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a) \(\left(2x^2-3x\right)\left(5x^2-2x+1\right)\)
\(=10x^4-4x^3+2x^2-15x^3+6x^2-3x\)
\(=10x^4-19x^3+8x^2-3x\)
b) \(\left(x+1\right)\left(x^2-x+1\right)-x\left(x+3\right)\left(x+5\right)\)
\(=x^3+1-x\left(x^2+8x+15\right)\)
\(=x^3+1-x^3-8x^2-15x\)
\(=-8x^2-15x+1\)
a) Đề:............
= 6x4 - 15x3 - 12x2
b) Đề:...........
= x2 + 2x + 1 + x2 + 3x - 2x - 6 - 4x
= 2x2 - x - 5
a: \(=\dfrac{4x-8+2x+4-8}{\left(x-2\right)\left(x+2\right)}=\dfrac{6x-12}{\left(x-2\right)\left(x+2\right)}=\dfrac{6}{x+2}\)
b: \(=\dfrac{-x+7x-4}{3x-2}=\dfrac{6x-4}{3x-2}=2\)
c: \(=\dfrac{x}{2x+1}-\dfrac{1}{\left(2x+1\right)\left(2x-1\right)}-\dfrac{\left(x-2\right)}{2x-1}\)
\(=\dfrac{2x^2-x-1-\left(x-2\right)\left(2x+1\right)}{\left(2x+1\right)\left(2x-1\right)}\)
\(=\dfrac{2x^2-x-1-2x^2-x+4x+2}{\left(2x+1\right)\left(2x-1\right)}\)
\(=\dfrac{2x+1}{\left(2x+1\right)\left(2x-1\right)}=\dfrac{1}{2x-1}\)
d: \(=\dfrac{5}{2x-3}+\dfrac{2}{2x+3}+\dfrac{2x-33}{4x^2-99}\)
\(=\dfrac{10x+15+4x-6+2x-33}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{16x-24}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{8}{2x+3}\)
a,\(2xy.3x.2y^3=\left(2.3.2\right)\left(xx\right)\left(yy^3\right)=12x^2y^4\)
b, \(x\left(x^2-2x+5\right)=x^3-2x^2+5x\)
c, \(\frac{3x^2-6x}{3x}=x-2\)
d, \(\frac{x^2-2x+1}{x-1}=\frac{\left(x-1\right)^2}{x-1}=x-1\)
\(\left(x^2-2x\right)\left(3x^2-x+1\right)\)
\(=3x^4-x^3+x^2-6x^3+2x^2-2x\)
\(=3x^4-7x^3+3x^2-2x\)
=.= hok tốt!!
\(\left(x^2-2x\right)\times\left(3x^2-x+1\right)\)
\(=3x^4-x^3+x^2-6x^3+2x^2-2x\)
\(=3x^4-9x^3+3x^2-2x\)
\(\left(x^2-2x\right)\left(3x^2-x+1\right)\)
\(=3x^4-x^3+x^2-6x^3+2x^2-2x\)
\(=3x^4-7x^3+3x^2-2x\)
Học tốt nhé!
(x^2-2x)*(3x^2-x+1)
=x^2*3x^2-x^2*x+x^2*1-2x*3x^2+2x*x-2x*1
=3x^4-x^3+x^2-6x^3+2x^2-2x
=3x^4+(-x^3-6x^3)+(x^2+2x^2)-2x
=3x^4-7x^3+3x^2-2x
x2-2x * 3x2-x+1= (X2 x 3X2 - X2 x X + X2 + 1) (- 2X x 3X2 +2X x X - 2X x1
=3X4 - x3 +x2 - 6x3 + 2x2 - 2x
= 3x4 - 7x3 + 3x3 - 2x