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a: \(35\cdot20+125:5^2\)
\(=700+\frac{125}{25}\)
=700+5=705
b: \(5^2\cdot8-60:2^2\)
\(=25\cdot8-60:4\)
=200-15
=185
c: \(4500:15+3^4\cdot10\)
=300+81*10
=300+810
=1110
d: \(175-\left\lbrack3\cdot5^2-5\cdot3^2\right\rbrack\)
\(=175-\left(3\cdot25-5\cdot9\right)\)
=175-(75-45)
=175-30
=145
e: 555:5+\(256:16^2\)
=111+256:256
=111+1
=112
a: \(160-\left(2^3\cdot5^2-6\cdot25\right)\)
\(=160-\left(8\cdot25-150\right)\)
=160-(200-150)
=160-50
=110
\(=2\cdot5\cdot11\)
b: \(4\cdot5^2-32:2^4=4\cdot25-32:16=100-2=98=2\cdot7^2\)
c: \(5871:\left\lbrack928-\left(247-82\cdot5\right)\right\rbrack\)
\(=5871:\left\lbrack928-\left(247-410\right)\right\rbrack\)
=5871:[928-247+410]
=5871:1091
d: \(777:7+1331:11^3=111+1=112=2^4\cdot7\)
e: \(6^2:4\cdot3+2\cdot5^2=36:4\cdot3+2\cdot25\)
=27+50
=77
\(=7\cdot11\)
g: \(5\cdot4^2-18:3^2=5\cdot16-18:9=80-2=78=2\cdot3\cdot13\)
h: \(80-\left(4\cdot5^2-3\cdot2^3\right)=80-\left(4\cdot25-3\cdot8\right)\)
=80-(100-24)
=80-76
=4
=2^2
i: \(23\cdot75+25\cdot23+180\)
\(=23\left(75+25\right)+180\)
=2300+180
=2480
\(=2^4\cdot5\cdot31\)
k: \(2^4\cdot5-\left\lbrack131-\left(13-4\right)^2\right\rbrack\)
\(=16\cdot5-\left\lbrack131-81\right\rbrack\)
=80-50
=30
=2*3*5
m: 100:{250:[450-\(\left(4\cdot5^3-2^2\cdot25\right)\) ]}
=100:{250:[450-\(\left(4\cdot125-4\cdot25\right)\) ]}
=100:{250:[450-500+100]}
=100:{250:50}
=100:5
=20
=2^2*5
\(a,3^6:3^5=3^{6-5}=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right)\cdot\left(7^5:7^4\right)=2^2\cdot7=28\\ d,5^4-2\cdot5^3=5^3\left(5-2\right)=3\cdot5^3=375\)
a) 3^6 : 3^5 = 729 : 243 = 3
b) 5^7 : 5^5 = 78125 : 3125 = 25
c) 14^5 : 2^3 : 7^4 = 537824 : 8 : 2401 = 89
d) 5^4 - 2 * 5^3 = 625 - 2 * 125 = 625 - 250 = 375
\(a,3^6:3^5=3^{6-5}=3^1=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right).\left(7^5:7^4\right)=2^{5-3}.7^{5-4}=2^2.7^1=4.7=28\\ d,5^4-2.5^3=5.5^3-2.5^3=\left(5-2\right).5^3=3.5^3=3.125=375\)
Thế này à:
a, \(\frac{2^{13}+25}{2^{10}}\)
b, \(\frac{21^2.14.125}{35^5.6}\)
c,\(\frac{45^3.20^4.18^2}{180^5}\)
d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33
Bài 1 :
\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)
\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)
\(\Rightarrow M< N\)
Bài 3 :
a) \(t^2+5t-8\) khi \(t=2\)
\(=5^2+2.5-8\)
\(=25+10-8\)
\(=27\)
b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)
\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)
\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)
c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)
\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)
\(\left(1\right)=1^3=1\)
A = 42.6.3
A = (22)2. 2.3.3
A = 24.2.32
A = 25.32
a)5*2^2-18:3=20-6=14
b)17*85+15*17-120=17*(120-85+15)=17*20=340
c2^3*17-2^3*14=2^3(17-14)=8*3=24