Câu 2:

5^300 và 3^453

5^300 = (5^2)^150 = 25^150

3^453 > 3^450 = (3^3)^150 = 27^150

25^150 < 27^150

Vậy 5^300 < 3^453

Câu 3:

333^444 = (333^4)^111

444^333 = (444^3)^111

333^4 = 3^4.111^4 = 81.111^4

444^3 = 4^3.111^3 = 64.111^3 < 81.111^4

444^3< 333^4

(333^4)^111 > (444^3)^111

333^444 > 444^333

Ta có: 333^444= 111^444 x 3^444 
444^333 = 111^333 x 4^333 
Tách: 3^444 = (3^4)^111 =81^111 <=>4^333 = (4^3)^111 = 64^111 
Mà: {111^444 > 111^333 (1) 
{81^111 > 64^111 hay: (3^4)^111 > (4^3)^111 (2) 
Từ (1) và (2) ta có:333^444 > 444^333 

So sánh A và B ta thấy:

 A<B

 Đ/s:..............

**** nha

Câu c:

10^30 và 2^100

10^30 = (10^3)^10 = 1000^10

2^100 = (2^10)^10 = 2024^10 > 1000^10

2^100 > 10^30

333^444 = (333^4)^111

444^333 = (444^3)^111

333^4 = 3^4.111^4 = 81.111^4

444^3 = 4^3.111^3 = 64.111^3 < 81.111^4

444^3< 333^4

(333^4)^111 > (444^3)^111

333^444 > 444^333

Ta có: 333⁴⁴⁴=333^111.4=333⁴mũ 111=12296370321¹¹¹

              444³³³=444^111.3=444³mũ 111=87528384¹¹¹

Mà: 12296370321>87528384 và 111=111.

=>333⁴⁴⁴>444³³³.

Tk phát nhé

333^444 = (333^4)^111

444^333 = (444^3)^111

333^4 = 3^4.111^4 = 81.111^4

444^3 = 4^3.111^3 = 64.111^3 < 81.111^4

444^3< 333^4

(333^4)^111 > (444^3)^111

333^444 > 444^333

Câu d:

333^444 = (333^4)^111

444^333 = (444^3)^111

333^4 = 3^4.111^4 = 81.111^4

444^3 = 4^3.111^3 = 64.111^3 < 81.111^4

444^3< 333^4

(333^4)^111 > (444^3)^111

333^444 > 444^333

Câu e:

13^40 và 12^161

12^161 > 12^160 = (12^4)^40 = 20736^40 > 13^40

Vậy 13^40 < 12^161

\(333^{444}=\left(333\times4\right)^{111}=1332^{111}\)

\(444^{333}=\left(444\times3\right)^{111}=1332^{111}\)

\(1332^{111}=1332^{111}\Rightarrow333^{444}=444^{333}\)

\(333^{444}=\left(333^4\right)^{111}\)

\(444^{333}=\left(444^3\right)^{111}\)

\(\Rightarrow333^4=111^4.3^4=111^3.111.3^4\)

     \(444^3=111^3.4^3\)

\(\Rightarrow111.3^4=111.81>4^3=64\)

\(\Rightarrow333^{444}>444^{333}\)

a, 2^100

b, 333^444

c,2^161

d, 3^453

a) Ta có : \(10^{30}=\left(10^3\right)^{10}=1000^{10}\)

                  \(2^{100}=\left(2^{10}\right)^{10}=1024^{10}\)

mà \(1000< 1024\)

\(\Rightarrow1000^{10}< 1024^{10}\)

\(\Rightarrow10^{30}< 2^{100}\)

b) Ta có : \(333^{444}=\left(111.3\right)^{444}=111^{444}.3^{444}=111^{444}.\left(3^4\right)^{111}=111^{444}.81^{111}\)

                 \(444^{333}=\left(111.4\right)^{333}=111^{333}.4^{333}=111^{333}.\left(4^3\right)^{111}=111^{333}.64^{111}\)

mà \(444>333\Rightarrow111^{444}>111^{333}\)

và \(81>64\Rightarrow81^{111}>64^{111}\)

\(\Rightarrow111^{444}.81^{111}>111^{333}.64^{111}\)

\(\Rightarrow333^{444}>444^{333}\)

c) Ta có : \(2^{161}>2^{160}=\left(2^4\right)^{40}=16^{40}>13^{40}\)

\(\Rightarrow2^{161}>13^{40}\)

d) Ta có : \(3^{453}>3^{450}=\left(3^3\right)^{150}=27^{150}>25^{150}=\left(5^2\right)^{150}=5^{300}\)

\(\Rightarrow3^{453}>5^{300}\)

lại sai đề 

a/ 3^200 và 2^300 chứ 0 phải 3000

chưa có học đến

a. 3⁴⁵⁰ = (3³)¹⁵⁰ = 27¹⁵⁰;

5³⁰⁰ = (5²)¹⁵⁰ = 25¹⁵⁰

Vì 27¹⁵⁰ > 25¹⁵⁰

=> 3⁴⁵⁰ > 5³⁰⁰.

b. 333⁴⁴⁴ = (3.111)⁴⁴⁴ = 3⁴⁴⁴.111⁴⁴⁴ =(3⁴)¹¹¹.111⁴⁴⁴=81¹¹¹.111⁴⁴⁴

444³³³=(4.111)³³³=4³³³.111³³³=(4³)¹¹¹.111³³³=64¹¹¹.111³³³

Vì 81¹¹¹ > 64¹¹¹ và 111⁴⁴⁴ > 111³³³

=> 81¹¹¹.111⁴⁴⁴ > 64¹¹¹.111³³³

=> 333⁴⁴⁴ > 444³³³.

c. 2014.2016

= 2014.(2015+1)

= 2014.2015+2014 (1)

2015²

=2015.2015

=2015.(2014+1)

=2015.2014+2015 (2)

Từ (1) và (2) => 2014.2016 < 2015².

b) 333\(^{444}\)và 444\(^{333}\)

Ta có :333\(^{444}\)(3.111)\(^{4.111}\)=(3\(^4\).111\(^4\))\(^{111}\)=(81.111\(^4\)).111

444\(^{333}\)(4.111)\(^{3.111}\)=4\(^3\).111\(^2\))\(^{111}\)=(64.111\(^3\))\(^{111}\) 

vì 81>64 ; 111\(^4\)>111\(^3\) nêb (81.111\(^4\))\(^{111}\)>(64.113\(^3\))\(^{111}\)

hay 333\(^{444}\)>444\(^{333}\)