a) 2001 x 757 + 2002 x 233

    = 2001 x 757 + (2001 + 1) x 233

    = 2001 x 757 + 2001 x 233 + 1 x 233

    = 2001 x (757+233) + 233

    = 2001 x 1000 + 233

    = 2001000 + 233

    = 2001233

a) 2001x757+2002x243

=2001 x 757+ (2001+1) x233

=2001 x757+2001x233+1 x233

=2001x(757+233)+233

=2001x1000 +233

=201000+233

=2001233

b)(m:1-m x1):(mx2001+m+1)

=(m-m):(mx2001+m+1)

=0:(mx2001+m+1)

=0

   Học tốt

a) 2001 x 767 + 2002 x 233

= 2002 x 767 – 767 + 2002 x 233

= 2002 x (767+ 233) – 767

= 2002 x 1000 – 767

= 2002000 – 767

= 2001233

   b) (m : 1 – m x 1) : (m x 2001 + m + 1)

= (m – m) : (m x 2001 + m + 1)

= 0 : (m x 2001 + m + 1)                                 

= 0

- HT_ #lie -

\(\left(m:1-m.1\right):\left(m.2001.m+1\right)\)

\(=0:A=0\)

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Tìm m biết: ( m : 1 – m x 1) : ( m × 2001 + m + 1)

a: \(\frac15\times m=\frac67\)

=>\(m=\frac67:\frac15=\frac67\times5=\frac{30}{7}\)

b: \(m:\frac34=\frac{10}{9}\)

=>\(m=\frac{10}{9}\times\frac34=\frac{30}{36}=\frac56\)

c: \(m+\frac29=\frac56\)

=>\(m=\frac56-\frac29=\frac{15}{18}-\frac{4}{18}=\frac{11}{18}\)

d: \(\frac45-m=\frac{7}{15}\)

=>\(m=\frac45-\frac{7}{15}=\frac{12}{15}-\frac{7}{15}=\frac{5}{15}=\frac13\)

bằng 0
 

A = A hay A = bao nhiêu?

1/2, 2/3