a)=>3x=33

=>x=11

b)x²⁰⁰=x

=>x²⁰⁰-x=0

=>x(x¹⁹⁹-1)=0=>x=0 hoặc x=1

c)=>1170:(x-13)=339-300=39

=>x-13=1170:39=30

=>x=43

d)=>7x=28

=>x=4

1, x^2 . x^3 = 3^7 : 3^2

       x^5     = 3^5

=> x = 3

2, x - 18 : 3 = 12

    x - 6       = 12

    x            = 12 + 6

    x            = 18

3, (x - 18) : 2 = 12

     x - 18       = 12 . 2

     x - 18       = 24

     x             = 24 + 18

     x             = 42

4, x^2 = 16

    x^2 = 4^2

=> x = 4

x=4 nha bn

k k nha

mk k lại cho!

1 .x+5  và 2y+1 là Ư(42) lập bảng tính

2.vd tc chia hết 

a) \(\left(19x+2\times5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Rightarrow\left(19x+50\right):14=5^2-4^2=25-16=9\)

\(\Rightarrow19x+50=126\)

\(\Rightarrow19x=76\Rightarrow x=4\)

Vậy x = 4

b) \(2\times3^2=10\times3^{12}+8\times27^4\)

\(\Rightarrow2\times3^2=10\times\left(3^3\right)^4+8\times27^4\)

\(\Rightarrow2\times3^2=27^4\times\left(10+8\right)\)

\(\Rightarrow18=27^4\times18\)

\(\Rightarrow27^4\times18-18=0\Rightarrow18\times\left(27^4-1\right)=0\)

=> Không thấy biến x đâu cả

c) Ta thấy 3³ = 27

\(\Rightarrow3^{2x-5}=3^3\Rightarrow2x-5=3\Rightarrow2x=8\Rightarrow x=4\)

Vậy x = 4

d) \(3^{x+1}-x=80\Rightarrow3^{x+1}=81\)

Ta thấy 3⁴ = 81

\(\Rightarrow3^{x+1}=3^4\Rightarrow x+1=4\Rightarrow x=3\)

Vậy x = 3

A=7 B=1 OR =0 C=2 D=4.5.6

a: \(2^{x}\cdot4=128\)

=>\(2^{x}=\frac{128}{4}=32=2^5\)

=>x=5

b: \(x^{15}=x\)

=>\(x^{15}-x=0\)

=>\(x\left(x^{14}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{14}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{14}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

c: \(\left(2x+1\right)^3=125\)

=>\(\left(2x+1\right)^3=5^3\)

=>2x+1=5

=>2x=5-1=4

=>\(x=\frac42=2\)

d: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-5-1\right)\left(x-5+1\right)=0\)

=>\(\left(x-5\right)^4\cdot\left(x-6\right)\left(x-4\right)=0\)

=>\(\left[\begin{array}{l}x-5=0\\ x-6=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=6\\ x=4\end{array}\right.\)

\(\frac{9^{x+y}}{3^{5y}}=243\Leftrightarrow\frac{9^{x+y}}{3^{5y}}=\frac{9^{4+1}}{3^{5\cdot1}}\Leftrightarrow x=4,y=1..\)

vậy x=4.y=1

Ai giúp mk đi làm ơn đó mai mk phải nộp rùi T_T