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a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}\)
\(=\frac{2}{3}-\frac{2}{5}=\frac{4}{15}\)
b) \(\frac{-2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}\)
\(=\frac{5}{8}\left(-\frac{2}{5}+\frac{3}{5}\right)\)
\(=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)
c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}\)
\(=0,25-1,5+0,5\cdot2,4\)
\(=0,25-1,5+1,2=-0,05\)
a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}=\frac{2}{3}-\frac{2}{5}=\frac{10-6}{15}=\frac{4}{15}\)
b) \(-\frac{2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}=\frac{5}{8}\cdot\left(-\frac{2}{5}+\frac{3}{5}\right)=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)
c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{1}{2}\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{6}{5}=\frac{5-30+24}{20}=-\frac{1}{20}\)
~~ Chúc bạn học tốt ~~
\(\frac{-3}{14}\) - \(\frac{5}{-14}\)
= \(\frac{-3}{14}+\frac{5}{14}\)
= \(\frac{2}{14}\)
= \(\frac17\)
- \(\frac54\) - \(\frac34\)
= -(\(\frac54+\frac34\))
= - \(\frac84\)
= - 2
\(\frac{15}{6}-\frac{-10}{20}\)
= \(\frac52\) + \(\frac12\)
= \(\frac62\)
= 3
\(\frac{26}{-35}\) - \(\frac{6}{35}\)
= - (\(\frac{26}{35}\) + \(\frac{6}{35}\))
=- \(\frac{32}{35}\)
Câu a:
(4 5/37 - 3 4/5 + 8 15/29) - (3 5/37 - 6 14/29)
= (4 5/37 - 3 5/37) + (8 15/29 + 6 14/29) - 3 4/5
= 1 + 15 - 3 4/5
= 16 - 3 - 4/5
= 13 - 4/5
= 61/5
Câu b:
(2\(\frac56\) + 1\(\frac49\)) : (10\(\frac{1}{12}\) - 9\(\frac12\))
= (17/6 + 13/9) :(121/12 - 19/2)
= (51/18 + 26/18) :(121/12 - 114/2)
= 77/18 : 7/12
= 77/18 x 12/7
= 22/3
\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)
\(A=1+\frac{1}{2}\)
\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)
\(A=\frac{3}{2}\)
a, 3 \(\frac{14}{19}\)+ \(\frac{13}{17}\)+ \(\frac{35}{43}\)+ 6\(\frac{5}{19}\)+ \(\frac{8}{43}\)= \(\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}=\)\(9+1+\frac{13}{17}=8+\frac{13}{17}=8\frac{13}{17}\)
b, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+1\frac{5}{7}\)\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)+1\frac{5}{7}\)\(=\frac{-5}{7}.1+1\frac{5}{7}\)\(=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)
Chúc bn học tốt
\(3\frac{14}{19}+\frac{13}{17}+\frac{35}{43}+6\frac{5}{19}+\frac{8}{43}\)
\(=\left(3\frac{14}{19}+6\frac{5}{19}\right)+\left(\frac{35}{43}+\frac{8}{43}\right)+\frac{13}{17}\)
\(=10+1+\frac{13}{17}=11+\frac{13}{17}=11\frac{13}{17}\)
a) \(\left(4\frac{1}{9}+3\frac{1}{4}\right)\cdot2\frac{1}{4}+2\frac{3}{4}\)
\(=7\frac{13}{36}\cdot2\frac{1}{4}+2\frac{3}{4}\)
\(=16\frac{9}{16}+2\frac{3}{4}\)
\(=19\frac{5}{16}\)
b)\(1+\left(\frac{9}{10}-\frac{4}{5}\right)\div3\frac{1}{6}\)
\(=1+\frac{1}{10}\div\frac{19}{6}\)
\(=1+\frac{3}{95}=1\frac{3}{95}\)
MK LÀM CHO BẠN 2 Ý THÔI NHA.
K MK NHA. CHÚC BN HỌC TỐT. ^_^
c) \(\left(-7+|13|\right)-\left(13-|-7|-25\right)-\left(25-|-10|-9\right)\)
\(=-7+13-13+7+25-25+10+9\)
\(=\left(-7+7\right)+\left(13-13\right)+\left(25-25\right)+10+9\)
\(=0+0+0+10+9=10+9=19\)
MK LÀM XONG RỒI. K MK NHA. KB
\(\frac{5}{-8}+\frac{14}{25}-\frac{6}{10}\)
\(=\frac{-5}{8}+\frac{14}{25}-\frac{3}{5}\)
\(=\frac{-125}{200}+\frac{112}{200}-\frac{120}{200}=\frac{-133}{200}\)
Chúc bạn học tốt!!
\(-\frac{133}{200}\)
=\(\frac{-5.50}{8.50}+\frac{14.16}{25.16}-\frac{6.40}{10.40}\)
=\(\frac{-250}{400}+\frac{224}{400}-\frac{240}{400}\)
=\(\frac{-266}{400}\)
=\(\frac{-133}{200}\)
\(\frac{5}{-8}\) + \(\frac{14}{25}\) - \(\frac{6}{10}\) = \(\frac{-5}{8}\)+ \(\frac{14}{25}\) - \(\frac{6}{10}\)
= \(\frac{-125}{200}\)+ \(\frac{112}{200}\)- \(\frac{120}{200}\)
= \(\frac{-133}{200}\)
Chúc bạn học tốt!!