=\frac{13}{-2}\)

a) (x² - 121) . (2x + 3) = 0

=>x²-121=0 hoặc 2x+3=0

+)Nếu x²-121=0

=>x²=0+121=121

=>x²=(-11)² hoặc x²=11²

=>x=-11 hoặc x=11

+)Nếu 2x+3=0

=>2x=0-3=-3

=>x=(-3):2=\(\frac{-3}{2}\)

Vậy x=-11 hoặc x=11 hoặc x=\(\frac{-3}{2}\)
b) 2x² - 8x = 0

=>2x(x-4)=0

=>x=0 hoặc x-4=0

Nếu x-4=0

=>x=0+4=4

Vậy x=0 hoặc x=4
c) (3x + 1)⁵ = (3x + 1)⁴

=>(3x+1)⁵:(3x+1)⁴=(3x+1)⁴:(3x+1)⁴

=>3x+1=1

=>3x=1-1=0

=>x=0:3=0

Vậy x=0

a)(x² - 121) . (2x + 3) = 0

=>x²-121=0 hoặc 2x+3=0

• Với x²-121=0

<=>x²=121 <=>x=±11

• Với 2x+3=0

<=>2x=-3 <=>x=-3/2

b) 2x² - 8x = 0

=>2x(x-4)=0

=>2x=0 hoặc x-4=0

=>x=0 hoặc x=4

1/ 3(x - 2) = 9 => x - 2 = 3 => x = 5

2/ 3(x - 36) = 216 => x - 36 = 72 => x = 108

3/ (x - 3)³ = 3³ => x - 3 = 3 => x = 6

4/ 2^x = 32 => 2^x = 2⁵ => x = 5

5/ 3x - 16 = 2.7⁴ : 7³ = 14 => 3x = 30 => x = 10

6/ (6x - 39) : 3 = 201 => 6x - 39 = 603 => 6x = 642 => x = 107

7/ (3x - 15)² = 81 => (3x - 15)² = 9² => 3x - 15 = 9 => 3x = 24 => x = 8

8/ 3(x + 4) = 105 => x + 4 = 35 => x = 31

9/ 12x - 4³ = 4.8⁴ : 8³ = 32 => 12x = 32 : 64 => 12x = 1/2 => x = 1/24

10/ 41 - (2x - 5) = 680 => 2x - 5 = -639 => 2x = -634 => x = - 317