\(35-\left|2x-1\right|=14\)

\(\Leftrightarrow\left|2x-1\right|=21\)

\(\Leftrightarrow\orbr{\begin{cases}2x-1=21\left(x\ge\frac{1}{2}\right)\\2x-1=-21\left(x< \frac{1}{2}\right)\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=22\\2x=-20\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=11\left(TM\right)\\x=-10\left(TM\right)\end{cases}}\)

\(35-|2x-1|=14\)

\(|2x-1|=21\)

\(\Rightarrow\orbr{\begin{cases}2x-1=21\\2x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}2x=22\\2x=-20\end{cases}\Rightarrow}\orbr{\begin{cases}x=11\\x=-10\end{cases}}}\)

Ta có:[2x-1]=35-14

=>[2x-1]=21

=>2x=21+1

=>2x=22

=>x=22/2

=>x=11

35-|2x-1|=14

|2x-1|=35-14

|2x-1|=21

* 2x-1=21                  * 2x-1=-21

  2x=21+1                    2x=-21+1                      

  2x=22                        2x=-20

    x=22:2                       x=-20:2

    x=11                          x=-10

Vậy x=11 hoặc x=-10

Trl:

\(35-\left|2x-1\right|=14\)

\(\Rightarrow\left|2x-1\right|=35-14\)

\(\Rightarrow\left|2x-1\right|=21\)

 Có 2 TH sau :

2x - 1 = 21 hoặc 2x - 1 = - 21

2x = 21 + 1 hoặc 2x = -21 + 1

2x = 22 hoặc 2x = -20

x = 11 hoặc x = -10

Vậy \(x\in\left\{11;-10\right\}\)

35-|2x-1|=14

|2x-1|=35-14=21

=>2x-1=21, -21

TH1: 2x-1=21

2x=21+1=22

x=22:2=11

TH2: 2x-1=-21

2x=-21+1=-20

x=-20:2=-10

Vay x=11, -10