a) \(3.5^2-16:2^2\)

\(=3.25-16.4\)

\(=75-64\)

\(=11\)

b) \(17.85+15.17-120\)

\(=17.\left(85+15\right)-120\)

\(=17.100-120\)

\(=1700-120\)

\(=1580\)

c) \(\left(3^{15}.4+5.3^{15}\right):3^{16}\)

\(=\left[3^{15}.\left(4+5\right)\right]:3^{16}\)

\(=\left[3^{15}.9\right]:3^{16}\)

\(=\left[3^{15}.3^2\right]:3^{16}\)

\(=3^{17}:3^{16}\)

\(=3\)

a. 3.5² - 2⁴ : 2² = 3.5²- 2² = 3.25-4= 75-4 =71

b. 17.(85+15) - 120 = 17.100-120=1700-120=1580

c. |3¹⁵.(4+5)| :3¹⁶= (3¹⁵.9) : 3¹⁶= 3¹⁵.3² : 3¹⁶= 3¹⁷:3¹⁶=3

dấu | là ngoặc vuông bn nhé

.(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)

=(5.3^11+4.3^12):(3^9.5^2-3^9.2^3)

=(5.3^11+4.3^11.3):[3^9.(5^2-2^3)]

=(5.3^11+12.3^11):[3^9.17]

=3^11.(5+12):(3^9.17)

=(3^11.17):(3^9.17)

=17.(3^11:3^9)

=17.3^2

=17.9

=153

tk nha

bai cua kacura dung nhung 4 dong cuoi la sai to

co khong co kieu phan phoi nhu vay ma phai thay la 3^11:3^9( nhan 17 chia 17 thi khi nao cung nhan duoc ket qua giong nhau)

                                                                           =3^2=9

a: \(35\cdot20+125:5^2\)

\(=700+\frac{125}{25}\)

=700+5=705

b: \(5^2\cdot8-60:2^2\)

\(=25\cdot8-60:4\)

=200-15

=185

c: \(4500:15+3^4\cdot10\)

=300+81*10

=300+810

=1110

d: \(175-\left\lbrack3\cdot5^2-5\cdot3^2\right\rbrack\)

\(=175-\left(3\cdot25-5\cdot9\right)\)

=175-(75-45)

=175-30

=145

e: 555:5+\(256:16^2\)

=111+256:256

=111+1

=112

c: Sửa đề: \(\left(5\cdot3^5+17\cdot3^4\right):6^2\)

\(=\frac{5\cdot3^5+17\cdot3^4}{6^2}\)

\(=\frac{3^4\left(5\cdot3+17\right)}{3^2\cdot2^2}=\frac{3^2\cdot\left(15+17\right)}{2^2}=3^2\cdot\frac{32}{2^2}=9\cdot8=72\)

b: Sửa đề: \(5^3\cdot2+\left(2^3\cdot4^0\right):2^3\)

\(=125\cdot2+8:2^3\)

=250+1

=251

(3¹⁵x4+5.3¹⁵):3¹⁵

⁼⁽57395628+71744535):3¹⁵

=129140163:3¹⁵

=9

Ta có: \(\frac{3^7\cdot2^5+3^8}{3^6\cdot5^2-3^6\cdot18}+\frac{2^5\cdot43+2^5}{2^5\cdot5^2-2^5\cdot3}\)

\(=\frac{3^7\left(2^5+3\right)}{3^6\left(5^2-18\right)}+\frac{2^5\left(43+1\right)}{2^5\left(25-3\right)}=\frac{3\cdot\left(32+3\right)}{25-18}+\frac{44}{22}\)

\(=\frac{3\cdot35}{7}+2=3\cdot5+2=15+2=17\)

123+456+777+444=(123+777)+(456+444)

=1000+1000=2000