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\(160-\left(2^3.5^2-6.25\right)\)
\(=160-\left(8.25-6.25\right)\)
\(=160-\left[\left(8-6\right).25\right]\)
\(=160-\left[2.25\right]\)
\(=160-50\)
\(=110\)
~ Hok tốt ~
\(A=\left(2^5\cdot2^7\right):2^{10}+5\cdot3^4-6^3:6\\ =2^{12}:2^{10}+5\cdot3^4-6^2\\ =2^2+5\cdot3^4-36\\ =4+405-36\\ =373\\ B=\left(5^2-3\right):11\\ =\left(25-3\right):11\\ =22:11\\ =2\\ C=\left(5^{2022}-5^{2021}\right):5^{2021}\\ =5^{2021}\cdot\left(5-1\right):5^{2021}\\ =4\\ D=\left(7^{20}-7^{19}\right):7^{19}\\ =7^{19}\cdot\left(7-1\right):7^{19}\\ =6\)
Ta có: \(\frac{3^7\cdot2^5+3^8}{3^6\cdot5^2-3^6\cdot18}+\frac{2^5\cdot43+2^5}{2^5\cdot5^2-2^5\cdot3}\)
\(=\frac{3^7\left(2^5+3\right)}{3^6\left(5^2-18\right)}+\frac{2^5\left(43+1\right)}{2^5\left(25-3\right)}=\frac{3\cdot\left(32+3\right)}{25-18}+\frac{44}{22}\)
\(=\frac{3\cdot35}{7}+2=3\cdot5+2=15+2=17\)
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
c: Sửa đề: \(\left(5\cdot3^5+17\cdot3^4\right):6^2\)
\(=\frac{5\cdot3^5+17\cdot3^4}{6^2}\)
\(=\frac{3^4\left(5\cdot3+17\right)}{3^2\cdot2^2}=\frac{3^2\cdot\left(15+17\right)}{2^2}=3^2\cdot\frac{32}{2^2}=9\cdot8=72\)
b: Sửa đề: \(5^3\cdot2+\left(2^3\cdot4^0\right):2^3\)
\(=125\cdot2+8:2^3\)
=250+1
=251