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a, 36:{336:[200–(12+8.20)]}
= 36:{336:[200–(12+160)]}
= 36:{336:[200–172]}
= 36:{336:28}
= 36:12 = 3
b, {145–[130–(246–236)]:2}.5
= {145–[130–10:2]}.5
= {145–130}.5
= 20.5 = 100
c, 100:{250:[450–(4. 5 3 – 2 2 .25]}
= 100:{250:[450–400]}
= 100:{250:50}
= 100:5 = 20
d, 798+100:[16–2.( 5 2 –22)]
= 798+100:10
= 798+10 = 808
e, (6954+1525:5+47.19).(29–58.2)
= (6954+1525:5+47.19).0 = 0
f, 2 4 .157– 2 4 .58+16
= 16.(157–58+1) = 1600
a) \(3^{7} \cdot 27^{5} \cdot 81^{3}\)
\(3^{7} \cdot \left(\right. 3^{3} \left.\right)^{5} \cdot \left(\right. 3^{4} \left.\right)^{3} = 3^{7} \cdot 3^{15} \cdot 3^{12} = 3^{7 + 15 + 12} = 3^{34} .\)
b) \(100^{6} \cdot 1000^{5} \cdot 10 \textrm{ } 000^{3}\)
\(\left(\right. 10^{2} \left.\right)^{6} \cdot \left(\right. 10^{3} \left.\right)^{5} \cdot \left(\right. 10^{4} \left.\right)^{3} = 10^{12} \cdot 10^{15} \cdot 10^{12} = 10^{39} .\)
c) \(\frac{36^{5}}{18^{5}}\)
\(\left(\left(\right. \frac{36}{18} \left.\right)\right)^{5} = 2^{5} = 32.\)
d) \(24 \cdot 5^{2} + 5^{2} \cdot 5^{3}\)
\(= 24 \cdot 25 + 25 \cdot 125 = 600 + 3125 = 3725.\)
e) \(\frac{125^{4}}{5^{8}}\)
\(\left(\right. 5^{3} \left.\right)^{4} : 5^{8} = 5^{12} : 5^{8} = 5^{12 - 8} = 5^{4} = 625.\)
TÓM lại là a) \(3^{34}\)
b) \(10^{39}\)
c) \(32\)
d) \(3725\)
e) \(625\)
bạn muốn chép đáp án hay sem cách làm///??
a: \(3^7\cdot27^5\cdot81^3\)
\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)
\(=3^7\cdot3^{15}\cdot3^{12}=3^{7+15+12}=3^{34}\)
b: \(100^6\cdot1000^5\cdot10000^3\)
\(=\left(10^2\right)^6\cdot\left(10^3\right)^5\cdot\left(10^4\right)^3\)
\(=10^{12}\cdot10^{15}\cdot10^{12}=10^{15+12+12}=10^{39}\)
c: \(36^5:18^5=\left(\frac{36}{18}\right)^5=2^5=32\)
d: \(24\cdot5^2+5^2\cdot5^3\)
\(=5^2\left(24+5^3\right)\)
\(=25\cdot\left(24+125\right)=25\cdot149=3725\)
e: \(125^4:5^8=\left(5^3\right)^4:5^8=5^{12}:5^8=5^{12-8}=5^4\)
a: \(=5^2+16\cdot125-1=24+2000=2024\)
b: \(=-145+55+42-42+90=-90+90=0\)
c: =-4+2+6+8-10+13-15=4+8-10-2=12-10-2=0
a) \(\left(\frac{-1}{6}+\frac{5}{-12}\right)+\frac{7}{12}=\left(\frac{-2}{12}+\frac{-5}{12}\right)+\frac{7}{12}=\left(\frac{-7}{12}\right)+\frac{7}{12}=0\)
b)\(\frac{7}{36}-\frac{8}{-9}+\frac{-2}{3}=\frac{7}{36}+\frac{32}{36}-\frac{24}{36}=\frac{15}{36}=\frac{5}{12}\)
c) \(\frac{3}{5}-\frac{2}{5}.\frac{10}{12}=\frac{3}{5}-\frac{2}{5}.\frac{5}{6}=\frac{3}{5}-\frac{1}{3}=\frac{9}{15}-\frac{5}{15}=\frac{4}{15}\)
d) \(\frac{2}{\left(-3\right)^2}+\frac{5}{-13}-\frac{-3}{4}=\frac{2}{9}-\frac{5}{13}+\frac{3}{4}=\frac{8}{36}-\frac{15}{36}+\frac{27}{36}=\frac{5}{9}\)
ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac
\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)
\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)
\(A=\frac{4-1}{36+12}\)
\(A=\frac{3}{48}=\frac{1}{16}\)
3.Tìm x biết:
a) \(2-x=17-\left(-5\right)\)
\(2-x=22\)
\(x=2-22\)
\(x=-20\)
Vậy \(x=-20\)
b) \(2x-6=-3-\left(-7\right)\)
\(2x-6=4\)
\(2x=6+4\)
\(2x=10\)
\(x=10:2\)
\(x=5\)
Vậy \(x=5\)
c) \(\left(3x-6\right).3=3^4\)
\(\left(3x-6\right).3=81\)
\(3x-6=81:3\)
\(3x-6=27\)
\(3x=27+6\)
\(3x=33\)
\(x=33:3\)
\(x=11\)
Vậy \(x=11\)