Tìm tập xác định của các hàm số sau:

a) y=\(\sqrt{2x-3}\) b) y= \(\sqrt{\left|2x-3\right|}\) c) y= \(\sqrt{4-x}+\sqrt{x+1}\) d) y=\(\sqrt{x-1}+\frac{1}{x-3}\) e) y=\(\frac{1}{\left(x+2\right)\sqrt{x-1}}\)

f) y=\(\sqrt{x+3-2\sqrt{x+2}}\) g) y=\(\frac{\sqrt{5-2x}}{\left(x-2\right)\sqrt{x-1}}\) h) y=\(\sqrt{2x-1}+\sqrt{\frac{1}{3-x}}\) i) y= \(\sqrt{x+3}+\frac{1}{x^2-4}\)

xác định hàm số 

a, \(y=\sqrt{x^2+x-4}\)

b , \(y=\frac{1}{x^2+1}\)

c, y= l 2x - 3 l 

d , \(y=\frac{1}{x^2-3x}\)

e , \(y=\sqrt{1-x}+\frac{1}{x\sqrt{1}+x}\)

f , \(y=\frac{2x-1}{\sqrt{x\sqrt{\left(x-4\right)}}}\)

g , \(y=\sqrt{3+x}+\frac{1}{x^2-1}\)

h , \(y=\frac{1}{\sqrt{2x^2-4x+4}}\)

i, \(y=\sqrt{6-x}+2x\sqrt{2x+1}\)

j, \(y=\frac{x^2+1}{\sqrt{2-5}}+x\sqrt{1+x}\)

k, \(y=\frac{1}{x^2+3x+3}+\left(x+2\right)\sqrt{x+3}\)

l, \(y=\sqrt[3]{\frac{3x+5}{x^2-1}}\)

Tìm tập hợp xác định sau:

a, y= \(\sqrt{x}+\sqrt{x^2}-4x\)

b, y= \(\frac{\sqrt{x-1}}{x-2}\)

c,y= \(\frac{\sqrt{x}-1}{\left|x\right|-4}\)

d, y= \(\frac{3x+5}{x^2-3x+2}\)

e, y= \(\sqrt{x+3+2\sqrt{x+2}}+\sqrt{2-x^2+2\sqrt{1-x^2}}\)

f, y= \(\sqrt{\sqrt{x^2+1}-x}\)

h, y= \(\frac{2003}{\sqrt{m_x-2004}}\)

Cảm ơn ạ !

Tìm tập xác định của các hàm số sau:

a) y = \(\frac{\sqrt{x+1}}{x^2-x-6}\)

b) y = \(\sqrt{6-3x}\) - \(\sqrt{x-1}\)

c) y = \(\frac{\sqrt{2-x}+\sqrt{x+2}}{x}\)

d) y = \(\frac{\sqrt{3x-2}+6x}{\sqrt{4-3x}}\)

e) y = \(\sqrt{6-x}\) + \(\frac{2x+1}{1+\sqrt{x-1}}\)

f) y = \(\frac{2x+9}{\left(x+4\right)\sqrt{x+3}}\)

g) y = \(\frac{\sqrt{x^2-2x+3}}{x-3\sqrt{x}+2}\)

h) f(x) = \(\frac{1}{\sqrt{1-\sqrt{1+4x}}}\)

i) y = \(\frac{2x^2}{\sqrt{x^2-3x+2}}\)

tập xác định hàm số

a, y=\(\sqrt{x^2+x-4}\)

b , y = \(\frac{1}{x^2+1}\)

c , y=\(\frac{\left|2x-3\right|}{x^2+x+6}\)

d , y =\(\frac{1}{x^2-3x}\)

e , y =\(\sqrt{1-x}\) +\(\frac{1}{x\sqrt{1}+x}\)

f , \(\frac{2x-1}{\sqrt{x\sqrt{\left(x-4\right)}}}\)

g, y = \(\frac{x^2+1}{\sqrt{2-5}}\) + \(\frac{1}{x^2-1}\)

h , y= \(\frac{1}{\sqrt{2x^2-4x+4}}\)

i, \(\sqrt{6-x}\)+2x\(\sqrt{2x+1}\)

j, y = \(\sqrt{3+x}\) +\(\frac{1}{x^2-1}\)

k, y = \(\frac{1}{x^2+3x+3}\)+(x+2)\(\sqrt{x+3}\)

l, y =\(\sqrt[3]{\frac{3x+5}{x^2-1}}\)