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20 tháng 3 2016

93 nhé các bạn !!!!

7 tháng 10 2016

93.Mình chắc luôn bạn

10 tháng 10 2016

Cách làm sao vậy chỉ mình với

14 tháng 12 2016

Cảm ơn mấy bạn. Tiện thể mk cũng tìm đc cách giải chi tiết luôn rồi. Số cần tìm có dạng 10a + b (a > 0, b >= 0), vậy theo đề bài thì ta có:

10a + b = 7(a + b) + 9

Đến đây thì giải như một bài tìm a, b thông thường.

10a + b  = 7a + 7b + 9

10a - 7a = 7b - b + 9

3a = 6b + 9

6b + 9 = 3a

3a - 6b = 9

3a : 3 - 6b : 3 = 9 : 3 (Số trừ và số bị trừ cùng giảm đi bao nhiêu thì hiệu giảm đi bấy nhiêu)

a - 2b = 3

2b = a - 3

b = (a - 3) : 2

b = (a - 3) : 2

Vì b >= 0 nên (a - 3) : 2 >= 0.

=> a >= 3

=> a = 3; 4; 5; 6; 7; 8; 9

Nếu a = 3 thì b = (3 - 3) : 2 = 0 (Loại)

Nếu a = 4 thì b = (4 - 3) : 2 = 1/2 (Loại)

Nếu a = 5 thì b = (5 - 3) : 2 = 1

Nếu a = 6 thì b = (6 - 3) : 2 = 3/2 (Loại)

Nếu a = 7 thì b = (7 - 3) : 2 = 2

Nếu a = 8 thì b = (8 - 3) : 2 = 5/2 (Loại)

Nếu a = 9 thì b = (9 - 3) : 2 = 3

Vậy số cần tìm có thể là 51; 72; 93. (Trong 3 số này các bạn muốn lấy cái nào làm đáp án cuối cùng cũng đc)

17 tháng 7 2018

93 la đung thât

21 tháng 4 2022

93 nha

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10 tháng 2 2018

Gọi số đó là: ab

Ta có:

ab : ( a + b ) = 7 ( dư 9 )

10a + b = 7(a+b) + 9

10a + b = 7a + 7b + 9

3a = b + 9

a = ( b + 9 ) : 3

Ta có các trường hợp:

TH1: b + 9 = 9

\(\Rightarrow\)a = 0 ; b = 0 ( loại vì a là hàng chục, không thể bằng 0 )

TH2: b + 9 = 18

\(\Rightarrow\)b = 9 ; a = 6 ( loại vì 69 : 15 = 4 ( dư 9 )

TH3: b + 9 = 27

\(\Rightarrow\)b = 18 ; a = 9 ( loại )

Tương tự bạn tìm các trường hợp tiếp theo

27 tháng 2 2016

93  nha ban yeu quy

27 tháng 2 2016

Giải : 
Gọi X là chữ số hàng chục của số cần tìm (X là số tự nhiên và X>=1) "vì hàng chục ko có =0 đc" 
Gọi Y là chữ số hàng đơn vị của số cần tìm (Y là số tự nhiên và Y>=0) 
Vậy số cần tìm có dạng : 10X+Y 
Theo đề bài ta có : 
10X+Y = 7*(X+Y) + 9 
<=> 3X - 6Y = 9 
<=> X - 2Y = 3 
<=> Y= (X-3):2 
Vì Y>=0 => (X-3): 2 >=0 => X>=3 
Ta có 
X 3 4 5 6 7 8 9 
Y - 1/2 1 3/2 2 5/2 3 

Vậy các số đó là : 51; 72; 93 

20 tháng 3 2016

93 vì :

tổng của các chữ số trong số tự nhiên đó là:

9+3=12

kết quả của số tự nhiên đó chia cho tổng các chữ số của số đó là :

93/12=7(dư 9)

số tự nhiên đó là :93

Đáp số :số tự nhiên đó là 93

7 tháng 6 2018

goi chu so hang don vi la b;so hang chuc la a

ab=(a+b)x7+9

ab=ax10+b

ax10+b=ax7+9

ax3=bx6+*

ax3=3x(bx2+3)

a=bx2+3(chia 2 ve cho 3)

ta co:b=1;a=5=>51(loai)

b=2;a=7=>72(loai)

b=3;a=9=>93

Vay so can tim la 93

22 tháng 3 2016

la so 93.....dung 100%

Ai tích mk mk sẽ tích lại

26 tháng 1 2016

ko thể dư 9 nhan bn ko bao giờ số dư lớn hơn số chia nha

26 tháng 1 2016

có thể thế hoặc có thể không

6 tháng 8 2019

Gọi số Cần tìm là ab .Theo đề bài ta có
ab=2x( a+b)+7
10 x a +b= a x 2 + b x 2 + 7 ( phân tích cấu tạo số ) 
10 x a +b - a x2 -b = a x2 + b x2 + 7-a x2 -b (cùng trừ a x2+b)
8xa = b + 7
Vì b<10 nên 8x a=b+7<10+7=17 và phải là một số chia hết cho 8
Vậy nếu 8xa=8 thì a=1 và b=1 có số 11 nhưng 11:(1+1)=5 dư 1 loại 
Nếu 8xa=16 thì a=2 và b=9 có số 29:(2+9)=2 dư 7 lấy 
Số Cần tìm là 29

7 tháng 10 2019

Ta có: 10a + b = 2a + 2b + 7
8a = b + 7
Do 0<= b <= 9 nên 7<= 8a <= 16 nên a chỉ có thể là 1 hoặc 2.
a = 1, b = 1 , không thỏa mãn
a = 2, b = 9, thỏa mãn

13 tháng 3 2017

Ta có: 10a + b = 2a + 2b + 7 8a = b + 7 Do 0<= b <= 9 nên 7<= 8a <= 16 nên a chỉ có thể là 1 hoặc 2. a = 1, b = 1 , không thỏa mãn a = 2, b = 9, thỏa mãn

22 tháng 3 2016

gọi số đó là ab ta có : 

ab = ( a + b ) x 9 + 1

10 x a + b = 9 x a + 9 x b + 1

a = 8 x b + 1

vì 0<a <9 hoặc =9 nên 8 x b + 1 < 9 hoặc = 9  vì a không thể là số có 2 chữ số

                                  8 x b = 9-1 

                                  8 x b = 8

suy ra b =1 và a = 9 

 số đó là 91