Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A . 89 - ( 73 - x ) = 20
73 - x = 89 - 20
73 - x = 69
\(\Rightarrow\)x = 4
B .
Bo may la binh day k di hieu ashdbfgbgygygggydfsghuyfhdguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu3
a) 2x = 16 e) 12x = 144
2x = 24 12x = 122
=> x = 4 => x = 2
b) 2x+1 = 16 các câu còn lại tương tự nhé nhiều quá
2x+1 = 24
x + 1 = 4
=> x = 3
c) 5x+1 = 125
5x+1 = 53
x + 1 = 3
=> x = 2
d) 52x - 1 = 125
52x-1 = 53
2x - 1 = 3
2x = 4
=> x = 2
a)Ta có : 2x = 16
2x = 24
=> x = 4
b) Ta có: 2x+1 = 16
2x+1 = 24
=> x+1 = 4
=> x = 4-1
=> x = 3
Mấy câu sau tương tự vậy đó để hôm khác mình làm tiếp cho bây giờ mình đi ngủ đã buồn ngủ quá hihi ! ^-^
Học tốt nha bạn !
a) x.(x+1)>0
b) (x-1).(x-2)<0
c) x mũ 3=0
d) (x-1) mũ 5= (x-1) mũ 7
e) x mũ 4 =16
Nhanh ak, giúp mik với
a)x2>-1
=>x>-1
b)\(\hept{\begin{cases}x-1< 0\\x-2< 0\end{cases}=>\hept{\begin{cases}x< 1\\x< 2\end{cases}}}\)
c) x3=0
=>x=0
d) chịu
e) x4=16
=>x=2
bài nào mk giải cho bợn đều đúng.....
nhớ tích mk nha
E,x^4=16=>x=2
C,x^3=0=>x=0
làm đc 2 câu, hình như bnaj thiếu đk của bài
a,5mũ 36=(5mũ3)mũ12=125 mũ12
11^24=(11^2)12=121^12
vì 121<125 nên 5^36>11^24
a)2^x + 1 . 2^2009 = 2^2010
=> 2^x + 1 + 2009 = 2^2010
=>2^x + 2010 = 2^2010
=>x + 2010 = 2010
=>x = 2010 - 2010 = 0
b)Chắc ý bạn là 6^17 : 6^15 + 44 : 11 đúng không?
Nếu thế thì mình sẽ giải như sau:
7x - 2x = 6^17 : 6^15 + 44 : 11
7x - 2x = 6^17 - 15 + 44 : 11
7x - 2x = 6^2 + 44 : 11
7x - 2x = 6^2 + 4
7x - 2x = 36 + 4
7x - 2x = 40
(7 - 2)x = 40
5x = 40
x = 40 : 5
x = 8
c)0 : x = 0
=>x ϵ N*
3^x = 9
3^x = 3^2
=> x = 2
d) x^4 = 16; 2^x : 2^5 = 1
x^4 = 2^4
x = 2
2^x : 2^5 = 1
2^x : 2^5 = 2^0
2^x - 5 = 2^0
=>x - 5 = 0
=>x = 0 + 5 = 5
e)|x - 2|= 0
<=> x - 2 = 0
<=> x = 0 + 2
<=> x = 2
g)4^x = 64
4^x = 4^3
x = 3
9^x - 1 = 9
9^x - 1 = 9^1
x - 1 = 1
x = 1 + 1
x = 2
câu a:
3\(^2\) x 5 + 2\(^3\) x 10 - 81 : 3
= 9 x 5 + 8 x 10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
Câu c:
100 : 5\(^2\) + 7 x 3\(^2\)
= 100 : 25 + 7 x 9
= 4 + 63
= 67
\(a,\left(-5\right).\left|x\right|=-75\)
\(\left|x\right|=\frac{-75}{-5}=15\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
Vậy....
\(b,\left(-6\right)^3.x^2=-1944\)
\(-216.x^2=-1944\)
\(x^2=9\)
\(\Rightarrow x=\pm3\)
Vậy....
\(d,\left|9-x\right|=-7+64\)
\(\left|9-x\right|=57\)
\(\Rightarrow\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}\Rightarrow\orbr{\begin{cases}x=-48\\x=66\end{cases}}}\)
Vậy...
\(e,\left|x+101\right|-\left(-16\right)=\left(-43\right).\left(-5\right)\)
\(\left|x+101\right|+16=215\)
\(\left|x+101\right|=199\)
\(\Rightarrow\orbr{\begin{cases}x+101=199\\x+101=-199\end{cases}\Rightarrow\orbr{\begin{cases}x=98\\x=-300\end{cases}}}\)
Vậy..
hok tốt!!
a,\(\left(-5\right).\left|x\right|=-75\)
\(=>\left|x\right|=-75:\left(-5\right)=15\)
\(=>\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
b,\(\left(-6\right)^3.x^2=-1944\)
\(=>\frac{1944}{216}=x^2\)
\(=>x=\sqrt{\frac{1944}{216}}=3\)
CẢM ƠN MỌI NGƯỜI NHIỀU Ạ
\(\left(3-2x\right)^2=25\)
\(=>\left(3-2x\right)^2=5^2\)
\(=>3-2x=5\)
\(=>-2x=5-3=2\)
\(=>x=\frac{2}{-2}=-1\)
\(g,3.\left(x-5\right)-7.\left(4-x\right)=x-7\)
\(3x-15-28-7x=x-7\)
\(3x-7x-x=-7+15+28\)
\(-5x=36\)
\(x=\frac{-36}{5}\)
\(h,\left(x^2-36\right).\left(x^2-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2-36=0\\x^2-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=36\\x^2=3\left(vôlis\right)\end{cases}\Rightarrow\orbr{\begin{cases}x=\pm6\\\end{cases}}}}\)
\(i,\left(x^2-36\right).\left(x^2-3\right)< 0\)
\(\Rightarrow\left(x^2-36\right)và\left(x^2-3\right)\)trái dấu
Vì \(\left(x^2-36\right)< \left(x^2-3\right)\)
\(\Rightarrow\orbr{\begin{cases}x^2-36< 0\\x^2-3>0\end{cases}\Rightarrow\orbr{\begin{cases}x^2< 36\\x^2>0\end{cases}}}\)
\(\Rightarrow0< x^2< 36\)
\(\Rightarrow x^2\in\left\{1;4;9;16;25\right\}\)
\(\Rightarrow x\in\left\{\pm1;\pm2;\pm3;\pm4;\pm5\right\}\)
n,\(x^2+5x=0\)
\(=>x.\left(x+5\right)=0\)
\(=>\orbr{\begin{cases}x=0\\x+5=0\end{cases}=>\orbr{\begin{cases}x=0\\x=-5\end{cases}}}\)
cảm ơn quân và tiểu thư nha
\(a,\left(-5\right).|x|=-75\)
\(|x|=15\Leftrightarrow x=\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
\(b,\left(-6\right)^3.x^2=-1944\)
\(-216.x^2=-1944\)
\(x^2=9\Leftrightarrow x^2=3^2\Leftrightarrow\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
\(c,\left(3-2x\right)^2=25\)
\(\left(3-2x\right)^2=\sqrt{25}=5^2\)
\(Th1:3-2x=5\Leftrightarrow2x=-2\Leftrightarrow x=-1\)
\(Th2:3-2x=-5\Leftrightarrow2x=8\Leftrightarrow x=4\)
\(d,|9-x|=-7+64\)
\(|9-x|=57\)
\(Th1:9-x=57\Leftrightarrow x=-48\)
\(Th2:9-x=-57\Leftrightarrow x=66\)
\(g,3\left(x-5\right)-7.\left(4-x\right)=x-7\)
\(3x-15-28+7x=x-7\)
\(3x+7x-x=-7+15+28\)
\(9x=36\Leftrightarrow x=4\)