\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)

\(\frac{2^{15}.9^4}{6^{6.}.8^3}\)=\(\frac{2^{15}.3^4.3^4}{2^{6.}.3^6.2^9}\) =\(\frac{2^{15}.3^4.3^4}{2^6.2^9.3^4.3^2}\) =\(\frac{2^{15}.3^4.3^2.3^2}{2^{15}.3^4.3^2}\) =\(3^2\) =9

Có: \(5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}=5\cdot2^{30}\cdot3^{18}-3^{20}\cdot2^{29}\)

\(=3^{18}\cdot2^{29}\cdot\left(5\cdot2-3^2\right)=3^{18}\cdot2^{29}\)

Lại có: \(5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6=5\cdot2^{10}\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}=5\cdot2^{29}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)

\(=2^{19}\cdot3^{18}\cdot\left(5\cdot3-7\right)=2^{19}\cdot3^{18}\cdot2^3=2^{22}\cdot3^{18}\)

Vậy \(\frac{3^{18}\cdot2^{29}}{2^{22}\cdot3^{18}}=2^7=128\)

thanks bạn Ngô Văn Phương nhiều nha!!!!

\(\frac{8^{15}.3^{16}}{4^{22}.9^8}=\frac{\left(2^3\right)^{15}.3^{16}}{\left(2^2\right)^{22}.\left(3^2\right)^8}=\frac{2^{45}.3^{16}}{2^{44}.3^{16}}=2\)

\(\frac{8^{15}.3^{16}}{4^{22}.9^8}=\frac{\left(2^3\right)^{15}.3^{16}}{\left(2^2\right)^{22}.\left(3^2\right)^8}=\frac{2^{45}.3^{16}}{2^{44}.3^{16}}=2\)

4⁵.(-9)⁴.(1/2)³-(-1/2)².6⁹ /2⁹.3⁶+6⁶.40=1024.6561.1/8+1/4.10077696/512.729+46656.40=839808+3587226,75+1866240=6293274,75.

đăng từng câu nhé bạn

chứ kiểu vậy thì ko có ai giải cho bạn đâu

a)(-7 / 5 + 3 / 8 ) : 2009 / 2010 + (-3 / 5+5 / 8) : 2009 / 2010

=[ (-7 / 5 + 3 / 8 ) + (-3 / 5+5 / 8) ] : 2009/2010

=[ -7/5 +3/8 + (-3)/5+5/8 ] : 2009/2010

=[ (-7/5 + (-3)/5) + (3/8 + 5/8) ] :2009/2010

=[-2+1] : 2009/2010

=-1 :2009/2010

=-2009/2010

b)\(\frac{9^8\cdot4^3}{27^4\cdot6^5}=\frac{\left(3^2\right)^8\cdot\left(2^2\right)^3}{\left(3^3\right)^4\cdot\left(2\cdot3\right)^5}=\frac{3^{16}\cdot2^6}{3^{12}\cdot2^5\cdot3^5}=\frac{3^{16}\cdot2^5\cdot2}{3^{16}\cdot3^1\cdot2^5}=\frac{2}{3^1}=\frac{2}{3}\)