\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}=-\frac{16}{5}.-\frac{15}{64}+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)

\(=-\frac{3}{4}+\left(-\frac{22}{15}\right).\frac{2}{7}\)

\(=-\frac{3}{4}-\frac{44}{105}\)

\(=\frac{-315-176}{420}\)

\(=-\frac{491}{420}\)

\(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)

\(=\frac{3}{4}+\frac{-22}{15}:\frac{7}{2}\)

\(=\frac{3}{4}+\frac{-44}{105}\)

\(=\frac{-315}{176}\)

=))

a) \(\frac{-5}{8}\cdot\left(\frac{4}{9}+\frac{-7}{12}\right)\)

\(=\frac{-5}{8}\cdot\frac{-5}{36}\)

\(=\frac{25}{288}\)

b) \(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{5}\right):3\frac{1}{2}\)

\(=\frac{3}{4}+\left(-2\right):\frac{7}{2}\)

\(=\frac{3}{4}+\frac{-4}{7}\)

\(=\frac{5}{28}\)

=))

a: \(=\dfrac{-8-38}{5}=\dfrac{-46}{5}\)

b: \(=\dfrac{-5}{7}\left(\dfrac{25}{1}-24-\dfrac{4}{7}\right)+\dfrac{46}{3}\cdot\dfrac{-1}{23}\)

\(=\dfrac{-5}{7}\cdot\dfrac{3}{7}+\dfrac{-2}{3}\)

=-15/49-2/3=-143/147

\(A=\dfrac{9-18+14}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{5}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\)

\(B=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right)\cdot\dfrac{5}{7}\)

\(=\dfrac{7}{5}-\dfrac{11+5}{20}\cdot\dfrac{5}{7}\)

\(=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49-20}{35}=\dfrac{29}{35}\)

tick di to lam cho

a, \(\left(\dfrac{3}{8}+\dfrac{-3}{4}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\)

\(=\left(\dfrac{-3}{8}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\)

\(=\dfrac{5}{24}.\dfrac{5}{6}+\dfrac{1}{2}\)

\(=\dfrac{25}{144}+\dfrac{1}{2}\)

\(=\dfrac{97}{144}\)

b, \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{5}\)

\(=\dfrac{28}{15}.0,75-\dfrac{4}{5}:\dfrac{7}{5}\)

\(=\dfrac{7}{5}-\dfrac{4}{7}\)

\(=\dfrac{29}{35}\)

a)\(0,2:1\frac{3}{5}+80\%=\frac{1}{8}+80\%=\frac{3205}{32}\)

b)\(0,5:\frac{5}{4}-2\frac{1}{5}=\frac{2}{5}-\frac{11}{5}=-\frac{9}{5}\)

\(0,2:1\frac{3}{5}+80\%=\left(\frac{2}{10}+\frac{8}{5}\right)+80\%=\left(\frac{20}{100}+\frac{160}{100}\right)+80\%=\frac{180}{100}+80\%=180\%+80\%=260\%\)

a ) 

\(\frac{2}{7}+\frac{7}{7}.\frac{14}{25}\)

\(=\frac{2}{7}+1.\frac{14}{25}=\frac{2}{7}+\frac{14}{25}\)

\(=\frac{50}{175}+\frac{98}{175}=\frac{148}{175}\)

b)

\(\frac{6}{7}+\frac{5}{7}:5-\frac{8}{9}\)

\(=\frac{6}{7}+\frac{5}{30}-\frac{8}{9}\)

\(=\frac{6}{7}+\frac{1}{6}-\frac{8}{9}\)

\(=\frac{36}{42}+\frac{7}{42}-\frac{8}{9}\)

\(=\frac{43}{42}-\frac{8}{9}=\frac{129}{126}-\frac{112}{126}=\frac{17}{126}\)

tk ủng hộ mk nha!!!!!!!!

\(=\frac{3}{200}:\frac{3}{5}+\frac{3}{2}\left(\frac{4}{25}-\frac{2}{5}\right)-\frac{1}{25}.\left(\frac{7}{4}:\frac{7}{5}-\frac{5}{2}\right)\)

\(=\frac{3.5}{200.3}+\frac{3}{2}\left(\frac{4}{25}-\frac{2.5}{25}\right)-\frac{1}{25}\left(\frac{7.5}{4.7}-\frac{5}{2}\right)\)

\(=\frac{1}{40}+\frac{3}{2}\left(\frac{-6}{25}\right)-\frac{1}{25}\left(\frac{5}{4}-\frac{10}{4}\right)\)

\(=\frac{1}{40}-\frac{9}{25}+\frac{1}{20}\)

\(=\frac{1.5}{40.5}-\frac{9.8}{25.8}+\frac{1.10}{20.10}\)

\(=\frac{5-72+10}{200}=\frac{-57}{200}\)

Thử máy tính lại ròi kq đúng