ai giải hộ mình mình k liền

A=7 B=1 OR =0 C=2 D=4.5.6

a: \(2^{x}\cdot4=128\)

=>\(2^{x}=\frac{128}{4}=32=2^5\)

=>x=5

b: \(x^{15}=x\)

=>\(x^{15}-x=0\)

=>\(x\left(x^{14}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{14}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{14}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

c: \(\left(2x+1\right)^3=125\)

=>\(\left(2x+1\right)^3=5^3\)

=>2x+1=5

=>2x=5-1=4

=>\(x=\frac42=2\)

d: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-5-1\right)\left(x-5+1\right)=0\)

=>\(\left(x-5\right)^4\cdot\left(x-6\right)\left(x-4\right)=0\)

=>\(\left[\begin{array}{l}x-5=0\\ x-6=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=6\\ x=4\end{array}\right.\)

a) 70 - 5 (x - 3) = 45

 5 (x - 3) =70-45

 5 (x - 3) =25

 (x - 3)=25:5

 (x - 3)=5

x=5+3

x=8

b) 10 + 2.x = 4^5 : 4^3

10 + 2.x=4^2

10 + 2.x=16

2.x=16-10

2.x=6

x=6:2

x=3

c) 2x - 138 = 2^3 . 3^2

2x - 138 = 8.9

2x - 138 = 72

2x=72+138

2x=210

x=210:2

x=105

d) 231 - (x - 6) = 133 : 13

 (đề sai)

a ) 2 ^x  . 4 = 128

    2 ^x          = 32

    2 ^x          = 2 ⁵

=> x = 5

b ) x ¹⁵ = x

=> x = 0 hoặc x = 1

c ) ( 2x + 1 ) ³ = 125

     ( 2x + 1 ) ³ = 5 ³

=> 2x + 1 = 5

     2x       = 4

       x       = 2

d ) ( x - 5 ) ⁴ = ( x - 5 ) ⁶

=> x - 5 = 0 hoặc x - 5 = 1

         x  = 5              x  = 6

Vậy x = 5 hoặc x = 6

a) x=5

b) x=1 hoặc x=0 hoặc x=-1

c) x=2

d) x=5 hoặc x=-4 hoặc x=6

Cho mình câu chả lời sớm nhất vào 4h30 chiều ngày 28/9/2021

Nếu bài dễ thì cố gắng tự làm bạn nhé.

Bài 1:

a) \(2x+3=5\)

\(\Leftrightarrow2x=5-3=2\)

\(\Leftrightarrow x=2:2=1\)

Vậy: x=1

b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)

Vậy: \(x\in\left\{3;0\right\}\)

c) \(3x+4=2x-7\)

\(\Leftrightarrow2x-3x=7+4\)

\(\Leftrightarrow-1x=11\)

\(\Leftrightarrow x=-11\)

Vậy: x=-11

d) \(\left(4x-1\right)^3=27\)\(=3^3\)

\(\Rightarrow4x-1=3\)

\(\Leftrightarrow4x=3+1=4\)

\(\Leftrightarrow x=4:4=1\)

Vậy: x=1

e) \(\left(x-7\right).2=3.\left(2x+4\right)\)

\(\Leftrightarrow2x-14=6x+12\)

\(\Leftrightarrow2x-6x=12+14\)

\(\Leftrightarrow-4x=26\)

\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)

Vậy: \(x=\frac{13}{-2}\)